General Chemistry
General Chemistry
7th Edition
ISBN: 9780073402758
Author: Chang, Raymond/ Goldsby
Publisher: McGraw-Hill College
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Chapter 4, Problem 4.104QP
Interpretation Introduction

Interpretation:

The mass percent of NaCl and KCl in given NaCl and KCl mixture should be calculated.

Concept introduction:

Precipitation reaction:

If precipitate is formed, when two soluble salt solutions are mixed together is known as precipitation reaction.

The mass of the precipitate is depends on the reactant masses.

Molarity:

The concentration of the solutions is given by the term of molarity and it is given by ratio between numbers of moles of solute present in litter of solution.

Molarity=No.molevolume(L)

Mole:

The mole of compound is given by the ratio between taken mass of the compound and molar mass of the compound.

Mole=MassofthecompoundMolarmassofthecompound

Mass percentage:

Mass percentage of given compound is calculated by the ration between the mass of the analyte and total mass of the compound.

Masspercent=MassTotalmass

Expert Solution & Answer
Check Mark

Answer to Problem 4.104QP

  • The mass percent of NaCl in given 0.8870g mixture is 44.11%
  • The mass percent of KCl in given 0.8870g mixture is 55.89%

Explanation of Solution

Record the given data,

Mass of NaCl and KCl mixture = 0.8870g

Mass of produced AgCl precipitate = 1.913 g

The given masses are recorded as shown above.

The mole of KCl and NaCl mixture to produce a 1.913 gAgCl precipitate

Molar mass of AgCl is 143.35g

The balance equation is,

XCl(aq)+AgNO3(aq)AgCl(s)+XNO3(aq)WhereX=NaorK

XClmole=1.913gAgCl×1molAgCl143.35g×1molXCl1mol AgCl=0.013345molXCl

  • One mole of XCl is required to react with one mole of AgNO3 to produce a mole of AgCl precipitate.
  • The mass of AgCl and molar mass of AgCl are plugged in the above equation to give the mole of KCl and NaCl mixture to produce a 1.913 gAgCl precipitate
  • The mole of KCl and NaCl mixture to produce a 1.913 gAgCl precipitate is 0.013345molXCl.

The moles of KCl and  NaCl in give 0.8870g mixture

Let consider x=number of moles of NaCl in give mixture, then the number of moles of KCl is

KCl=0.013345mol-x

The sum of KCl and NaCl masses are equal to 0.8870g

Molar mass of KCl is 74.55g

Molar mass of NaCl is 58.44g

0.8870g=[xmolNaCl×58.44gNaCl1moleNaCl]+[(0.013345-x)molKCl×74.55gKCl1molKCl]x=6.6958×10-3molesNaClMoleKCl=0.013345-x=0.013345-6.6958×10-3=6.6492×10-3molKCl

  • The calculated mole of KCl and NaCl mixture and molar masses of KCl and NaCl are plugged in above equation and do some maths to give the mole of KCl and NaCl present in give 0.8870g mixture.
  • The mole of KCl present in give 0.8870g mixture is 6.6492×10-3
  • The mole of NaCl present in give 0.8870g mixture is 6.6958×10-3

The masses of KCl and  NaCl in give 0.8870g mixture

MoleofNaCl=(6.6958×10-3molNaCl)×58.44gNaCl1molNaCl=0.3913gNaClMoleofKCl=(6.6492×10-3molKCl)×74.55gKCl1molKCl=0.4957gKCl

  • The calculated mole of KCl and  NaCl are multiplied with molar masses of KCl and  NaCl to give the masses of KCl and  NaCl in give 0.8870g mixture
  • Mass of KCl in give 0.8870g mixture is 0.4957g
  • Mass of NaCl in give 0.8870g mixture is 0.3913g

The mass percentages of KCl and  NaCl in give 0.8870g mixture

Mass%NaCl=0.3913g0.8870g×100=44.11%Mass%KCl=0.49.57g0.8870g×100=55.89%

  • The calculated masses of KCl and  NaCl are divided by total mass of mixture 0.8870g to give a mass percentages of KCl and  NaCl in given mixture.
  • The mass percent of NaCl in given 0.8870g mixture is 44.11%
  • The mass percent of KCl in given 0.8870g mixture is 55.89%
Conclusion

The mass percent of NaCl and KCl in given NaCl and KCl mixture calculated.

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Chapter 4 Solutions

General Chemistry

Ch. 4.5 - Prob. 1PECh. 4.5 - Prob. 2PECh. 4.5 - Prob. 3PECh. 4.5 - Prob. 1RCCh. 4.6 - Prob. 1PECh. 4.6 - Prob. 1RCCh. 4.6 - Prob. 2PECh. 4.6 - Prob. 3PECh. 4 - Prob. 4.1QPCh. 4 - Prob. 4.2QPCh. 4 - Prob. 4.3QPCh. 4 - 4.4 What is the difference between the following...Ch. 4 - 4.5 Water is an extremely weak electrolyte and...Ch. 4 - Prob. 4.6QPCh. 4 - Prob. 4.7QPCh. 4 - 4.8 Which of the following diagrams best...Ch. 4 - Prob. 4.9QPCh. 4 - Prob. 4.10QPCh. 4 - Prob. 4.11QPCh. 4 - Prob. 4.12QPCh. 4 - Prob. 4.13QPCh. 4 - Prob. 4.14QPCh. 4 - Prob. 4.15QPCh. 4 - Prob. 4.16QPCh. 4 - Prob. 4.17QPCh. 4 - Prob. 4.18QPCh. 4 - Prob. 4.19QPCh. 4 - Prob. 4.20QPCh. 4 - 4.21 Write ionic and net ionic equations for the...Ch. 4 - Prob. 4.22QPCh. 4 - Prob. 4.23QPCh. 4 - Prob. 4.24QPCh. 4 - Prob. 4.25QPCh. 4 - Prob. 4.26QPCh. 4 - Prob. 4.27QPCh. 4 - Prob. 4.28QPCh. 4 - Prob. 4.29QPCh. 4 - Prob. 4.30QPCh. 4 - Prob. 4.31QPCh. 4 - Prob. 4.32QPCh. 4 - Prob. 4.33QPCh. 4 - Prob. 4.34QPCh. 4 - Prob. 4.35QPCh. 4 - Prob. 4.36QPCh. 4 - Prob. 4.37QPCh. 4 - Prob. 4.38QPCh. 4 - 4.39 For the complete redox reactions given here,...Ch. 4 - Prob. 4.40QPCh. 4 - Prob. 4.41QPCh. 4 - Prob. 4.42QPCh. 4 - Prob. 4.43QPCh. 4 - Prob. 4.44QPCh. 4 - Prob. 4.45QPCh. 4 - Prob. 4.46QPCh. 4 - Prob. 4.47QPCh. 4 - Prob. 4.48QPCh. 4 - Prob. 4.49QPCh. 4 - Prob. 4.50QPCh. 4 - Prob. 4.51QPCh. 4 - Prob. 4.52QPCh. 4 - Prob. 4.53QPCh. 4 - Prob. 4.54QPCh. 4 - Prob. 4.55QPCh. 4 - Prob. 4.56QPCh. 4 - Prob. 4.57QPCh. 4 - Prob. 4.58QPCh. 4 - Prob. 4.59QPCh. 4 - Prob. 4.60QPCh. 4 - Prob. 4.61QPCh. 4 - Prob. 4.62QPCh. 4 - Prob. 4.63QPCh. 4 - Prob. 4.64QPCh. 4 - Prob. 4.65QPCh. 4 - Prob. 4.66QPCh. 4 - Prob. 4.67QPCh. 4 - Prob. 4.68QPCh. 4 - Prob. 4.69QPCh. 4 - 4.70 Distilled water must be used in the...Ch. 4 - 4.71 If 30.0 mL of 0.150 M CaCl2 is added to 15.0...Ch. 4 - Prob. 4.72QPCh. 4 - Prob. 4.73QPCh. 4 - Prob. 4.74QPCh. 4 - Prob. 4.75QPCh. 4 - Prob. 4.76QPCh. 4 - Prob. 4.77QPCh. 4 - Prob. 4.78QPCh. 4 - Prob. 4.79QPCh. 4 - Prob. 4.80QPCh. 4 - Prob. 4.81QPCh. 4 - Prob. 4.82QPCh. 4 - Prob. 4.83QPCh. 4 - Prob. 4.84QPCh. 4 - Prob. 4.85QPCh. 4 - Prob. 4.86QPCh. 4 - Prob. 4.87QPCh. 4 - Prob. 4.88QPCh. 4 - Prob. 4.89QPCh. 4 - Prob. 4.90QPCh. 4 - Prob. 4.91QPCh. 4 - Prob. 4.92QPCh. 4 - Prob. 4.93QPCh. 4 - 4.74 The molecular formula of malonic acid is...Ch. 4 - Prob. 4.95QPCh. 4 - Prob. 4.96QPCh. 4 - Prob. 4.97QPCh. 4 - Prob. 4.98QPCh. 4 - Prob. 4.99QPCh. 4 - Prob. 4.100QPCh. 4 - Prob. 4.101QPCh. 4 - Prob. 4.102QPCh. 4 - 4.103 These are common household compounds: table...Ch. 4 - Prob. 4.104QPCh. 4 - Prob. 4.105QPCh. 4 - Prob. 4.106QPCh. 4 - 4.107 A number of metals are involved in redox...Ch. 4 - Prob. 4.108QPCh. 4 - Prob. 4.109QPCh. 4 - Prob. 4.110QPCh. 4 - Prob. 4.111QPCh. 4 - Prob. 4.112QPCh. 4 - Prob. 4.114SPCh. 4 - Prob. 4.115SPCh. 4 - Prob. 4.116SPCh. 4 - Prob. 4.117SPCh. 4 - Prob. 4.118SP
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