(a)
Interpretation:
The molarity of 25.00 mL solution of iron(III) nitrate should be determined which reacts with 12.54 mL of 0.1488 M sodium carbonate.
Concept introduction:
Number of moles is equal to the ratio of given mass to the molar mass.
The mathematical expression is given by:
Number of moles =
Molarity is defined as the ratio of number of moles of solute to the volume of the solution in liters.
The mathematical expression is given by:
Molarity =
A solution of salt of metal when reacts with other solution to give products, the formula which is used to find the volume of either solution is given by:
Where, M1 and M2 are molarity of the solution
V1 and V2 are volume of the solution
(b)
Interpretation:
The molarity of 25.00 mL solution of iron(III) nitrate should be determined which reacts with 7.58 g of potassium phosphate.
Concept introduction:
Number of moles is equal to the ratio of given mass to the molar mass.
The mathematical expression is given by:
Number of moles =
Molarity is defined as the ratio of number of moles of solute to the volume of the solution in liters.
The mathematical expression is given by:
Molarity =
A solution of salt of metal when reacts with other solution to give products, the formula which is used to find the volume of either solution is given by:
Where, M1 and M2 are molarity of the solution
V1 and V2 are volume of the solution
(c)
Interpretation:
The molarity of 25.00 mL solution of iron(III) nitrate should be determined which reacts with 10.00 mL of 0.1573 M
Concept introduction:
Number of moles is equal to the ratio of given mass to the molar mass.
The mathematical expression is given by:
Number of moles =
Molarity is defined as the ratio of number of moles of solute to the volume of the solution in liters.
The mathematical expression is given by:
Molarity =
A solution of salt of metal when reacts with other solution to give products, the formula which is used to find the volume of either solution is given by:
Where, M1 and M2 are molarity of the solution
V1 and V2 are volume of the solution
Trending nowThis is a popular solution!
Chapter 4 Solutions
Chemistry: Principles and Reactions
- Bone was dissolved in hydrochloric acid, giving 50.0 mL of solution containing calcium chloride, CaCL2. To precipitate the calcium ion from the resulting solution, an excess of potassium oxalate was added. The precipitate of calcium oxalate, CaC2O4, weighed 1.437 g. What was the molarity of CaCl2 in the solution?arrow_forwardA soluble iodide was dissolved in water. Then an excess of silver nitrate, AgNO3, was added to precipitate all of the iodide ion as silver iodide, AgI. If 1.545 g of the soluble iodide gave 2.185 g of silver iodide, how many grams of iodine are in the sample of soluble iodide? What is the mass percentage of iodine, I, in the compound?arrow_forwardWhen 10. L of water is added to 3.0 L of 6.0 M H2SO4, what is the molarity of the resulting solution? Assume the volumes are additive.arrow_forward
- A 1.345-g sample of a compound of barium and oxygen was dissolved in hydrochloric acid to give a solution of barium ion, which was then precipitated with an excess of potassium chromate to give 2.012 g of barium chromate, BaCrO4. What is the formula of the compound?arrow_forwardTwenty-five mL of a 0.388 M solution of Na2SO4 is mixed with 35.3 mL of 0.229 M Na2SO4. What is the molarity of the resulting solution? Assume that the volumes are additive.arrow_forwardWhat is the molarity of a solution of sodium hydrogen sulfate that is prepared by dissolving 9.21 g NaHSO4 in enough water to form 2.00-L solution? What is the molarity of each ion in the solution?arrow_forward
- Write a balanced equation for the reaction of hydroiodic acid, HI, with calcium hydroxide, Ca(OH)2. Then, write the balanced complete ionic equation and the net ionic equation for this neutralization reaction.arrow_forwardAn antacid tablet has calcium carbonate as the active ingredient; other ingredients include a starch binder. You dissolve the tablet in hydrochloric acid and filter off insoluble material. You add potassium oxalate to the filtrate (containing calcium ion) to precipitate calcium oxalate. If a tablet weighing 0.750 g gave 0.629 g of calcium oxalate, what is the mass percentage of active ingredient in the tablet?arrow_forwardDetermine the volume of sulfuric acid solution needed to prepare 37.4 g of aluminum sulfate, Al2(SO4)3, by the reaction 2Al(s)+3H2SO4(aq)Al2(SO4)3(aq)+3H2(g) The sulfuric acid solution, whose density is 1.104 g/mL, contains 15.0% H2SO4 by mass.arrow_forward
- Determine the volume of sodium hydroxide solution needed to prepare 26.2 g sodium phosphate, Na3PO4, by the reaction 3NaOH(aq)+H3PO4(aq)Na3PO4(aq)+3H2O(l) The sodium hydroxide solution, whose density is 1.133 g/mL, contains 12.0% NaOH by mass.arrow_forwardA solution of hydrogen peroxide, H2O2, is titrated with a solution of potassium permanganate, KMnO4. The reaction is 5H2O2(aq)+2KMnO4(aq)+3H2SO4(aq)5O2(g)+2MnSO4(aq)+K2SO4(aq)+8H2O(l) It requires 51.7 mL of 0.145 M KMnO4 to titrate 20.0 g of the solution of hydrogen peroxide. What is the mass percentage of H2O2 in the solution?arrow_forward
- Chemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage LearningChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningGeneral Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage Learning
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningIntroductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage Learning