Explanation Formula used: The auxiliary equation of a linear homogeneous differential equation of the form a 0 D 2 y + a 1 D y + a 2 y = 0 with constant coefficients is given by a 0 m 2 + a 1 m + a 2 = 0 . The general solution of the auxiliary equation with complex roots is given by y = e α x ( c 1 sin β x + c 2 cos β x ) . The general solution of the auxiliary equation with double roots m is given by y = e m x ( c 1 + c 2 x ) . The general solution of the auxiliary equation with two distinct roots m 1 and m 2 , is given by y = c 1 e m 1 x + c 2 e m 2 x . The solution of a linear non-homogeneous differential equation of the form a 0 D 2 y + a 1 D y + a 2 y = b where the a ’s are constants and b is a function of x or is a constant, is given by y = y c + y p . The y c is called the complementary solution obtained by solving the corresponding homogeneous equation and where y p is the particular solution. The different forms of b and their corresponding particular solution to be used is shown below: b y p ( x ) a e β x A e β x a cos ( β x ) A cos ( β x ) + B sin ( β x ) b sin ( β x ) A cos ( β x ) + B sin ( β x ) a cos ( β x ) + b sin ( β x ) A cos ( β x ) + B sin ( β x ) n th degree polynomial A n x n + A n − 1 x n − 1 + A 1 x + A 0 Calculation: The given equation is D 3 y − D 2 y + 9 D y − 9 y = sin x which is same as y ′ ′ ′ − y ″ + 9 y ′ − 9 y = sin x . Note that the solution of the auxiliary equation m 3 − m 2 + 9 m − 9 = 0 gives the roots as follows. m 3 − m 2 + 9 m − 9 = 0 m 2 ( m − 1 ) + 9 ( m − 1 ) = 0 ( m 2 + 9 ) ( m − 1 ) = 0 m 2 + 9 = 0 and m − 1 = 0 m = ± 3 i and m = 1 Thus, the complimentary function is given as follows. y c = c 1 e x + e 0 x ( c 2 sin 3 x + c 3 cos 3 x ) = c 1 e x + c 2 sin 3 x + c 3 cos 3 x Note that the particular solution is y p = A sin x + B cos x

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ISBN: 9780134437705

Author: Washington

Publisher: PEARSON

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Chapter 31, Problem 35RE

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The solution for the given differential equation D3y−D2y+9Dy−9y=sinx.

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Chapter 31, Problem 34RE

Chapter 31, Problem 36RE

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Chapter 31 Solutions

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Ch. 31.1 - Show that is a solution of . Is it the general...Ch. 31.1 - Prob. 1E Ch. 31.1 - In Exercises 1 and 2, show that the indicated...Ch. 31.1 - In Exercises 3–6, determine whether the given...Ch. 31.1 - Prob. 4E Ch. 31.1 - In Exercises 3–6, determine whether the given...Ch. 31.1 - Prob. 6E Ch. 31.1 - In Exercises 7–10, show that each function y =...Ch. 31.1 - Prob. 8E Ch. 31.1 - In Exercises 7–10, show that each function y =...

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The solution for the given differential equation D 3 y − D 2 y + 9 D y − 9 y = sin x .

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The solution for the given differential equation D3y−D2y+9Dy−9y=sinx.

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