Big Ideas Math A Bridge To Success Algebra 2: Student Edition 2015
Big Ideas Math A Bridge To Success Algebra 2: Student Edition 2015
1st Edition
ISBN: 9781680331165
Author: HOUGHTON MIFFLIN HARCOURT
Publisher: Houghton Mifflin Harcourt
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Chapter 3.1, Problem 65E
To determine

To calculate: .The length of quadrilateral of each side.

Expert Solution & Answer
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Answer to Problem 65E

The required lengths are 1203,1603,1003 and 300 .

Explanation of Solution

Given Information:

The figure of quadrilateral which divided into two right triangle is:

  Big Ideas Math A Bridge To Success Algebra 2: Student Edition 2015, Chapter 3.1, Problem 65E

Formula Used:

Pythagoras theorem:

  a2+b2=c2

Where,

  a= side of right angle.

  b= side of right angle.

  c= hypotenuse.

Calculation:

Consider the ΔDAB and ΔDCB are right angle triangle and DB=p is a length of hypotenuse.

Use Pythagoras theorem in right angle ΔDAB .

  a2+b2=c2

Substitute 6x for a , 8x for b and p for c in the above equation.

  (6x)2+(8x)2=p2 ………………(1)

Again, use Pythagoras theorem in right angle ΔDCB .

  a2+b2=c2

Substitute 5x for a , 300 for b and p for c in the above equation.

  (5x)2+(300)2=p2 …………….(2)

Now, compare the equation (1) and (2).

  (6x)2+(8x)2=(5x)2+(300)2

Simplify the above equation.

  (6x)2+(8x)2=(5x)2+(300)236x2+64x2=25x2+90000100x225x2=9000075x2=90000

Simplify the equation.

  75x2=90000x2=9000075x=1200x=203

Since, from the figure the each sides of quadrilateral are 6x,8x,5x and 300 .

Substitute 203 for x in the above each side.

Thus, the side are 1203,1603,1003 and 300 .

Hence, the required sides are 1203,1603,1003 and 300 .

Chapter 3 Solutions

Big Ideas Math A Bridge To Success Algebra 2: Student Edition 2015

Ch. 3.1 - Prob. 11ECh. 3.1 - Prob. 12ECh. 3.1 - Prob. 13ECh. 3.1 - Prob. 14ECh. 3.1 - Prob. 15ECh. 3.1 - Prob. 16ECh. 3.1 - Prob. 17ECh. 3.1 - Prob. 18ECh. 3.1 - Prob. 19ECh. 3.1 - Prob. 20ECh. 3.1 - Prob. 21ECh. 3.1 - Prob. 22ECh. 3.1 - Prob. 23ECh. 3.1 - Prob. 24ECh. 3.1 - Prob. 25ECh. 3.1 - Prob. 26ECh. 3.1 - Prob. 27ECh. 3.1 - Prob. 28ECh. 3.1 - Prob. 29ECh. 3.1 - Prob. 30ECh. 3.1 - Prob. 31ECh. 3.1 - Prob. 32ECh. 3.1 - Prob. 33ECh. 3.1 - Prob. 34ECh. 3.1 - Prob. 35ECh. 3.1 - Prob. 36ECh. 3.1 - Prob. 37ECh. 3.1 - Prob. 38ECh. 3.1 - Prob. 39ECh. 3.1 - Prob. 40ECh. 3.1 - Prob. 41ECh. 3.1 - Prob. 42ECh. 3.1 - Prob. 43ECh. 3.1 - Prob. 44ECh. 3.1 - Prob. 45ECh. 3.1 - Prob. 46ECh. 3.1 - Prob. 47ECh. 3.1 - Prob. 48ECh. 3.1 - Prob. 49ECh. 3.1 - Prob. 50ECh. 3.1 - Prob. 51ECh. 3.1 - Prob. 52ECh. 3.1 - Prob. 53ECh. 3.1 - Prob. 54ECh. 3.1 - Prob. 55ECh. 3.1 - Prob. 56ECh. 3.1 - Prob. 57ECh. 3.1 - Prob. 58ECh. 3.1 - Prob. 59ECh. 3.1 - Prob. 60ECh. 3.1 - Prob. 61ECh. 3.1 - Prob. 62ECh. 3.1 - Prob. 63ECh. 3.1 - 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