Physics: Principles with Applications
Physics: Principles with Applications
6th Edition
ISBN: 9780130606204
Author: Douglas C. Giancoli
Publisher: Prentice Hall
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Question
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Chapter 31, Problem 61GP

(a)

To determine

Total power output of the Sun.

(a)

Expert Solution
Check Mark

Answer to Problem 61GP

The total power output is P=3.96×1026W

Explanation of Solution

Given:

Rate of energy, I=1400 W/m2

Formula used:

Power output can be given as:

  P=I(4πr2)

Calculation:

Distance between the Earth and the Sun is r=1.5×1011m

Substituting all the values, in the above formula:

  P=(1400 W/m2)(4)(3.14)(1.5×1011m)2P=3.96×1026W

Conclusion:

Hence, the total power output is P=3.96×1026W

(b)

To determine

Number of protons consumed per second in the reaction.

(b)

Expert Solution
Check Mark

Answer to Problem 61GP

The number of protons per second is N=3.706×1038

Explanation of Solution

Given:

Rate of energy, I=1400 W/m2

Calculation:

Energy released for the reaction in eq 31-7,

  E=26.7 MeVE=26.7×106×1.6×1019JE=160.2×1013J

So, the number of protons per second is:

  N=(3.96×1026W)(4)160.2×1013JN=3.706×1038protons/s

Conclusion:

Thus, the number of protons per second is N=3.706×1038

(c)

To determine

Time taken by the Sun to glow at its present rate.

(c)

Expert Solution
Check Mark

Answer to Problem 61GP

The time taken by the Sun to glow at its present rate will be t=1011yrs

Explanation of Solution

Given:

Rate of energy, I=1400 W/m2

Mass of Sun, m=2.0×1030kg

Calculation:

The time taken can be calculated as follows:

  t=(2.0×1030kg)(1.67×1027kg)(3.706×1038protons/s)(3.156×107s)t=1011yrs

Conclusion:

Hence, the time taken by the Sun to glow at its present rate will be t=1011yrs

Chapter 31 Solutions

Physics: Principles with Applications

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