Chapter 4, Problem 4.16P

(a)

Interpretation Introduction

Interpretation:

To find the final temperature, T, when heat is added to the subcooled liquid methanol.

Concept Introduction:

$MCPH=\frac{{(C_p)}_H}{R}=A+\frac{B}{2}{T}_0(\tau +1)+\frac{C}{3}{T}_0^2\left({\tau }^2+\tau +1\right)+\frac{D}{\tau T_0^2}$

$(T-T_0)=\frac{\Delta H}{{(C_p)}_H}$

where,

T = Final Temperature

T_o = Initial temperature = 25 ^oC = 298 K

$\Delta H$ = Heat added = 60 kJ/mol = 60000 J/mol

A, B, C, D are constants

also, $\tau =\frac{T}{T_O}$

(b)

Interpretation Introduction

Interpretation:

To find the final temperature, T, when heat is added to the subcooled liquid ethanol

Concept Introduction:

$MCPH=\frac{{(C_p)}_H}{R}=A+\frac{B}{2}{T}_0(\tau +1)+\frac{C}{3}{T}_0^2\left({\tau }^2+\tau +1\right)+\frac{D}{\tau T_0^2}$

$(T-T_0)=\frac{\Delta H}{{(C_p)}_H}$

where,

T = Final Temperature

T_o = Initial temperature = 25 ^oC = 298 K

$\Delta H$ = Heat added = 60 kJ/mol = 60000 J/mol

also, $\tau =\frac{T}{T_O}$

(c)

Interpretation Introduction

Interpretation:

To find the final temperature, T, when heat is added to the subcooled liquid Benzene

Concept Introduction:

$MCPH=\frac{{(C_p)}_H}{R}=A+\frac{B}{2}{T}_0(\tau +1)+\frac{C}{3}{T}_0^2\left({\tau }^2+\tau +1\right)+\frac{D}{\tau T_0^2}$

$(T-T_0)=\frac{\Delta H}{{(C_p)}_H}$

where,

T = Final Temperature

T_o = Initial temperature = 25 ^oC = 298 K

$\Delta H$ = Heat added = 60 kJ/mol = 60000 J/mol

also, $\tau =\frac{T}{T_O}$

(d)

Interpretation Introduction

Interpretation:

To find the final temperature, T, when heat is added to the subcooled liquid Toluene

Concept Introduction:

$MCPH=\frac{{(C_p)}_H}{R}=A+\frac{B}{2}{T}_0(\tau +1)+\frac{C}{3}{T}_0^2\left({\tau }^2+\tau +1\right)+\frac{D}{\tau T_0^2}$

$(T-T_0)=\frac{\Delta H}{{(C_p)}_H}$

where,

T = Final Temperature

T_o = Initial temperature = 25 ^oC = 298 K

$\Delta H$ = Heat added = 60 kJ/mol = 60000 J/mol

also, $\tau =\frac{T}{T_O}$

(e)

Interpretation Introduction

Interpretation:

To find the final temperature, T, when heat is added to the subcooled liquid Water

Concept Introduction:

$MCPH=\frac{{(C_p)}_H}{R}=A+\frac{B}{2}{T}_0(\tau +1)+\frac{C}{3}{T}_0^2\left({\tau }^2+\tau +1\right)+\frac{D}{\tau T_0^2}$

$(T-T_0)=\frac{\Delta H}{{(C_p)}_H}$

where,

T = Final Temperature

T_o = Initial temperature = 25 ^oC = 298 K

$\Delta H$ = Heat added = 60 kJ/mol = 60000 J/mol

also, $\tau =\frac{T}{T_O}$