COLLEGE PHYSICS-CONNECT ACCESS
COLLEGE PHYSICS-CONNECT ACCESS
5th Edition
ISBN: 9781260486834
Author: GIAMBATTISTA
Publisher: MCG
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Chapter 3, Problem 49P

(a)

To determine

To draw the initial and final velocity vectors.

(a)

Expert Solution
Check Mark

Answer to Problem 49P

The diagram of the initial and final velocity vectors is

COLLEGE PHYSICS-CONNECT ACCESS, Chapter 3, Problem 49P , additional homework tip  1

Explanation of Solution

Velocity is rate of change of displacement of an object. It is a vector and has both magnitude and direction. The initial and final velocity vectors of the person is drawn in figure 1.

COLLEGE PHYSICS-CONNECT ACCESS, Chapter 3, Problem 49P , additional homework tip  2

In figure, vi is the initial velocity vector. It has magnitude of 192 km/h and is directed along the north direction. vf is the final velocity vector. It has magnitude 240 km/h and is at angle 45° west of north.

Conclusion:

Therefore, the initial and final velocity vectors is drawn in figure 1.

(b)

To determine

The change in velocity.

(b)

Expert Solution
Check Mark

Answer to Problem 49P

The change in velocity is 170 km/h at 7° south of west .

Explanation of Solution

Take the positive x-axis to be directed along west direction and the positive y-axis to be directed along north direction.

Write the expression for the initial velocity vector.

  vi=192 km/h, north

Write the expression for the x component of vi .

  vix=0        (I)

Here, vix is the x component of vi .

Write the expression for the y component of vi .

  viy=192 km/h        (II)

Here, viy is the y component of vi .

Write the expression for the final velocity vector.

  vf=240 km/h, 45° west of north

Here, vf is the final velocity vector.

Write the expression for the x component of vf .

  vfx=(240 km/h)sin45°        (III)

Here, vfx is the x component of vi .

Write the expression for the y component of vf .

  vfy=(240 km/h)cos45°        (IV)

Here, vfy is the y component of vi

Write the equation for the x-component of the change in velocity.

  Δvx=vfxvix

Here, Δvx is the x-component of the change in velocity.

Put equations (I) and (III) in the above equation.

  Δvx=(240 km/h)sin45°0=(240 km/h)sin45°        (V)

Write the equation for the y-component of the change in velocity.

  Δvy=vfyviy

Here, Δvy is the y-component of the change in velocity.

Put equations (II) and (IV) in the above equation.

  Δvy=(240 km/h)cos45°192 km/h        (VI)

Write the equation for the magnitude of the change in velocity.

  Δv=(Δvx)2+(Δvy)2        (VII)

Here, Δv is the magnitude of the change in velocity.

Write the equation for the direction of the change in velocity.

  θ=tan1ΔvyΔvx        (VIII)

Here, θ is the angle the change in velocity makes with the x-axis.

Conclusion:

Put equations (V) and (VI) in equation (VII) to find Δv.

  Δv=((240 km/h)sin45°)2+((240 km/h)cos45°192 km/h)2=171.1 km/h170 km/h

Put equations (V) and (VI) in equation (VIII) to find θ.

  θ=tan1((240 km/h)cos45°192 km/h(240 km/h)sin45°)=7.4°7°

The negative sign shows that the angle is clockwise or the change in velocity is at 7° south of west.

Therefore, the change in velocity is 170 km/h at 7° south of west.

(c)

To determine

The average acceleration during the trip.

(c)

Expert Solution
Check Mark

Answer to Problem 49P

The average acceleration during the trip is 570km/h2 at 7° south of west .

Explanation of Solution

Write the equation for the magnitude of the average acceleration.

  aav=ΔvΔt        (IX)

Here, aav is the magnitude of the average acceleration and Δt is the time interval.

Conclusion:

Substitute 170 km/h for Δv and 3.0 h for Δt in equation (IX) to find aav.

  aav=170 km/h3.0 h=57 km/h2

The direction of acceleration will be the same as that of change in velocity.

Therefore, the average acceleration during the trip is 570km/h2 at 7° south of west.

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Chapter 3 Solutions

COLLEGE PHYSICS-CONNECT ACCESS

Ch. 3.3 - Prob. 3.6PPCh. 3.3 - Prob. 3.3BCPCh. 3.3 - Prob. 3.7PPCh. 3.3 - Prob. 3.3CCPCh. 3.4 - The wheels fall off Beatrice’s suitcase, so she...Ch. 3.4 - Prob. 3.9PPCh. 3.4 - Prob. 3.10PPCh. 3.4 - Prob. 3.11PPCh. 3.5 - Prob. 3.5CPCh. 3.5 - Prob. 3.12PPCh. 3.5 - Prob. 3.13PPCh. 3 - Prob. 1CQCh. 3 - Prob. 2CQCh. 3 - Prob. 3CQCh. 3 - Prob. 4CQCh. 3 - Prob. 5CQCh. 3 - Prob. 6CQCh. 3 - Prob. 7CQCh. 3 - Prob. 8CQCh. 3 - Prob. 9CQCh. 3 - Prob. 10CQCh. 3 - Prob. 11CQCh. 3 - Prob. 12CQCh. 3 - Prob. 13CQCh. 3 - Prob. 14CQCh. 3 - Prob. 15CQCh. 3 - Tell whether each of the following objects has a...Ch. 3 - Prob. 17CQCh. 3 - Prob. 18CQCh. 3 - Prob. 21CQCh. 3 - Prob. 1MCQCh. 3 - Prob. 2MCQCh. 3 - Prob. 3MCQCh. 3 - Prob. 4MCQCh. 3 - Prob. 5MCQCh. 3 - Prob. 6MCQCh. 3 - Prob. 7MCQCh. 3 - Prob. 8MCQCh. 3 - Multiple-Choice Questions 7–16. A jogger is...Ch. 3 - Prob. 10MCQCh. 3 - Prob. 11MCQCh. 3 - Prob. 12MCQCh. 3 - Prob. 14MCQCh. 3 - Prob. 15MCQCh. 3 - Prob. 16MCQCh. 3 - Prob. 17MCQCh. 3 - Prob. 18MCQCh. 3 - Prob. 19MCQCh. 3 - Prob. 20MCQCh. 3 - Prob. 21MCQCh. 3 - Prob. 22MCQCh. 3 - Prob. 23MCQCh. 3 - Prob. 24MCQCh. 3 - Prob. 25MCQCh. 3 - Prob. 26MCQCh. 3 - Prob. 27MCQCh. 3 - Prob. 28MCQCh. 3 - Prob. 29MCQCh. 3 - Prob. 30MCQCh. 3 - Prob. 31MCQCh. 3 - Prob. 32MCQCh. 3 - Prob. 33MCQCh. 3 - Prob. 34MCQCh. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Prob. 3PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Prob. 9PCh. 3 - Prob. 10PCh. 3 - You will be hiking to a lake with some of your...Ch. 3 - Prob. 12PCh. 3 - Prob. 13PCh. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 19PCh. 3 - Prob. 20PCh. 3 - Prob. 21PCh. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - Prob. 30PCh. 3 - Prob. 31PCh. 3 - Prob. 32PCh. 3 - Prob. 33PCh. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Prob. 43PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 51PCh. 3 - Prob. 53PCh. 3 - Prob. 54PCh. 3 - Prob. 55PCh. 3 - Prob. 56PCh. 3 - Prob. 57PCh. 3 - Prob. 59PCh. 3 - Prob. 60PCh. 3 - Prob. 61PCh. 3 - Prob. 62PCh. 3 - Prob. 63PCh. 3 - Prob. 64PCh. 3 - Prob. 65PCh. 3 - Prob. 66PCh. 3 - Prob. 67PCh. 3 - Prob. 68PCh. 3 - Prob. 69PCh. 3 - Prob. 70PCh. 3 - Prob. 71PCh. 3 - Prob. 72PCh. 3 - Prob. 73PCh. 3 - Prob. 74PCh. 3 - Prob. 75PCh. 3 - Prob. 76PCh. 3 - Prob. 77PCh. 3 - Prob. 78PCh. 3 - Prob. 79PCh. 3 - Prob. 80PCh. 3 - Prob. 82PCh. 3 - Prob. 83PCh. 3 - Prob. 84PCh. 3 - Prob. 86PCh. 3 - Prob. 87PCh. 3 - Prob. 88PCh. 3 - Prob. 89PCh. 3 - Prob. 91PCh. 3 - Prob. 92PCh. 3 - Prob. 93PCh. 3 - An elevator starts at rest on the ninth floor. At...Ch. 3 - Prob. 95PCh. 3 - Prob. 96PCh. 3 - Prob. 98PCh. 3 - Prob. 99PCh. 3 - Prob. 100PCh. 3 - Prob. 101PCh. 3 - Prob. 102PCh. 3 - Prob. 103PCh. 3 - Prob. 104PCh. 3 - Prob. 105PCh. 3 - Prob. 106PCh. 3 - Prob. 107PCh. 3 - Prob. 108PCh. 3 - Prob. 109PCh. 3 - Prob. 110PCh. 3 - Prob. 112PCh. 3 - Prob. 113PCh. 3 - Prob. 114PCh. 3 - Prob. 115PCh. 3 - Prob. 116PCh. 3 - Prob. 117PCh. 3 - Prob. 118PCh. 3 - Prob. 119PCh. 3 - Prob. 120PCh. 3 - Prob. 121PCh. 3 - Prob. 122PCh. 3 - Prob. 123PCh. 3 - Prob. 124PCh. 3 - Prob. 126P
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