EBK PHYSICS FOR SCIENTISTS & ENGINEERS
EBK PHYSICS FOR SCIENTISTS & ENGINEERS
5th Edition
ISBN: 9780134296074
Author: GIANCOLI
Publisher: VST
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Chapter 37, Problem 76GP
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The proof that the magnitude of the electrostatic potential energy of an electron in any Bohr orbit of a hydrogen atom it twice the magnitude of its kinetic energy in that orbit.

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As per Bohr model of a hydrogen atom for a stable orbit centripetal, Coulomb, and all forces should be in equilibrium. Therefore, for an electron with mass me and speed v₁ on the nth orbit with radius rn, (k being Coulomb/s constant) mevn = ke²/rn mevn² = ke²/rn mevn²/rn = ke²/rn 2.2 Ome²v² = ke²/r²
A particular Bohr orbit in a hydrogen atom has a total energy of-0.85 eV. What are (a) the kinetic energy of the electron in thisorbit and (b) the electric potential energy of the system?
The electron of a hydrogen atom is in an orbit with radius of 8.46 Å (1 Å = 10-10 m), according to the Bohr model. Which of the following statements is correct?  a) The total energy of the orbit is –13.6 eV, and the kinetic energy is +13.6 eV. b) The total energy of the orbit is –0.85 eV, and the potential energy is –1.70 eV. c) The total energy of the orbit is –0.85 eV, and the potential energy is +1.70 eV. d) The total energy of the orbit is –0.85 eV, and the potential energy is –0.85 eV. e) The total energy of the orbit is –3.40 eV, and the potential energy is –6.80 eV.
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