Answer The correct answer is (a) T= 135 hr . (b)Average speed= 0.068 F / h r . (c) Approximate speed= 0.060 F / h r (d) 9 − 10 Furlong marker (F) horse is running fastest. (e) 9 − 10 Furlong marker (F) horse is accelerating fastest. Explanation Given information: In this question a racehorse is running a 10-furlong race, is given And some data is given. We will use this data to find the answer of the given questions. Calculation: See the table carefully, in this table to complete 10 furlong race, horse is taking 135 sec. And this time is total time to finish the race. Average speed of the horse over the first 5 furlongs can be find by using, A v e r a g e s p e e d = t o t a l d i s tan c e t o t a l t i m e A v e r a g e s p e e d = t o t a l d i s tan c e t o t a l t i m e = 5 73 = 0.068 F / h r Approximate speed of the horse as it passes the 3-furlong maker can be find by using, s p e e d = t o t a l d i s tan c e t o t a l t i m e = 2 33 = 0.060 F / h r To find in which portion the horse is running fastest, we will see in speed formula. For applying this formula we have to know about relation between distance and time, Herein the question distance is fixed, so we will take least value of time required. Then in 9 − 10 Furlong marker (F) horse takes less time. Hence in this duration horse is running fastest. To find in which portion the horse is accelerating fastest, we will see in acceleration formula. For applying this formula we have to know about relation between Velocity and time, Here in the question velocity and is fastest in above cases, so we will take least value of time required. Then in 9 − 10 Furlong marker (F) horse takes less time. Hence in this duration horse is accelerating fastest. Thus, the correct answer is (a) T= 135 hr . (b)Average speed= 0.068 F / h r . (c) Approximate speed= 0.060 F / h r (d) 9 − 10 Furlong marker (F) horse is running fastest. (e) 9 − 10 Furlong marker (F) horse is accelerating fastest

Calculus 2012 Student Edition (by Finney/Demana/Waits/Kennedy)

4th Edition

ISBN: 9780133178579

Author: Ross L. Finney

Publisher: PEARSON

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Question

Chapter 3.4, Problem 12E

To determine

To calculate: Find (a) the time taken by the horse to finish the race.

(b) Average speed of the horse over the first 5 furlongs?

(c) Approximate speed of the horse as it passes the 3-furlong maker.

(d) During which portion of the race, horse is running fast.

(e) During which portion of the race, horse is accelerating fast.

Expert Solution & Answer

Answer to Problem 12E

The correct answer is (a) T= 135 hr.

(b)Average speed= 0.068F/hr.

(d) 9−10 Furlong marker (F) horse is running fastest.

(e) 9−10 Furlong marker (F) horse is accelerating fastest.

Explanation of Solution

Given information: In this question a racehorse is running a 10-furlong race, is given And some data is given. We will use this data to find the answer of the given questions.

Calculation:

See the table carefully, in this table to complete 10 furlong race, horse is taking 135 sec. And this time is total time to finish the race.
Average speed of the horse over the first 5 furlongs can be find by using,

Average speed=total distancetotal time

Average speed=total distancetotal time=573=0.068F/hr

Approximate speed of the horse as it passes the 3-furlong maker can be find by using,

speed=total distancetotal time=233=0.060F/hr

To find in which portion the horse is running fastest, we will see in speed formula. For applying this formula we have to know about relation between distance and time, Herein the question distance is fixed, so we will take least value of time required. Then in 9−10 Furlong marker (F) horse takes less time. Hence in this duration horse is running fastest.
To find in which portion the horse is accelerating fastest, we will see in acceleration formula. For applying this formula we have to know about relation between Velocity and time, Here in the question velocity and is fastest in above cases, so we will take least value of time required. Then in 9−10 Furlong marker (F) horse takes less time. Hence in this duration horse is accelerating fastest.

Thus, the correct answer is (a) T= 135 hr.

(b)Average speed= 0.068F/hr.

(d) 9−10 Furlong marker (F) horse is running fastest.

(e) 9−10 Furlong marker (F) horse is accelerating fastest

Chapter 3.4, Problem 11E

Chapter 3.4, Problem 13E

Chapter 3 Solutions

Calculus 2012 Student Edition (by Finney/Demana/Waits/Kennedy)

Ch. 3.1 - Prob. 1QR Ch. 3.1 - Prob. 2QR Ch. 3.1 - Prob. 3QR Ch. 3.1 - Prob. 4QR Ch. 3.1 - Prob. 5QR Ch. 3.1 - Prob. 6QR Ch. 3.1 - Prob. 7QR Ch. 3.1 - Prob. 8QR Ch. 3.1 - Prob. 9QR Ch. 3.1 - Prob. 10QR

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