EBK PHYSICS FOR SCIENTISTS AND ENGINEER
1st Edition
ISBN: 9780100546714
Author: Katz
Publisher: YUZU
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Chapter 30, Problem 85PQ
To determine
Determine the direction of the magnetic field in each case.
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Chapter 30 Solutions
EBK PHYSICS FOR SCIENTISTS AND ENGINEER
Ch. 30.2 - Prob. 30.1CECh. 30.3 - Prob. 30.2CECh. 30.4 - Prob. 30.3CECh. 30.8 - Cosmic rays are high-energy charged particles...Ch. 30.9 - The Earths Van Allen belts (Fig. 30.34) are a...Ch. 30.10 - Prob. 30.6CECh. 30.10 - Prob. 30.7CECh. 30.12 - Prob. 30.8CECh. 30 - A yoga teacher tells her students to imagine their...Ch. 30 - Prob. 2PQ
Ch. 30 - Prob. 3PQCh. 30 - Prob. 4PQCh. 30 - Prob. 5PQCh. 30 - Copy Figure P30.6 and sketch the magnetic field...Ch. 30 - Prob. 7PQCh. 30 - Prob. 9PQCh. 30 - Figure P30.10 shows a circular current-carrying...Ch. 30 - Figure P30.11 shows three configurations of wires...Ch. 30 - Review A proton is accelerated from rest through a...Ch. 30 - An electron moves in a circle of radius r at...Ch. 30 - One common type of cosmic ray is a proton...Ch. 30 - Prob. 15PQCh. 30 - Prob. 16PQCh. 30 - Prob. 17PQCh. 30 - A Two long, straight, parallel wires are shown in...Ch. 30 - Prob. 19PQCh. 30 - Two long, straight, parallel wires carry current...Ch. 30 - Prob. 21PQCh. 30 - Two long, straight wires carry the same current as...Ch. 30 - Prob. 23PQCh. 30 - A wire is bent in the form of a square loop with...Ch. 30 - Prob. 25PQCh. 30 - A Derive an expression for the magnetic field...Ch. 30 - Prob. 27PQCh. 30 - Prob. 28PQCh. 30 - Prob. 29PQCh. 30 - Prob. 30PQCh. 30 - Prob. 31PQCh. 30 - Prob. 32PQCh. 30 - Prob. 33PQCh. 30 - Prob. 34PQCh. 30 - Normally a refrigerator is not magnetized. If you...Ch. 30 - Prob. 36PQCh. 30 - Prob. 37PQCh. 30 - The magnetic field in a region is given by...Ch. 30 - Prob. 39PQCh. 30 - Prob. 40PQCh. 30 - Prob. 41PQCh. 30 - The velocity vector of a singly charged helium ion...Ch. 30 - Prob. 43PQCh. 30 - Can you use a mass spectrometer to measure the...Ch. 30 - In a laboratory experiment, a beam of electrons is...Ch. 30 - Prob. 46PQCh. 30 - Prob. 47PQCh. 30 - Prob. 48PQCh. 30 - A proton and a helium nucleus (consisting of two...Ch. 30 - Two ions are accelerated from rest in a mass...Ch. 30 - Prob. 51PQCh. 30 - Prob. 52PQCh. 30 - A rectangular silver strip is 2.50 cm wide and...Ch. 30 - For both sketches in Figure P30.56, there is a...Ch. 30 - A 1.40-m section of a straight wire oriented along...Ch. 30 - Professor Edward Ney was the founder of infrared...Ch. 30 - Prob. 59PQCh. 30 - A wire with a current of I = 8.00 A directed along...Ch. 30 - Prob. 61PQCh. 30 - The triangular loop of wire shown in Figure P30.62...Ch. 30 - Prob. 63PQCh. 30 - Consider the wires described in Problem 63. Find...Ch. 30 - Prob. 65PQCh. 30 - Prob. 66PQCh. 30 - A Three parallel current-carrying wires are shown...Ch. 30 - Prob. 68PQCh. 30 - Prob. 69PQCh. 30 - Prob. 70PQCh. 30 - Prob. 71PQCh. 30 - Prob. 72PQCh. 30 - A circular coil 15.0 cm in radius and composed of...Ch. 30 - Prob. 74PQCh. 30 - Prob. 75PQCh. 30 - Prob. 76PQCh. 30 - Prob. 77PQCh. 30 - Two long, straight, current-carrying wires run...Ch. 30 - Prob. 79PQCh. 30 - Prob. 80PQCh. 30 - Prob. 81PQCh. 30 - Prob. 82PQCh. 30 - Two infinitely long current-carrying wires run...Ch. 30 - Prob. 84PQCh. 30 - Prob. 85PQCh. 30 - Prob. 86PQCh. 30 - A charged particle with charge q and velocity...Ch. 30 - Prob. 88PQCh. 30 - Prob. 89PQCh. 30 - A mass spectrometer (Fig. 30.40, page 956)...Ch. 30 - Three long, current-carrying wires are parallel to...Ch. 30 - Prob. 92PQCh. 30 - A current-carrying conductor PQ of mass m and...Ch. 30 - A proton enters a region with a uniform electric...
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- Two infinitely long current-carrying wires run parallel in the xy plane and are each a distance d = 11.0 cm from the y axis (Fig. P30.83). The current in both wires is I = 5.00 A in the negative y direction. a. Draw a sketch of the magnetic field pattern in the xz plane due to the two wires. What is the magnitude of the magnetic field due to the two wires b. at the origin and c. as a function of z along the z axis, at x = y = 0? FIGURE P30.83arrow_forwardFigure P30.10 shows a circular current-carrying wire. Using the coordinate system indicated (with the z axis out of the page), state the direction of the magnetic field at points A and B.arrow_forwardA uniform magnetic field of magnitude is directed parallel to the z-axis. A proton enters the field with a velocity v=(4j+3k)106m/s and travels in a helical path with a radius of 5.0 cm. (a) What is the value of B? (b) What is the time required for one trip around the helix? (c) Where is the proton 5.0107s after entering the field?arrow_forward
- Why is the following situation impossible? Figure P28.46 shows an experimental technique for altering the direction of travel for a charged particle. A particle of charge q = 1.00 C and mass m = 2.00 1015 kg enters the bottom of the region of uniform magnetic field at speed = 2.00 105 m/s, with a velocity vector perpendicular to the field lines. The magnetic force on the particle causes its direction of travel to change so that it leaves the region of the magnetic field at the top traveling at an angle from its original direction. The magnetic field has magnitude B = 0.400 T and is directed out of the page. The length h of the magnetic field region is 0.110 m. An experimenter performs the technique and measures the angle at which the particles exit the top of the field. She finds that the angles of deviation are exactly as predicted. Figure P28.46arrow_forwardDetermine the initial direction of the deflection of charged particles as they enter the magnetic fields as shown in Figure P22.2. Figure P22.2.arrow_forwardAn electron in a TV CRT moves with a speed of 6.0107 m/s, in a direction perpendicular to Earth's field, which has a strength of 5.0105 T. (a) What strength electric field must be applied perpendicular to the Earth’s field to make the election moves in a straight line? (b) If this is done between plates separated by 1.00 cm, what is the voltage applied? (Note that TVs are usually surrounded by a ferromagnetic material to shield against external magnetic fields and avoid the need for such a collection,)arrow_forward
- A circular coil 15.0 cm in radius and composed of 145 tightly wound turns carries a current of 2.50 A in the counterclockwise direction, where the plane of the coil makes an angle of 15.0 with the y axis (Fig. P30.73). The coil is free to rotate about the z axis and is placed in a region with a uniform magnetic field given by B=1.35jT. a. What is the magnitude of the magnetic torque on the coil? b. In what direction will the coil rotate? FIGURE P30.73arrow_forwardA toroid has a major radius R and a minor radius r and is tightly wound with N turns of wire on a hollow cardboard torus. Figure P31.6 shows half of this toroid, allowing us to see its cross section. If R r, the magnetic field in the region enclosed by the wire is essentially the same as the magnetic field of a solenoid that has been bent into a large circle of radius R. Modeling the field as the uniform field of a long solenoid, show that the inductance of such a toroid is approximately L=120N2r2R Figure P31.6arrow_forwardA toroid with an inner radius of 20 cm and an outer radius of 22 cm is tightly wound with one layer of wire that has a diameter of 0.25 mm. (a) How many turns are there on the toroid? (b) If the current through the toroid windings is 2.0 A, what is the strength of the magnetic field at the center of the toroid?arrow_forward
- The Hall effect finds important application in the electronics industry. It is used to find the sign and density of the carriers of electric current in semiconductor chips. The arrangement is shown in Figure P22.66. A semiconducting block of thickness t and width d carries a current I in the x direction. A uniform magnetic field B is applied in the y direction. If the charge carriers are positive, the magnetic force deflects them in the z direction. Positive charge accumulates on the top surface of the sample and negative charge on the bottom surface, creating a downward electric field. In equilibrium, the downward electric force on the charge carriers balances the upward magnetic force and the carriers move through the sample without deflection. The Hall voltage ΔVH = Vc − Va between the top and bottom surfaces is measured, and the density of the charge carriers can be calculated from it. (a) Demonstrate that if the charge carriers are negative the Hall voltage will be negative. Hence, the Hall effect reveals the sign of the charge carriers, so the sample can be classified as p-type (with positive majority charge carriers) or n-type (with negative). (b) Determine the number of charge carriers per unit volume n in terms of I, t, B, ΔVH, and the magnitude q of the carrier charge. Figure P22.66arrow_forwardAn infinitely long wire carrying a current I is bent at a right angle as shown in Figure P22.30. Determine the magnetic field at point P, located a distance x from the corner of the wire. Figure P22.30arrow_forwardTwo long, straight wires are parallel and 25 cm apart. (a) If each wire carries a current of 50 A in the same direction, what is the magnetic force per meter exerted on each wire? (b) Does tire force pull the wires together or push them apart? (c) What happens if the currents flow in opposite directions?arrow_forward
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