Physics for Scientists and Engineers
10th Edition
ISBN: 9781337553278
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
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Chapter 31, Problem 44AP
To determine
The reason for which the given situation is impossible for the experiment.
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Chapter 31 Solutions
Physics for Scientists and Engineers
Ch. 31.1 - A coil with zero resistance has its ends labeled a...Ch. 31.2 - Prob. 31.2QQCh. 31.3 - Prob. 31.3QQCh. 31.4 - Prob. 31.4QQCh. 31.5 - (i) At an instant of time during the oscillations...Ch. 31 - Prob. 1PCh. 31 - Prob. 2PCh. 31 - An emf of 24.0 mV Ls induced in a 500-turn coil...Ch. 31 - Prob. 4PCh. 31 - Prob. 5P
Ch. 31 - A toroid has a major radius R and a minor radius r...Ch. 31 - Prob. 7PCh. 31 - Prob. 8PCh. 31 - Prob. 9PCh. 31 - Prob. 10PCh. 31 - Prob. 11PCh. 31 - Show that i = Iiet/ is a solution of the...Ch. 31 - Prob. 13PCh. 31 - You are working as a demonstration assistant for a...Ch. 31 - Prob. 15PCh. 31 - The switch in Figure P31.15 is open for t 0 and...Ch. 31 - Prob. 17PCh. 31 - Two ideal inductors, L1 and L2, have zero internal...Ch. 31 - Prob. 19PCh. 31 - Prob. 20PCh. 31 - Prob. 21PCh. 31 - Complete the calculation in Example 31.3 by...Ch. 31 - Prob. 23PCh. 31 - A flat coil of wire has an inductance of 40.0 mH...Ch. 31 - Prob. 25PCh. 31 - Prob. 26PCh. 31 - Prob. 27PCh. 31 - Prob. 28PCh. 31 - In the circuit of Figure P31.29, the battery emf...Ch. 31 - Prob. 30PCh. 31 - An LC circuit consists of a 20.0-mH inductor and a...Ch. 31 - Prob. 32PCh. 31 - In Figure 31.15, let R = 7.60 , L = 2.20 mH, and C...Ch. 31 - Prob. 34PCh. 31 - Electrical oscillations are initiated in a series...Ch. 31 - Review. Consider a capacitor with vacuum between...Ch. 31 - A capacitor in a series LC circuit has an initial...Ch. 31 - Prob. 38APCh. 31 - Prob. 39APCh. 31 - At the moment t = 0, a 24.0-V battery is connected...Ch. 31 - Prob. 41APCh. 31 - You are working on an LC circuit for an experiment...Ch. 31 - Prob. 43APCh. 31 - Prob. 44APCh. 31 - Prob. 45APCh. 31 - At t = 0, the open switch in Figure P31.46 is...Ch. 31 - Review. The use of superconductors has been...Ch. 31 - Review. A fundamental property of a type 1...Ch. 31 - Prob. 49APCh. 31 - In earlier times when many households received...Ch. 31 - Assume the magnitude of the magnetic field outside...Ch. 31 - Prob. 52CPCh. 31 - Prob. 53CP
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- After you disconnect the DC power supply from an RLC circuit, it oscillates at a frequency of f. Then you remake the circuit with the same inductor and capacitor but now with 2 resistors in series instead of just one, so that the new circuit has twice the resistance. Despite the resistance having doubled, the circuit can still be said to be underdamped. What is the new oscillation frequency that you observe when you power the new circuit from the DC power supply and disconnect it? O less than f impossible to say without knowing whether the inductance is bigger or smaller than the resistance exactly equal to f greater than farrow_forwardA circuit consists of a 0.8 H inductor and a 3.5 ohm resistor. At t = 0 the current through the inductor is 1.2 A. How much energy is stored in the inductor at this instant?arrow_forwardA battery is used to charge a capacitor. When the stored energy in the capacitor is 1 µj, it is disconnected from the battery in the circuit and connected in series with an inductor which has inductance of 6 µH. What is the current in the inductor when the capacitor charge is half of its initial maximum value? (Resistance is negligible.) O 0.2 A O 0.5 A O v2 A O 2 A O 20 Aarrow_forward
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- charge and the current (i) is zero, then P= 0. If q =0 at time t =0, then =±n/2. Example: A 300-V dc power supply is used to charge a 25-µF capacitor. After the capacitor is fully charged, it is disconnected from the power supply and connected across a 10-mH inductor. The resistance in the circuit is negligible. (a) Find the frequency and period of oscillation of the circuit. (b) Find the capacitor charge and the circuit current 1.2 ms after the inductor and capacitor are connected. Then find for the magnetic and electric energies (c) at and (d) at t = 1.2 ms. Given: C = 25 x 106 F L = 10 x 103 H t = 1.2 x 103 s (c) Solving for magnetic (UB) and electric (UE) energies at time t =0. Solution: (7.5 x 10-3 C)? (a) Solving for angular frequency (w)and period (T) Ug =Li? = 0 Ug = 2C - 1.1 J 2(25 x 10-6 F) 1 = 2.03 x 10° rad/s (10 x 10-3H)(25 x 10¬°F) (d) Solving for magnetic (UB) and electric (UE) energies at time t =1.2 ms. 2. 03 х 103 Рad Ug = }Li² = }(10 × 10-3 H)(-10 A)² = 0.5 J f = 320…arrow_forwardA circuit consists of a 0.80 H inductor and a 3.5 ohm resistor. At t = 0 the current through the inductor is 1.2 A. At what time is the current through the inductor equal to 0.40 A?arrow_forwardAn uncharged capacitor is connected in series with a resistor, a dc battery, and an open switch. At time t = 0 s, the switch is closed. (a) Draw a graph that best describes the current I through the capacitor as a function of time t. (b) If an inductor is added in series to this dc circuit and the capacitor is uncharged again with an open switch, then draw a graph that shows the current I through the capacitor as a function of time starting at t= 0 s when the switch is closed.arrow_forward
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