Chapter 4, Problem 4.93QP

Interpretation Introduction

Interpretation:

The molar mass of the monoprotic acid should be calculated.

Concept introduction:

Molarity:

The concentration of the solutions is given by the term of molarity and it is given by ratio between numbers of moles of solute present in litter of solution.

$\text{Molarity}\text{=}\frac{\text{No}\text{.mole}}{\text{volume}\text{(L)}}$

Mole:

The mole of the solute is calculated by multiplication of concentration of solution and volume of the solution and it is,

$\text{Mole}\text{=}\text{Concentration}\text{(M)×}\text{volume}\text{(L)}$

Molar mass:

The molar mass of compound is given by the ratio between taken mass of the compound and mole of the compound.

$\text{Molar}\text{mass}\text{=}\frac{\text{Mass of}\text{the}\text{compound (g)}}{\text{Mole}}$