Essentials of Computer Organization and Architecture
5th Edition
ISBN: 9781284123036
Author: Linda Null
Publisher: Jones & Bartlett Learning
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Expert Solution & Answer
Chapter 4, Problem 37E
Explanation of Solution
Given scenario:
From given list, the address of node pointer is points to the next of each node in memory location. The given diagram starts with “Node 1”, so the address of the “Addr” is “Hex 0012”.
The “Node 1” points to “Node 2”, so the address of “Node 1” is “Hex 000E”, similarly the address of each node is as follows:
| Address(Hex) | Label | Instruction |
| 00D | Addr | Hex 0012 |
| 00E | Node 2 | Hex 0032 |
| 00F | Hex 0014 | |
| 010 | Node 4 | Hex 0034 |
| 011 | Hex 0016 | |
| 012 | Node 1 | Hex 0031 |
| 013 | Hex 000E | |
| 014 | Node 3 | Hex 0033 |
| 015 | Hex 0010 | |
| 016 | Node 5 | Hex 0035 |
| 017 | Hex 0000 |
MARIE
The following program is to traverse the list and print the node values in given order. The address of the code starts with “018”...
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Chapter 4 Solutions
Essentials of Computer Organization and Architecture
Ch. 4 - Prob. 1RETCCh. 4 - Prob. 2RETCCh. 4 - Prob. 3RETCCh. 4 - Prob. 4RETCCh. 4 - Prob. 5RETCCh. 4 - Prob. 6RETCCh. 4 - Prob. 7RETCCh. 4 - Prob. 8RETCCh. 4 - Prob. 9RETCCh. 4 - Prob. 10RETC
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