Concept explainers
(a)
The height attained by the beanbag in the air.
(a)
Answer to Problem 76A
Explanation of Solution
Given:
A beanbag is thrown in the air and it took
Formula used:
Final velocity with constant acceleration can be obtained by:
Where,
The distance traveled by an object with a constant acceleration can be obtained by:
Here, d represents displacement, v represents velocity, t represents time and a is the acceleration.
Calculation:
Any object comes at momentarily rest at maximum height, thus the velocity of the beanbag at the maximum height will be 0. That is,
Acceleration acting on it will be due to gravity only in downwards direction. Thus,
Also, since the motion of the bag will be symmetric since uniform acceleration acts on it, thus time taken by bag to reach maximum height will be
Considering the upward motion of the bag, acceleration will be
Then, the maximum height attained in 1.1s will be:
Conclusion:
Thus, the maximum height attained bythe beanbag is
(b)
The initial velocity of the beanbag with which it was thrown in the air.
(b)
Answer to Problem 76A
Explanation of Solution
Given:
A beanbag is thrown in the air and it took 2.2s to reach its initial position.
Formula used:
Final velocity with constant acceleration is given by,
Where,
Calculation:
Any object comes at momentarily rest at maximum height, thus the velocity of the beanbag at the maximum height will be 0. That is,
Acceleration acting on it will be due to gravity only in downwards direction. Thus,
Also, since the motion of the bag will be symmetric since uniform acceleration acts on it, thus time taken by bag to reach maximum height will be
Considering the upward motion of the bag, acceleration will be
Conclusion:
Thus, the initial velocity with which the beanbag was thrown is
Chapter 3 Solutions
Glencoe Physics: Principles and Problems, Student Edition
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