Explanation Given Info: The inductance of the inductor is 0 ⋅ 380 H , the resistance of the resistor is 48 ⋅ 0 Ω , the emf of the battery is 18 ⋅ 0 V . At a time t switch S 1 is closed, the current in the circuit increasing at the rate of change of current is 7 ⋅ 20 A / s . Sketch the given circuit as follows, Refer figure 1, apply Kirchhoff’s voltage law for the circuit after the switch S 1 is closed by keeping switch S 2 open, as the current in the circuit increasing through the circuit, the indictor cannot be act as short circuit (for the steady state currents inductor will act as short circuit), therefore the loop equation is, ε − i R − L d i d t = 0 . (I) Formula to calculate the voltage across the resistor in the circuit is, v a b = V R = i R (II) i is the current through the resistor, R is the resistance of the resistor. Substitute the equation (II) in equation (I), ε − V R − L d i d t = 0 Rearrange the equation to find V R , V R = ε − L d i d t Substitute 18 ⋅ 0 V for ε , 0 ⋅ 380 H for L and 7 ⋅ 20 A / s for d i d t to find V R ,

14th Edition

ISBN: 9780133969290

Author: Hugh D. Young, Roger A. Freedman

Publisher: PEARSON

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Chapter 30, Problem 30.29E

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The voltage across the resistor (vab) after the switch S1 is closed.

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Chapter 30, Problem 30.28E

Chapter 30, Problem 30.30E

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The voltage across the resistor ( v a b ) after the switch S 1 is closed.

Solution Summary: The author calculates the voltage across the resistor after the switch S_1 is closed.

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The voltage across the resistor (vab) after the switch S1 is closed.

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Chapter 30 Solutions