Chapter 4, Problem 18MCQ

To determine

To find:The standard form of the given equation.

Answer to Problem 18MCQ

The standard form of the given equation is $y-\left(-4\right)=\frac{2}{3}\left(x-\left(3\right)\right)$ .

Explanation of Solution

Given:

The equation is $y+4=\frac{2}{3}\left(x-3\right)$

Calculation:

The standard form of slope and point form of the straight line is $y-y_1=m\left(x-x_1\right)$ .

Here m is the slope of the straight line and $\left(x_1,y_1\right)$ is the point from which the straight line passes.

Converting the given equation in the standard form:

  $\begin{array}{l}y+4=\frac{2}{3}\left(x-3\right)\\ y-\left(-4\right)=\frac{2}{3}\left(x-\left(3\right)\right)\end{array}$

From the standard form of the equation, following information can be obtained.

The slope mof the equation is $\frac{2}{3}$ and the line passes through the point $\left(3,-4\right)$ ..

Therefore, the standard form of the slope and point form of the equation of the straight line is $y-\left(-4\right)=\frac{2}{3}\left(x-\left(3\right)\right)$ .