Algorithm : Algorithm MostOftenK(A, p,n): Input: An array “A” of “n” integers in the interval “[0,4n]” Output: An integer “k” that occurs most often in the array “A” loop for “j” from “0” to “m-1” do set A[A[j]%n] <- A[A[j]%n]+n endfor set temp <-A[0] set k <- 0 loop for “j” from “1” to “m-1”

Question

Want to see the full answer?

Answer 1

Expert Solution & Answer

Chapter 4, Problem 24C

Explanation of Solution

Algorithm:

Algorithm MostOftenK(A, p,n):

Input: An array “A” of “n” integers in the interval “[0,4n]”

Output: An integer “k” that occurs most often in the array “A”

loop for “j” from “0” to “m-1” do

set A[A[j]%n] <- A[A[j]%n]+n

endfor

set temp <-A[0]

set k <- 0

loop for “j” from “1” to “m-1”

Explanation of Solution

Running time of the algorithm:

The first “for” loop in the above algorithm is executed in the running time of “O(n)”.

The second “for” loop in the above algorithm is also exe

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 2

Expert Solution & Answer

Chapter 4, Problem 24C

Explanation of Solution

Algorithm:

Algorithm MostOftenK(A, p,n):

Input: An array “A” of “n” integers in the interval “[0,4n]”

Output: An integer “k” that occurs most often in the array “A”

loop for “j” from “0” to “m-1” do

set A[A[j]%n] <- A[A[j]%n]+n

endfor

set temp <-A[0]

set k <- 0

loop for “j” from “1” to “m-1”

Explanation of Solution

Running time of the algorithm:

The first “for” loop in the above algorithm is executed in the running time of “O(n)”.

The second “for” loop in the above algorithm is also exe

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Expert Solution & Answer

Chapter 4, Problem 24C

Explanation of Solution

Algorithm:

Algorithm MostOftenK(A, p,n):

Input: An array “A” of “n” integers in the interval “[0,4n]”

Output: An integer “k” that occurs most often in the array “A”

loop for “j” from “0” to “m-1” do

set A[A[j]%n] <- A[A[j]%n]+n

endfor

set temp <-A[0]

set k <- 0

loop for “j” from “1” to “m-1”

Explanation of Solution

Running time of the algorithm:

The first “for” loop in the above algorithm is executed in the running time of “O(n)”.

The second “for” loop in the above algorithm is also exe

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Expert Solution & Answer

Chapter 4, Problem 24C

Explanation of Solution

Algorithm:

Algorithm MostOftenK(A, p,n):

Input: An array “A” of “n” integers in the interval “[0,4n]”

Output: An integer “k” that occurs most often in the array “A”

loop for “j” from “0” to “m-1” do

set A[A[j]%n] <- A[A[j]%n]+n

endfor

set temp <-A[0]

set k <- 0

loop for “j” from “1” to “m-1”

Explanation of Solution

Running time of the algorithm:

The first “for” loop in the above algorithm is executed in the running time of “O(n)”.

The second “for” loop in the above algorithm is also exe

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Expert Solution & Answer

Answer 6

Expert Solution & Answer

Answer 7

Chapter 4, Problem 24C

Explanation of Solution

Algorithm:

Algorithm MostOftenK(A, p,n):

Input: An array “A” of “n” integers in the interval “[0,4n]”

Output: An integer “k” that occurs most often in the array “A”

loop for “j” from “0” to “m-1” do

set A[A[j]%n] <- A[A[j]%n]+n

endfor

set temp <-A[0]

set k <- 0

loop for “j” from “1” to “m-1”

Explanation of Solution

Running time of the algorithm:

The first “for” loop in the above algorithm is executed in the running time of “O(n)”.

The second “for” loop in the above algorithm is also exe

Answer 8

Chapter 4, Problem 24C

Explanation of Solution

Algorithm:

Algorithm MostOftenK(A, p,n):

Input: An array “A” of “n” integers in the interval “[0,4n]”

Output: An integer “k” that occurs most often in the array “A”

loop for “j” from “0” to “m-1” do

set A[A[j]%n] <- A[A[j]%n]+n

endfor

set temp <-A[0]

set k <- 0

loop for “j” from “1” to “m-1”

Answer 9

Chapter 4, Problem 24C

Explanation of Solution

Algorithm:

Algorithm MostOftenK(A, p,n):

Input: An array “A” of “n” integers in the interval “[0,4n]”

Output: An integer “k” that occurs most often in the array “A”

loop for “j” from “0” to “m-1” do

set A[A[j]%n] <- A[A[j]%n]+n

endfor

set temp <-A[0]

set k <- 0

loop for “j” from “1” to “m-1”

Answer 10

Explanation of Solution

Running time of the algorithm:

The first “for” loop in the above algorithm is executed in the running time of “O(n)”.

The second “for” loop in the above algorithm is also exe

Answer 11

Explanation of Solution

Running time of the algorithm:

The first “for” loop in the above algorithm is executed in the running time of “O(n)”.

The second “for” loop in the above algorithm is also exe

Answer 12

Expert Solution & Answer

Answer 13

Expert Solution & Answer

Answer 14

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 15

Ch. 4 - Prob. 1R Ch. 4 - Prob. 2R Ch. 4 - Prob. 3R Ch. 4 - Draw the recursion trace of the Power algorithm...Ch. 4 - Prob. 5R Ch. 4 - Prob. 7R Ch. 4 - Prob. 8R Ch. 4 - Prob. 9R Ch. 4 - Prob. 10R Ch. 4 - Prob. 11R

Concept explainers

Explanation of Solution

Explanation of Solution

Running time of the algorithm:

The first “for” loop in the above algorithm is executed in the running time of “O(n)”.

The second “for” loop in the above algorithm is also exe

Want to see the full answer?

Chapter 4 Solutions

Concept explainers

Explanation of Solution

Explanation of Solution

Running time of the algorithm: The first “for” loop in the above algorithm is executed in the running time of “O(n)”. The second “for” loop in the above algorithm is also exe

Want to see the full answer?

Chapter 4 Solutions

Running time of the algorithm:

The first “for” loop in the above algorithm is executed in the running time of “O(n)”.

The second “for” loop in the above algorithm is also exe