Essential University Physics (3rd Edition)
3rd Edition
ISBN: 9780134202709
Author: Richard Wolfson
Publisher: PEARSON
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Chapter 35.3, Problem 35.5GI
To determine
Either of Proton or electron more likely get through the barrier.
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Four different particles are trapped in one dimensional wells with infinite potential at the walls and zero potential inside. The masses of the particles and their energy level, n , are given by:
1. mass=m, n=1
2. mass=2m, n=2
3. mass =3m, n=3
4. mass=4m, n=2
All these wells have the same length L. Rank the kinetic energy of the particles in order of size, smallest to largest.
Group of answer choices
E3 <E1<E2<E4
E1 = E4 < E2 < E3
E4 <E3 <E2 = E1
E1 < E2 = E4 < E3
E1 < E2 = E3 <E4
81. Take the derivative of the Lennard–Jones potential to express the force exerted on one atom by another as a function of the distance R between them. Calculate the forces (in joules per meter) on a pair of interacting argon atoms at distances of 3.0, 3.4, 3.8, and 4.2 × 10210 m. To calculate the direction of the force on each atom, assume that one Ar atom is at the origin and the other argon atom is at the coordinates (23.0 Å, 0), (23.4 Å, 0), (23.8 Å, 0), and (24.2 Å, 0). Calculate the vector components Fx and Fy for the force F5 (Fx, Fy) on the argon atom at the origin (particle 1 in the solutions) and the vector components for the force on the other atom (particle 2 in the solution), showing explicitly what you are using for the unit vector ˆ21 r or the unit vector ˆ12 r . (Hint: Use Eq. 3.4, but with the correct V(R).) Is the force
The layer in the figure is between z=+d and z=-d in the z direction. The layer extends to infinity in the x and y directions. The charge density inside the layer is p and is independent of position. There is no charge outside the layer. Find the electric potential inside (|z|<d) and outside (|z|>d) of the layer.
Chapter 35 Solutions
Essential University Physics (3rd Edition)
Ch. 35.1 - Prob. 35.1GICh. 35.2 - Prob. 35.2GICh. 35.3 - Prob. 35.3GICh. 35.3 - Prob. 35.4GICh. 35.3 - Prob. 35.5GICh. 35.4 - Prob. 35.6GICh. 35 - Prob. 1FTDCh. 35 - Prob. 2FTDCh. 35 - Prob. 3FTDCh. 35 - Prob. 4FTD
Ch. 35 - Prob. 5FTDCh. 35 - Prob. 6FTDCh. 35 - Prob. 7FTDCh. 35 - What did Einstein mean by his re maxi, loosely...Ch. 35 - Prob. 9FTDCh. 35 - Prob. 10FTDCh. 35 - Prob. 12ECh. 35 - Prob. 13ECh. 35 - Prob. 14ECh. 35 - Prob. 15ECh. 35 - Prob. 16ECh. 35 - Prob. 17ECh. 35 - Prob. 18ECh. 35 - Prob. 19ECh. 35 - Prob. 20ECh. 35 - Prob. 21ECh. 35 - Prob. 22ECh. 35 - Prob. 23ECh. 35 - Prob. 24ECh. 35 - Prob. 25ECh. 35 - Prob. 26ECh. 35 - Prob. 27ECh. 35 - Prob. 28ECh. 35 - Prob. 29ECh. 35 - Prob. 30ECh. 35 - Prob. 31ECh. 35 - Prob. 32PCh. 35 - Prob. 33PCh. 35 - Prob. 34PCh. 35 - Prob. 35PCh. 35 - Prob. 36PCh. 35 - Prob. 37PCh. 35 - Prob. 38PCh. 35 - Prob. 39PCh. 35 - Prob. 40PCh. 35 - Prob. 41PCh. 35 - Prob. 42PCh. 35 - Prob. 43PCh. 35 - Prob. 44PCh. 35 - Prob. 45PCh. 35 - Prob. 46PCh. 35 - Prob. 47PCh. 35 - Prob. 48PCh. 35 - Prob. 49PCh. 35 - Prob. 50PCh. 35 - Prob. 51PCh. 35 - Prob. 52PCh. 35 - Prob. 53PCh. 35 - Prob. 54PCh. 35 - Prob. 55PCh. 35 - Prob. 56PCh. 35 - Prob. 57PCh. 35 - Prob. 58PCh. 35 - Prob. 59PCh. 35 - Prob. 60PCh. 35 - Prob. 61PPCh. 35 - Prob. 62PPCh. 35 - Prob. 63PPCh. 35 - Prob. 64PP
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