COLLEGE PHYSICS-CONNECT ACCESS
COLLEGE PHYSICS-CONNECT ACCESS
5th Edition
ISBN: 9781260486834
Author: GIAMBATTISTA
Publisher: MCG
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 3, Problem 30P

(a)

To determine

The average speed of the trip.

(a)

Expert Solution
Check Mark

Answer to Problem 30P

The average speed of the trip is 102km/h .

Explanation of Solution

Write the expression for the average speed of the boat,

  va=v1t1+v2t2t1+t2        (I)

Here, va is the average speed, v1 is the first velocity, t1 is the time for which the speed is v1, v2 is the second velocity, t2 is the time for which the speed is v2.

Conclusion:

Substitute  20.0min for t1, 108km/h for v1 , 90.0km/h for v2 , and 10.0min for t2 in expression (I),

  va=(108km/h)(20.0min)+(90.0km/h)(10.0min)20.0min+10.0min=102km/h                                      

The average speed of the trip is 102km/h .

(b)

To determine

The average velocity of the trip.

(b)

Expert Solution
Check Mark

Answer to Problem 30P

The average velocity of the trip is 90.8km/h and directed 16.6° south of the west direction.

Explanation of Solution

Write the expression for the distance covered in west direction,

  d1=v1t1        (I)

Here, d1 is the distance, v1 is the first velocity, t1 is the time for which the speed is v1.

Write the expression for the distance covered in the direction towards 60.0° south west,

  d2=v2t2        (II)

Here, d2 is the distance, v2 is the first velocity, t2 is the time for which the speed is v2.

The figures 1 the total trip,

COLLEGE PHYSICS-CONNECT ACCESS, Chapter 3, Problem 30P

Write the formula for the x component of the displacement.

  dx=d1+d2cos240.0°        (III)

Here, dx is the displacement along x component

Write the formula for the y component of the displacement.

  dy=d2sin240.0°        (IV)

Here, dy is the displacement along y component

Write the formula for the magnitude of the displacement.

  |d|=dx2+dy2        (V)

Here, d  is the displacement

Write the formula for the angle made by the displacement vector.

  θ=tan1(dxdy)        (VI)

Here, θ  is the angle made by the velocity vector.

Write the expression for the average velocity

  |v|=dt        (VII)

Here v  is the velocity vector, and t  is the total time for the trip.

Conclusion:

Substitute  20.0min for t1, 108km/h for v1 in expression (I),

  d1=(108km/h)(20.0min)=(108km/h)(20.0min)(1h60min)=36.0km                                      

Substitute  90.0km/h for v2 , and 10.0min for t2 in expression (II)

  d2=(90.0km/h)(10.0min)=(90.0km/h)(10.0min)(1h60min)=15.0km

Substitute  36.0km for d1, 15.0km for d2 in expression (III)

  dx=36.0km+(15.0km)cos240.0°=43.5km

Substitute  15.0km for d2 in expression (IV)

  dy=(15.0km)sin240.0°=13.0km

Substitute  13.0km for dy , and 43.5km for dx in expression (V)

  |d|=(13.0km)2+(43.5km)2=45.5km

Substitute  13.0km for dy , and 43.5km for dx in expression (VI)

  θ=tan1(13.0km43.5km)=16.6°

Substitute  45.5km for d , and 30.0min for t in expression (VII)

  |v|=45.5km30.0min(1h60min)=90.8km/h

Thus, the average velocity of the trip is 90.8km/h and directed 16.6° south of the west direction.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Chapter 3 Solutions

COLLEGE PHYSICS-CONNECT ACCESS

Ch. 3.3 - Prob. 3.6PPCh. 3.3 - Prob. 3.3BCPCh. 3.3 - Prob. 3.7PPCh. 3.3 - Prob. 3.3CCPCh. 3.4 - The wheels fall off Beatrice’s suitcase, so she...Ch. 3.4 - Prob. 3.9PPCh. 3.4 - Prob. 3.10PPCh. 3.4 - Prob. 3.11PPCh. 3.5 - Prob. 3.5CPCh. 3.5 - Prob. 3.12PPCh. 3.5 - Prob. 3.13PPCh. 3 - Prob. 1CQCh. 3 - Prob. 2CQCh. 3 - Prob. 3CQCh. 3 - Prob. 4CQCh. 3 - Prob. 5CQCh. 3 - Prob. 6CQCh. 3 - Prob. 7CQCh. 3 - Prob. 8CQCh. 3 - Prob. 9CQCh. 3 - Prob. 10CQCh. 3 - Prob. 11CQCh. 3 - Prob. 12CQCh. 3 - Prob. 13CQCh. 3 - Prob. 14CQCh. 3 - Prob. 15CQCh. 3 - Tell whether each of the following objects has a...Ch. 3 - Prob. 17CQCh. 3 - Prob. 18CQCh. 3 - Prob. 21CQCh. 3 - Prob. 1MCQCh. 3 - Prob. 2MCQCh. 3 - Prob. 3MCQCh. 3 - Prob. 4MCQCh. 3 - Prob. 5MCQCh. 3 - Prob. 6MCQCh. 3 - Prob. 7MCQCh. 3 - Prob. 8MCQCh. 3 - Multiple-Choice Questions 7–16. A jogger is...Ch. 3 - Prob. 10MCQCh. 3 - Prob. 11MCQCh. 3 - Prob. 12MCQCh. 3 - Prob. 14MCQCh. 3 - Prob. 15MCQCh. 3 - Prob. 16MCQCh. 3 - Prob. 17MCQCh. 3 - Prob. 18MCQCh. 3 - Prob. 19MCQCh. 3 - Prob. 20MCQCh. 3 - Prob. 21MCQCh. 3 - Prob. 22MCQCh. 3 - Prob. 23MCQCh. 3 - Prob. 24MCQCh. 3 - Prob. 25MCQCh. 3 - Prob. 26MCQCh. 3 - Prob. 27MCQCh. 3 - Prob. 28MCQCh. 3 - Prob. 29MCQCh. 3 - Prob. 30MCQCh. 3 - Prob. 31MCQCh. 3 - Prob. 32MCQCh. 3 - Prob. 33MCQCh. 3 - Prob. 34MCQCh. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Prob. 3PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Prob. 9PCh. 3 - Prob. 10PCh. 3 - You will be hiking to a lake with some of your...Ch. 3 - Prob. 12PCh. 3 - Prob. 13PCh. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 19PCh. 3 - Prob. 20PCh. 3 - Prob. 21PCh. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - Prob. 30PCh. 3 - Prob. 31PCh. 3 - Prob. 32PCh. 3 - Prob. 33PCh. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Prob. 43PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 51PCh. 3 - Prob. 53PCh. 3 - Prob. 54PCh. 3 - Prob. 55PCh. 3 - Prob. 56PCh. 3 - Prob. 57PCh. 3 - Prob. 59PCh. 3 - Prob. 60PCh. 3 - Prob. 61PCh. 3 - Prob. 62PCh. 3 - Prob. 63PCh. 3 - Prob. 64PCh. 3 - Prob. 65PCh. 3 - Prob. 66PCh. 3 - Prob. 67PCh. 3 - Prob. 68PCh. 3 - Prob. 69PCh. 3 - Prob. 70PCh. 3 - Prob. 71PCh. 3 - Prob. 72PCh. 3 - Prob. 73PCh. 3 - Prob. 74PCh. 3 - Prob. 75PCh. 3 - Prob. 76PCh. 3 - Prob. 77PCh. 3 - Prob. 78PCh. 3 - Prob. 79PCh. 3 - Prob. 80PCh. 3 - Prob. 82PCh. 3 - Prob. 83PCh. 3 - Prob. 84PCh. 3 - Prob. 86PCh. 3 - Prob. 87PCh. 3 - Prob. 88PCh. 3 - Prob. 89PCh. 3 - Prob. 91PCh. 3 - Prob. 92PCh. 3 - Prob. 93PCh. 3 - An elevator starts at rest on the ninth floor. At...Ch. 3 - Prob. 95PCh. 3 - Prob. 96PCh. 3 - Prob. 98PCh. 3 - Prob. 99PCh. 3 - Prob. 100PCh. 3 - Prob. 101PCh. 3 - Prob. 102PCh. 3 - Prob. 103PCh. 3 - Prob. 104PCh. 3 - Prob. 105PCh. 3 - Prob. 106PCh. 3 - Prob. 107PCh. 3 - Prob. 108PCh. 3 - Prob. 109PCh. 3 - Prob. 110PCh. 3 - Prob. 112PCh. 3 - Prob. 113PCh. 3 - Prob. 114PCh. 3 - Prob. 115PCh. 3 - Prob. 116PCh. 3 - Prob. 117PCh. 3 - Prob. 118PCh. 3 - Prob. 119PCh. 3 - Prob. 120PCh. 3 - Prob. 121PCh. 3 - Prob. 122PCh. 3 - Prob. 123PCh. 3 - Prob. 124PCh. 3 - Prob. 126P
Knowledge Booster
Background pattern image
Physics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Text book image
College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
Text book image
University Physics (14th Edition)
Physics
ISBN:9780133969290
Author:Hugh D. Young, Roger A. Freedman
Publisher:PEARSON
Text book image
Introduction To Quantum Mechanics
Physics
ISBN:9781107189638
Author:Griffiths, David J., Schroeter, Darrell F.
Publisher:Cambridge University Press
Text book image
Physics for Scientists and Engineers
Physics
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Text book image
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:9780321820464
Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:Addison-Wesley
Text book image
College Physics: A Strategic Approach (4th Editio...
Physics
ISBN:9780134609034
Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:PEARSON
Kinematics Part 3: Projectile Motion; Author: Professor Dave explains;https://www.youtube.com/watch?v=aY8z2qO44WA;License: Standard YouTube License, CC-BY