Assuming that P = 48000 lb and that it may be applied at any joint on the line FJ , determine the location of P that would cause (a) maximum tension in member HI ; (b) maximum compression in member CI ; and (c) maximum tension in member CI . Also determine the magnitude of the indicated force in each case.

Question

Want to see more full solutions like this?

Answer 1

Textbook Question

Chapter 4, Problem 4.155P

Assuming that $P = 48000 lb$ and that it may be applied at any joint on the line FJ, determine the location of P that would cause (a) maximum tension in member HI; (b) maximum compression in member CI; and (c) maximum tension in member CI. Also determine the magnitude of the indicated force in each case.

Chapter 4, Problem 4.155P, Assuming that P=48000lb and that it may be applied at any joint on the line FJ, determine the

Expert Solution

To determine

(a)

Location of force 'P' that would cause maximum tension in member HI.

Answer to Problem 4.155P

The maximum tension occurs at HI, when force 'P' acts at H.

The magnitude of maximum tension $PHI$ is $48000 lb$ .

Explanation of Solution

Given information:

International Edition---engineering Mechanics: Statics, 4th Edition, Chapter 4, Problem 4.155P , additional homework tip 1

Assume $P=48000 lb$ .

Steps to follow in the equilibrium analysis of a body are:

1. Draw the free body diagram.

2. Write the equilibrium equations.

3. Solve the equations for the unknowns.

Calculation:

Assume $Ey$ as the vertical reaction at point E.

Consider entire body

Force 'P' at point J

$↑Ey=P$

Force 'P' at point I

$↑Ey=0.75P$

Force 'P' at point H

$↑Ey=0.5P$

Force 'P' at point G

$↑Ey=0.25P$

Force 'P' at point F

$↑Ey=0$

FBD of below section

International Edition---engineering Mechanics: Statics, 4th Edition, Chapter 4, Problem 4.155P , additional homework tip 2

Assume $PCD,PCI,PHI$ as the forces acting on member CD, CI and HI respectively.

If force 'P' acts at point J

Write equilibrium equation in vertical direction.

$↑∑Fy=0$

$PCI=0$

For the equilibrium of above section, the bending moment about point C is equal to zero.

$∑MC=0$

$PHI=0$

If force 'P' acts at point I

$Ey−P+(12)PCI=0$

Solve

$PCI=2(P−Ey) =2(P−0.75P) =0.353P$

For the equilibrium of above section, the bending moment about point C is equal to zero.

$∑MC=0$

$Ey(2a)−P(a)−PHI(a)=0$

Solve

$PHI=2(0.75P)−P =0.5P$

If force 'P' acts at points G, H and F,

Write equilibrium equation in vertical direction.

$↑∑Fy=0$

$Ey+(1 2 )PCI=0 PCI=−2Ey$

For the equilibrium of above section, the bending moment about point C is equal to zero.

$∑MC=0$

$Ey(2a)−PHI(a)=0 PHI=2Ey$

The maximum tension occurs at HI, when force 'P' acts at H.

$PHI=2Ey =2(0.5P) =P =48000 lb$

Conclusion:

The maximum tension occurs at HI, when force 'P' acts at H.

The magnitude of maximum tension $PHI$ is $48000 lb$ .

Expert Solution

To determine

(b)

Location of force 'P' that would cause maximum compression in member CI.

Answer to Problem 4.155P

The maximum compression occurs at CI, when force 'P' acts at H.

The magnitude of maximum compression $PCI$ is $33941.12 lb$ .

Explanation of Solution

Given information:

International Edition---engineering Mechanics: Statics, 4th Edition, Chapter 4, Problem 4.155P , additional homework tip 3

Assume $P=48000 lb$ .

Steps to follow in the equilibrium analysis of a body are:

1. Draw the free body diagram.

2. Write the equilibrium equations.

3. Solve the equations for the unknowns.

Calculation:

According to sub part a

Force 'P' at point H

$↑Ey=0.5P$

The force $PCI$ in member CI

$PCI=−2Ey$

The maximum compression occurs at CI, when force 'P' acts at H.

$PCI=2Ey =2(0.5P) =0.7071P =33941.12 lb$

Conclusion:

The maximum compression occurs at CI, when force 'P' acts at H.

The magnitude of maximum compression $PCI$ is $33941.12 lb$ .

Expert Solution

To determine

(c)

Location of force 'P' that would cause maximum tension in member CI

Answer to Problem 4.155P

The maximum compression occurs at CI, when force 'P' acts at I.

The magnitude of maximum tension $PCI$ is $16944 lb$ .

Explanation of Solution

Given information:

International Edition---engineering Mechanics: Statics, 4th Edition, Chapter 4, Problem 4.155P , additional homework tip 4

Assume $P=48000 lb$ .

Steps to follow in the equilibrium analysis of a body are:

1. Draw the free body diagram.

2. Write the equilibrium equations.

3. Solve the equations for the unknowns.

Calculation:

According to sub part a

If force 'P' acts at point I

$Ey−P+(12)PCI=0$

Solve

$PCI=2(P−Ey) =2(P−0.75P) =0.353P =16944 lb$

The maximum tension occurs at member CI when force 'P' acts at point I.

Conclusion:

The maximum compression occurs at CI, when force 'P' acts at I.

The magnitude of maximum tension $PCI$ is $16944 lb$ .

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Students have asked these similar questions

This is a tilt and rotation question. Here are notes attached for reference. I prefer handwritten solutions. ONLY UPLOAD A SOLUTION IF YOU ARE SURE ABOUT THE ANSWER PLEASE. I prefer handwritten solutions.(If you had once answered this question don't answer it as I am looking for a different solution)

One end of a thin uniform rod of mass m and length 31 rests against a smooth vertical wall. The other end of the rod is attached by a string of length I to a fixed point which is located a distance 21 from the wall. A horizontal force of magnitude F, is applied to the lower end of the rod as shown. Assuming the rod and the string remain in the same vertical plane perpendicular to the wall, find the angle 9 between the rod and the wall at the position of static equilibrium. Notes: This quiz is going to walk you through a sequence of steps to do this. It won't give you the answers, but it will hopefully get you to see how to approach problems like this so that you have a working reference/template in the future. This is actually a modified version of a problem from the textbook (6.3). Note that in that problem, is not actually given. It has been introduced for convenience as we move through solving the problem, and should not show up in the final answer. DO NOT DO PROBLEM 6.3. It is not…

This is a tilt and rotation question. Here are notes attached for reference. I prefer handwritten solutions. ONLY UPLOAD A SOLUTION IF YOU ARE SURE ABOUT THE ANSWER PLEASE. I prefer handwritten solutions.(If you had once answered this question don't answer it as I am looking for a different solution)

Answer 2

Textbook Question

Chapter 4, Problem 4.155P

Assuming that $P = 48000 lb$ and that it may be applied at any joint on the line FJ, determine the location of P that would cause (a) maximum tension in member HI; (b) maximum compression in member CI; and (c) maximum tension in member CI. Also determine the magnitude of the indicated force in each case.

Chapter 4, Problem 4.155P, Assuming that P=48000lb and that it may be applied at any joint on the line FJ, determine the

Expert Solution

To determine

(a)

Location of force 'P' that would cause maximum tension in member HI.

Answer to Problem 4.155P

The maximum tension occurs at HI, when force 'P' acts at H.

The magnitude of maximum tension $PHI$ is $48000 lb$ .

Explanation of Solution

Given information:

International Edition---engineering Mechanics: Statics, 4th Edition, Chapter 4, Problem 4.155P , additional homework tip 1

Assume $P=48000 lb$ .

Steps to follow in the equilibrium analysis of a body are:

1. Draw the free body diagram.

2. Write the equilibrium equations.

3. Solve the equations for the unknowns.

Calculation:

Assume $Ey$ as the vertical reaction at point E.

Consider entire body

Force 'P' at point J

$↑Ey=P$

Force 'P' at point I

$↑Ey=0.75P$

Force 'P' at point H

$↑Ey=0.5P$

Force 'P' at point G

$↑Ey=0.25P$

Force 'P' at point F

$↑Ey=0$

FBD of below section

International Edition---engineering Mechanics: Statics, 4th Edition, Chapter 4, Problem 4.155P , additional homework tip 2

Assume $PCD,PCI,PHI$ as the forces acting on member CD, CI and HI respectively.

If force 'P' acts at point J

Write equilibrium equation in vertical direction.

$↑∑Fy=0$

$PCI=0$

For the equilibrium of above section, the bending moment about point C is equal to zero.

$∑MC=0$

$PHI=0$

If force 'P' acts at point I

$Ey−P+(12)PCI=0$

Solve

$PCI=2(P−Ey) =2(P−0.75P) =0.353P$

For the equilibrium of above section, the bending moment about point C is equal to zero.

$∑MC=0$

$Ey(2a)−P(a)−PHI(a)=0$

Solve

$PHI=2(0.75P)−P =0.5P$

If force 'P' acts at points G, H and F,

Write equilibrium equation in vertical direction.

$↑∑Fy=0$

$Ey+(1 2 )PCI=0 PCI=−2Ey$

For the equilibrium of above section, the bending moment about point C is equal to zero.

$∑MC=0$

$Ey(2a)−PHI(a)=0 PHI=2Ey$

The maximum tension occurs at HI, when force 'P' acts at H.

$PHI=2Ey =2(0.5P) =P =48000 lb$

Conclusion:

The maximum tension occurs at HI, when force 'P' acts at H.

The magnitude of maximum tension $PHI$ is $48000 lb$ .

Expert Solution

To determine

(b)

Location of force 'P' that would cause maximum compression in member CI.

Answer to Problem 4.155P

The maximum compression occurs at CI, when force 'P' acts at H.

The magnitude of maximum compression $PCI$ is $33941.12 lb$ .

Explanation of Solution

Given information:

International Edition---engineering Mechanics: Statics, 4th Edition, Chapter 4, Problem 4.155P , additional homework tip 3

Assume $P=48000 lb$ .

Steps to follow in the equilibrium analysis of a body are:

1. Draw the free body diagram.

2. Write the equilibrium equations.

3. Solve the equations for the unknowns.

Calculation:

According to sub part a

Force 'P' at point H

$↑Ey=0.5P$

The force $PCI$ in member CI

$PCI=−2Ey$

The maximum compression occurs at CI, when force 'P' acts at H.

$PCI=2Ey =2(0.5P) =0.7071P =33941.12 lb$

Conclusion:

The maximum compression occurs at CI, when force 'P' acts at H.

The magnitude of maximum compression $PCI$ is $33941.12 lb$ .

Expert Solution

To determine

(c)

Location of force 'P' that would cause maximum tension in member CI

Answer to Problem 4.155P

The maximum compression occurs at CI, when force 'P' acts at I.

The magnitude of maximum tension $PCI$ is $16944 lb$ .

Explanation of Solution

Given information:

International Edition---engineering Mechanics: Statics, 4th Edition, Chapter 4, Problem 4.155P , additional homework tip 4

Assume $P=48000 lb$ .

Steps to follow in the equilibrium analysis of a body are:

1. Draw the free body diagram.

2. Write the equilibrium equations.

3. Solve the equations for the unknowns.

Calculation:

According to sub part a

If force 'P' acts at point I

$Ey−P+(12)PCI=0$

Solve

$PCI=2(P−Ey) =2(P−0.75P) =0.353P =16944 lb$

The maximum tension occurs at member CI when force 'P' acts at point I.

Conclusion:

The maximum compression occurs at CI, when force 'P' acts at I.

The magnitude of maximum tension $PCI$ is $16944 lb$ .

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Textbook Question

Chapter 4, Problem 4.155P

Assuming that $P = 48000 lb$ and that it may be applied at any joint on the line FJ, determine the location of P that would cause (a) maximum tension in member HI; (b) maximum compression in member CI; and (c) maximum tension in member CI. Also determine the magnitude of the indicated force in each case.

Chapter 4, Problem 4.155P, Assuming that P=48000lb and that it may be applied at any joint on the line FJ, determine the

Expert Solution

To determine

(a)

Location of force 'P' that would cause maximum tension in member HI.

Answer to Problem 4.155P

The maximum tension occurs at HI, when force 'P' acts at H.

The magnitude of maximum tension $PHI$ is $48000 lb$ .

Explanation of Solution

Given information:

International Edition---engineering Mechanics: Statics, 4th Edition, Chapter 4, Problem 4.155P , additional homework tip 1

Assume $P=48000 lb$ .

Steps to follow in the equilibrium analysis of a body are:

1. Draw the free body diagram.

2. Write the equilibrium equations.

3. Solve the equations for the unknowns.

Calculation:

Assume $Ey$ as the vertical reaction at point E.

Consider entire body

Force 'P' at point J

$↑Ey=P$

Force 'P' at point I

$↑Ey=0.75P$

Force 'P' at point H

$↑Ey=0.5P$

Force 'P' at point G

$↑Ey=0.25P$

Force 'P' at point F

$↑Ey=0$

FBD of below section

International Edition---engineering Mechanics: Statics, 4th Edition, Chapter 4, Problem 4.155P , additional homework tip 2

Assume $PCD,PCI,PHI$ as the forces acting on member CD, CI and HI respectively.

If force 'P' acts at point J

Write equilibrium equation in vertical direction.

$↑∑Fy=0$

$PCI=0$

For the equilibrium of above section, the bending moment about point C is equal to zero.

$∑MC=0$

$PHI=0$

If force 'P' acts at point I

$Ey−P+(12)PCI=0$

Solve

$PCI=2(P−Ey) =2(P−0.75P) =0.353P$

For the equilibrium of above section, the bending moment about point C is equal to zero.

$∑MC=0$

$Ey(2a)−P(a)−PHI(a)=0$

Solve

$PHI=2(0.75P)−P =0.5P$

If force 'P' acts at points G, H and F,

Write equilibrium equation in vertical direction.

$↑∑Fy=0$

$Ey+(1 2 )PCI=0 PCI=−2Ey$

For the equilibrium of above section, the bending moment about point C is equal to zero.

$∑MC=0$

$Ey(2a)−PHI(a)=0 PHI=2Ey$

The maximum tension occurs at HI, when force 'P' acts at H.

$PHI=2Ey =2(0.5P) =P =48000 lb$

Conclusion:

The maximum tension occurs at HI, when force 'P' acts at H.

The magnitude of maximum tension $PHI$ is $48000 lb$ .

Expert Solution

To determine

(b)

Location of force 'P' that would cause maximum compression in member CI.

Answer to Problem 4.155P

The maximum compression occurs at CI, when force 'P' acts at H.

The magnitude of maximum compression $PCI$ is $33941.12 lb$ .

Explanation of Solution

Given information:

International Edition---engineering Mechanics: Statics, 4th Edition, Chapter 4, Problem 4.155P , additional homework tip 3

Assume $P=48000 lb$ .

Steps to follow in the equilibrium analysis of a body are:

1. Draw the free body diagram.

2. Write the equilibrium equations.

3. Solve the equations for the unknowns.

Calculation:

According to sub part a

Force 'P' at point H

$↑Ey=0.5P$

The force $PCI$ in member CI

$PCI=−2Ey$

The maximum compression occurs at CI, when force 'P' acts at H.

$PCI=2Ey =2(0.5P) =0.7071P =33941.12 lb$

Conclusion:

The maximum compression occurs at CI, when force 'P' acts at H.

The magnitude of maximum compression $PCI$ is $33941.12 lb$ .

Expert Solution

To determine

(c)

Location of force 'P' that would cause maximum tension in member CI

Answer to Problem 4.155P

The maximum compression occurs at CI, when force 'P' acts at I.

The magnitude of maximum tension $PCI$ is $16944 lb$ .

Explanation of Solution

Given information:

International Edition---engineering Mechanics: Statics, 4th Edition, Chapter 4, Problem 4.155P , additional homework tip 4

Assume $P=48000 lb$ .

Steps to follow in the equilibrium analysis of a body are:

1. Draw the free body diagram.

2. Write the equilibrium equations.

3. Solve the equations for the unknowns.

Calculation:

According to sub part a

If force 'P' acts at point I

$Ey−P+(12)PCI=0$

Solve

$PCI=2(P−Ey) =2(P−0.75P) =0.353P =16944 lb$

The maximum tension occurs at member CI when force 'P' acts at point I.

Conclusion:

The maximum compression occurs at CI, when force 'P' acts at I.

The magnitude of maximum tension $PCI$ is $16944 lb$ .

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Textbook Question

Chapter 4, Problem 4.155P

Assuming that $P = 48000 lb$ and that it may be applied at any joint on the line FJ, determine the location of P that would cause (a) maximum tension in member HI; (b) maximum compression in member CI; and (c) maximum tension in member CI. Also determine the magnitude of the indicated force in each case.

Chapter 4, Problem 4.155P, Assuming that P=48000lb and that it may be applied at any joint on the line FJ, determine the

Expert Solution

To determine

(a)

Location of force 'P' that would cause maximum tension in member HI.

Answer to Problem 4.155P

The maximum tension occurs at HI, when force 'P' acts at H.

The magnitude of maximum tension $PHI$ is $48000 lb$ .

Explanation of Solution

Given information:

International Edition---engineering Mechanics: Statics, 4th Edition, Chapter 4, Problem 4.155P , additional homework tip 1

Assume $P=48000 lb$ .

Steps to follow in the equilibrium analysis of a body are:

1. Draw the free body diagram.

2. Write the equilibrium equations.

3. Solve the equations for the unknowns.

Calculation:

Assume $Ey$ as the vertical reaction at point E.

Consider entire body

Force 'P' at point J

$↑Ey=P$

Force 'P' at point I

$↑Ey=0.75P$

Force 'P' at point H

$↑Ey=0.5P$

Force 'P' at point G

$↑Ey=0.25P$

Force 'P' at point F

$↑Ey=0$

FBD of below section

International Edition---engineering Mechanics: Statics, 4th Edition, Chapter 4, Problem 4.155P , additional homework tip 2

Assume $PCD,PCI,PHI$ as the forces acting on member CD, CI and HI respectively.

If force 'P' acts at point J

Write equilibrium equation in vertical direction.

$↑∑Fy=0$

$PCI=0$

For the equilibrium of above section, the bending moment about point C is equal to zero.

$∑MC=0$

$PHI=0$

If force 'P' acts at point I

$Ey−P+(12)PCI=0$

Solve

$PCI=2(P−Ey) =2(P−0.75P) =0.353P$

For the equilibrium of above section, the bending moment about point C is equal to zero.

$∑MC=0$

$Ey(2a)−P(a)−PHI(a)=0$

Solve

$PHI=2(0.75P)−P =0.5P$

If force 'P' acts at points G, H and F,

Write equilibrium equation in vertical direction.

$↑∑Fy=0$

$Ey+(1 2 )PCI=0 PCI=−2Ey$

For the equilibrium of above section, the bending moment about point C is equal to zero.

$∑MC=0$

$Ey(2a)−PHI(a)=0 PHI=2Ey$

The maximum tension occurs at HI, when force 'P' acts at H.

$PHI=2Ey =2(0.5P) =P =48000 lb$

Conclusion:

The maximum tension occurs at HI, when force 'P' acts at H.

The magnitude of maximum tension $PHI$ is $48000 lb$ .

Expert Solution

To determine

(b)

Location of force 'P' that would cause maximum compression in member CI.

Answer to Problem 4.155P

The maximum compression occurs at CI, when force 'P' acts at H.

The magnitude of maximum compression $PCI$ is $33941.12 lb$ .

Explanation of Solution

Given information:

International Edition---engineering Mechanics: Statics, 4th Edition, Chapter 4, Problem 4.155P , additional homework tip 3

Assume $P=48000 lb$ .

Steps to follow in the equilibrium analysis of a body are:

1. Draw the free body diagram.

2. Write the equilibrium equations.

3. Solve the equations for the unknowns.

Calculation:

According to sub part a

Force 'P' at point H

$↑Ey=0.5P$

The force $PCI$ in member CI

$PCI=−2Ey$

The maximum compression occurs at CI, when force 'P' acts at H.

$PCI=2Ey =2(0.5P) =0.7071P =33941.12 lb$

Conclusion:

The maximum compression occurs at CI, when force 'P' acts at H.

The magnitude of maximum compression $PCI$ is $33941.12 lb$ .

Expert Solution

To determine

(c)

Location of force 'P' that would cause maximum tension in member CI

Answer to Problem 4.155P

The maximum compression occurs at CI, when force 'P' acts at I.

The magnitude of maximum tension $PCI$ is $16944 lb$ .

Explanation of Solution

Given information:

International Edition---engineering Mechanics: Statics, 4th Edition, Chapter 4, Problem 4.155P , additional homework tip 4

Assume $P=48000 lb$ .

Steps to follow in the equilibrium analysis of a body are:

1. Draw the free body diagram.

2. Write the equilibrium equations.

3. Solve the equations for the unknowns.

Calculation:

According to sub part a

If force 'P' acts at point I

$Ey−P+(12)PCI=0$

Solve

$PCI=2(P−Ey) =2(P−0.75P) =0.353P =16944 lb$

The maximum tension occurs at member CI when force 'P' acts at point I.

Conclusion:

The maximum compression occurs at CI, when force 'P' acts at I.

The magnitude of maximum tension $PCI$ is $16944 lb$ .

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

Expert Solution

To determine

(a)

Location of force 'P' that would cause maximum tension in member HI.

Answer to Problem 4.155P

The maximum tension occurs at HI, when force 'P' acts at H.

The magnitude of maximum tension $PHI$ is $48000 lb$ .

Explanation of Solution

Given information:

International Edition---engineering Mechanics: Statics, 4th Edition, Chapter 4, Problem 4.155P , additional homework tip 1

Assume $P=48000 lb$ .

Steps to follow in the equilibrium analysis of a body are:

1. Draw the free body diagram.

2. Write the equilibrium equations.

3. Solve the equations for the unknowns.

Calculation:

Assume $Ey$ as the vertical reaction at point E.

Consider entire body

Force 'P' at point J

$↑Ey=P$

Force 'P' at point I

$↑Ey=0.75P$

Force 'P' at point H

$↑Ey=0.5P$

Force 'P' at point G

$↑Ey=0.25P$

Force 'P' at point F

$↑Ey=0$

FBD of below section

International Edition---engineering Mechanics: Statics, 4th Edition, Chapter 4, Problem 4.155P , additional homework tip 2

Assume $PCD,PCI,PHI$ as the forces acting on member CD, CI and HI respectively.

If force 'P' acts at point J

Write equilibrium equation in vertical direction.

$↑∑Fy=0$

$PCI=0$

For the equilibrium of above section, the bending moment about point C is equal to zero.

$∑MC=0$

$PHI=0$

If force 'P' acts at point I

$Ey−P+(12)PCI=0$

Solve

$PCI=2(P−Ey) =2(P−0.75P) =0.353P$

For the equilibrium of above section, the bending moment about point C is equal to zero.

$∑MC=0$

$Ey(2a)−P(a)−PHI(a)=0$

Solve

$PHI=2(0.75P)−P =0.5P$

If force 'P' acts at points G, H and F,

Write equilibrium equation in vertical direction.

$↑∑Fy=0$

$Ey+(1 2 )PCI=0 PCI=−2Ey$

For the equilibrium of above section, the bending moment about point C is equal to zero.

$∑MC=0$

$Ey(2a)−PHI(a)=0 PHI=2Ey$

The maximum tension occurs at HI, when force 'P' acts at H.

$PHI=2Ey =2(0.5P) =P =48000 lb$

Conclusion:

The maximum tension occurs at HI, when force 'P' acts at H.

The magnitude of maximum tension $PHI$ is $48000 lb$ .

Expert Solution

To determine

(b)

Location of force 'P' that would cause maximum compression in member CI.

Answer to Problem 4.155P

The maximum compression occurs at CI, when force 'P' acts at H.

The magnitude of maximum compression $PCI$ is $33941.12 lb$ .

Explanation of Solution

Given information:

International Edition---engineering Mechanics: Statics, 4th Edition, Chapter 4, Problem 4.155P , additional homework tip 3

Assume $P=48000 lb$ .

Steps to follow in the equilibrium analysis of a body are:

1. Draw the free body diagram.

2. Write the equilibrium equations.

3. Solve the equations for the unknowns.

Calculation:

According to sub part a

Force 'P' at point H

$↑Ey=0.5P$

The force $PCI$ in member CI

$PCI=−2Ey$

The maximum compression occurs at CI, when force 'P' acts at H.

$PCI=2Ey =2(0.5P) =0.7071P =33941.12 lb$

Conclusion:

The maximum compression occurs at CI, when force 'P' acts at H.

The magnitude of maximum compression $PCI$ is $33941.12 lb$ .

Expert Solution

To determine

(c)

Location of force 'P' that would cause maximum tension in member CI

Answer to Problem 4.155P

The maximum compression occurs at CI, when force 'P' acts at I.

The magnitude of maximum tension $PCI$ is $16944 lb$ .

Explanation of Solution

Given information:

International Edition---engineering Mechanics: Statics, 4th Edition, Chapter 4, Problem 4.155P , additional homework tip 4

Assume $P=48000 lb$ .

Steps to follow in the equilibrium analysis of a body are:

1. Draw the free body diagram.

2. Write the equilibrium equations.

3. Solve the equations for the unknowns.

Calculation:

According to sub part a

If force 'P' acts at point I

$Ey−P+(12)PCI=0$

Solve

$PCI=2(P−Ey) =2(P−0.75P) =0.353P =16944 lb$

The maximum tension occurs at member CI when force 'P' acts at point I.

Conclusion:

The maximum compression occurs at CI, when force 'P' acts at I.

The magnitude of maximum tension $PCI$ is $16944 lb$ .

Answer 8

Expert Solution

To determine

(a)

Location of force 'P' that would cause maximum tension in member HI.

Answer to Problem 4.155P

The maximum tension occurs at HI, when force 'P' acts at H.

The magnitude of maximum tension $PHI$ is $48000 lb$ .

Explanation of Solution

Given information:

International Edition---engineering Mechanics: Statics, 4th Edition, Chapter 4, Problem 4.155P , additional homework tip 1

Assume $P=48000 lb$ .

Steps to follow in the equilibrium analysis of a body are:

1. Draw the free body diagram.

2. Write the equilibrium equations.

3. Solve the equations for the unknowns.

Calculation:

Assume $Ey$ as the vertical reaction at point E.

Consider entire body

Force 'P' at point J

$↑Ey=P$

Force 'P' at point I

$↑Ey=0.75P$

Force 'P' at point H

$↑Ey=0.5P$

Force 'P' at point G

$↑Ey=0.25P$

Force 'P' at point F

$↑Ey=0$

FBD of below section

International Edition---engineering Mechanics: Statics, 4th Edition, Chapter 4, Problem 4.155P , additional homework tip 2

Assume $PCD,PCI,PHI$ as the forces acting on member CD, CI and HI respectively.

If force 'P' acts at point J

Write equilibrium equation in vertical direction.

$↑∑Fy=0$

$PCI=0$

For the equilibrium of above section, the bending moment about point C is equal to zero.

$∑MC=0$

$PHI=0$

If force 'P' acts at point I

$Ey−P+(12)PCI=0$

Solve

$PCI=2(P−Ey) =2(P−0.75P) =0.353P$

For the equilibrium of above section, the bending moment about point C is equal to zero.

$∑MC=0$

$Ey(2a)−P(a)−PHI(a)=0$

Solve

$PHI=2(0.75P)−P =0.5P$

If force 'P' acts at points G, H and F,

Write equilibrium equation in vertical direction.

$↑∑Fy=0$

$Ey+(1 2 )PCI=0 PCI=−2Ey$

For the equilibrium of above section, the bending moment about point C is equal to zero.

$∑MC=0$

$Ey(2a)−PHI(a)=0 PHI=2Ey$

The maximum tension occurs at HI, when force 'P' acts at H.

$PHI=2Ey =2(0.5P) =P =48000 lb$

Conclusion:

The maximum tension occurs at HI, when force 'P' acts at H.

The magnitude of maximum tension $PHI$ is $48000 lb$ .

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

To determine

(a)

Location of force 'P' that would cause maximum tension in member HI.

Answer 13

Answer to Problem 4.155P

The maximum tension occurs at HI, when force 'P' acts at H.

The magnitude of maximum tension $PHI$ is $48000 lb$ .

Answer 14

Explanation of Solution

Given information:

International Edition---engineering Mechanics: Statics, 4th Edition, Chapter 4, Problem 4.155P , additional homework tip 1

Assume $P=48000 lb$ .

Steps to follow in the equilibrium analysis of a body are:

1. Draw the free body diagram.

2. Write the equilibrium equations.

3. Solve the equations for the unknowns.

Calculation:

Assume $Ey$ as the vertical reaction at point E.

Consider entire body

Force 'P' at point J

$↑Ey=P$

Force 'P' at point I

$↑Ey=0.75P$

Force 'P' at point H

$↑Ey=0.5P$

Force 'P' at point G

$↑Ey=0.25P$

Force 'P' at point F

$↑Ey=0$

FBD of below section

International Edition---engineering Mechanics: Statics, 4th Edition, Chapter 4, Problem 4.155P , additional homework tip 2

Assume $PCD,PCI,PHI$ as the forces acting on member CD, CI and HI respectively.

If force 'P' acts at point J

Write equilibrium equation in vertical direction.

$↑∑Fy=0$

$PCI=0$

For the equilibrium of above section, the bending moment about point C is equal to zero.

$∑MC=0$

$PHI=0$

If force 'P' acts at point I

$Ey−P+(12)PCI=0$

Solve

$PCI=2(P−Ey) =2(P−0.75P) =0.353P$

For the equilibrium of above section, the bending moment about point C is equal to zero.

$∑MC=0$

$Ey(2a)−P(a)−PHI(a)=0$

Solve

$PHI=2(0.75P)−P =0.5P$

If force 'P' acts at points G, H and F,

Write equilibrium equation in vertical direction.

$↑∑Fy=0$

$Ey+(1 2 )PCI=0 PCI=−2Ey$

For the equilibrium of above section, the bending moment about point C is equal to zero.

$∑MC=0$

$Ey(2a)−PHI(a)=0 PHI=2Ey$

The maximum tension occurs at HI, when force 'P' acts at H.

$PHI=2Ey =2(0.5P) =P =48000 lb$

Conclusion:

The maximum tension occurs at HI, when force 'P' acts at H.

The magnitude of maximum tension $PHI$ is $48000 lb$ .

Answer 15

Expert Solution

To determine

(b)

Location of force 'P' that would cause maximum compression in member CI.

Answer to Problem 4.155P

The maximum compression occurs at CI, when force 'P' acts at H.

The magnitude of maximum compression $PCI$ is $33941.12 lb$ .

Explanation of Solution

Given information:

International Edition---engineering Mechanics: Statics, 4th Edition, Chapter 4, Problem 4.155P , additional homework tip 3

Assume $P=48000 lb$ .

Steps to follow in the equilibrium analysis of a body are:

1. Draw the free body diagram.

2. Write the equilibrium equations.

3. Solve the equations for the unknowns.

Calculation:

According to sub part a

Force 'P' at point H

$↑Ey=0.5P$

The force $PCI$ in member CI

$PCI=−2Ey$

The maximum compression occurs at CI, when force 'P' acts at H.

$PCI=2Ey =2(0.5P) =0.7071P =33941.12 lb$

Conclusion:

The maximum compression occurs at CI, when force 'P' acts at H.

The magnitude of maximum compression $PCI$ is $33941.12 lb$ .

Answer 16

Expert Solution

Answer 17

Expert Solution

Answer 18

Expert Solution

Answer 19

To determine

(b)

Location of force 'P' that would cause maximum compression in member CI.

Answer 20

Answer to Problem 4.155P

The maximum compression occurs at CI, when force 'P' acts at H.

The magnitude of maximum compression $PCI$ is $33941.12 lb$ .

Answer 21

Explanation of Solution

Given information:

International Edition---engineering Mechanics: Statics, 4th Edition, Chapter 4, Problem 4.155P , additional homework tip 3

Assume $P=48000 lb$ .

Steps to follow in the equilibrium analysis of a body are:

1. Draw the free body diagram.

2. Write the equilibrium equations.

3. Solve the equations for the unknowns.

Calculation:

According to sub part a

Force 'P' at point H

$↑Ey=0.5P$

The force $PCI$ in member CI

$PCI=−2Ey$

The maximum compression occurs at CI, when force 'P' acts at H.

$PCI=2Ey =2(0.5P) =0.7071P =33941.12 lb$

Conclusion:

The maximum compression occurs at CI, when force 'P' acts at H.

The magnitude of maximum compression $PCI$ is $33941.12 lb$ .

Answer 22

Expert Solution

To determine

(c)

Location of force 'P' that would cause maximum tension in member CI

Answer to Problem 4.155P

The maximum compression occurs at CI, when force 'P' acts at I.

The magnitude of maximum tension $PCI$ is $16944 lb$ .

Explanation of Solution

Given information:

International Edition---engineering Mechanics: Statics, 4th Edition, Chapter 4, Problem 4.155P , additional homework tip 4

Assume $P=48000 lb$ .

Steps to follow in the equilibrium analysis of a body are:

1. Draw the free body diagram.

2. Write the equilibrium equations.

3. Solve the equations for the unknowns.

Calculation:

According to sub part a

If force 'P' acts at point I

$Ey−P+(12)PCI=0$

Solve

$PCI=2(P−Ey) =2(P−0.75P) =0.353P =16944 lb$

The maximum tension occurs at member CI when force 'P' acts at point I.

Conclusion:

The maximum compression occurs at CI, when force 'P' acts at I.

The magnitude of maximum tension $PCI$ is $16944 lb$ .

Answer 23

Expert Solution

Answer 24

Expert Solution

Answer 25

Expert Solution

Answer 26

To determine

(c)

Location of force 'P' that would cause maximum tension in member CI

Answer 27

Answer to Problem 4.155P

The maximum compression occurs at CI, when force 'P' acts at I.

The magnitude of maximum tension $PCI$ is $16944 lb$ .

Answer 28

Explanation of Solution

Given information:

International Edition---engineering Mechanics: Statics, 4th Edition, Chapter 4, Problem 4.155P , additional homework tip 4

Assume $P=48000 lb$ .

Steps to follow in the equilibrium analysis of a body are:

1. Draw the free body diagram.

2. Write the equilibrium equations.

3. Solve the equations for the unknowns.

Calculation:

According to sub part a

If force 'P' acts at point I

$Ey−P+(12)PCI=0$

Solve

$PCI=2(P−Ey) =2(P−0.75P) =0.353P =16944 lb$

The maximum tension occurs at member CI when force 'P' acts at point I.

Conclusion:

The maximum compression occurs at CI, when force 'P' acts at I.

The magnitude of maximum tension $PCI$ is $16944 lb$ .

Answer 29

Ch. 4 - Each of the bodies shown is homogeneous and has a...Ch. 4 - Each of the bodies shown is homogeneous and has a...Ch. 4 - Each of the bodies shown is homogeneous and has a...Ch. 4 - The homogeneous bar weighs 12 lb. It is resting on...Ch. 4 - The homogeneous beam AB weighs 400 lb. For each...Ch. 4 - The homogeneous triangular plate has a mass of 12...Ch. 4 - The bracket of negligible weight is supported by a...Ch. 4 - The figure models the handle of the water cock...Ch. 4 - The high-pressure water cock is rigidly attached...Ch. 4 - Draw the FBD of the entire frame, assuming that...

Concept explainers

Videos

Answer to Problem 4.155P

Explanation of Solution

Answer to Problem 4.155P

Explanation of Solution

Answer to Problem 4.155P

Explanation of Solution

Want to see more full solutions like this?

Chapter 4 Solutions