Astronomy: A Beginner's Guide to the Universe (8th Edition)
8th Edition
ISBN: 9780134087702
Author: Eric Chaisson, Steve McMillan
Publisher: PEARSON
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Chapter 4, Problem 3RD
To determine
That all asteroids lie in the asteroid belt.
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Two identical circular loops of radius R, each carrying a steady current I,
are placed parallel to the xy-plane with their centers separated by a distance
d.
1. Derive an expression for the magnetic field produced by one loop at
the center of the other loop.
2. Calculate the force exerted by one loop on the other due to their mutual
magnetic interaction.
3. Discuss the sign of the force (attractive or repulsive) and how it depends
on the direction of the currents in the loops.
R
Loop 2
d
Loop 1
Consider a thin glass rod of radius R and length L carrying a uniform surface
charge σ. It is set spinning about its axis at an angular velocity w.
1. Find the direction of the magnetic field at a distances >> R from the
axis in the xy plane.
2. Find the magnitude of the magnetic fiield at a distances > R from
the axis in the xy plane. It is acceptable to provide the answer in an
integral form in this exam.
Hint: Treat the glass rod as a stack of magnetic dipoles.
FIGURE 5.66
>L/2
Chapter 4 Solutions
Astronomy: A Beginner's Guide to the Universe (8th Edition)
Ch. 4 - Prob. 1RDCh. 4 - Prob. 2RDCh. 4 - Prob. 3RDCh. 4 - Prob. 4RDCh. 4 - Prob. 5RDCh. 4 - Prob. 6RDCh. 4 - Prob. 7RDCh. 4 - Prob. 8RDCh. 4 - Prob. 9RDCh. 4 - Prob. 10RD
Ch. 4 - Prob. 11RDCh. 4 - Prob. 12RDCh. 4 - Prob. 13RDCh. 4 - Prob. 14RDCh. 4 - Prob. 15RDCh. 4 - Prob. 1CTCh. 4 - Prob. 2CTCh. 4 - Prob. 3CTCh. 4 - Prob. 4CTCh. 4 - Prob. 5CTCh. 4 - Prob. 6CTCh. 4 - Prob. 7CTCh. 4 - Prob. 8CTCh. 4 - Prob. 9CTCh. 4 - Prob. 10CTCh. 4 - Prob. 11CTCh. 4 - Prob. 12CTCh. 4 - Prob. 13CTCh. 4 - Prob. 14CTCh. 4 - Prob. 15CTCh. 4 - Prob. 1PCh. 4 - Prob. 2PCh. 4 - Prob. 3PCh. 4 - Prob. 4PCh. 4 - Prob. 5PCh. 4 - The planet orbiting star HD187123 has a semimajor...Ch. 4 - Prob. 7PCh. 4 - Prob. 8PCh. 4 - Prob. 9PCh. 4 - The amount of energy reaching a planet’s surface...
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