Organic Chemistry
Organic Chemistry
12th Edition
ISBN: 9781118875766
Author: T. W. Graham Solomons, Craig B. Fryhle, Scott A. Snyder
Publisher: WILEY
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Chapter 3, Problem 46P
Interpretation Introduction

Interpretation:

The dash structural formula of DMF showing unshared electron pairs is to be drawn. The most important resonance form of DMF is to be predicted. On the basis of Lewis acid–base considerations, the greater reactivity of nucleophile in DMF is to be explained.

Concept introduction:

Electrophiles are electron-deficient species, which has positive or partially positive charge. Lewis acids are electrophiles, which accept electron pair.

Nucleophiles are electron-rich species, which has negative or partially negative charge. Lewis bases are nucleophiles, which donate electron pair.

In dash line formula, all the symbols of atoms and the bonding electron pair lines are shown.

Resonating structures are structures that have more than one equivalent Lewis structures for the same molecule or ion.

Resonance is the phenomenon of describing delocalized electrons in certain molecular ions through various forms or resonance structures and the forms contributing to the hybrid form.

The rules for drawing resonance structures are as follows:

Only nonbonding electron pairs and pi electrons can participate in conjugation in the formation of various resonating structures.

The single bonds present in the molecule do not break or form in the resonance structures.

The placement of atoms present in the molecule remains fixed.

The octet of all atoms is completely filled.

According to the convention, these structures are connected by double-headed arrows ().

Movement of electrons (whether bonding or lone pair) is indicated by curved arrows.

Curved arrows are used to represent the direction of the flow of electrons in a reaction mechanism.

Curved arrows are drawn in such a way that they point from the source of an electron pair toward the atom, which receives the electron pair.

The direction of flow of electrons is always from a high electron density site to a low electron density site.

Curved arrows never represent the movement of atoms.

The movement of electrons shown by the curved arrows should not violate the octet rule for the elements, which are present in the second row of the periodic table.

The more stable structure is the structure that has more covalent bonds.

Stability of resonating structures is decreased by charge separation.

The structures that contain complete valence shells are more stable.

Reactivity of a molecule depends on the solvation of nucleophilic anions.

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Consider Lewis formulas A, B, and C:(a) Are A, B, and C constitutional isomers, or are they resonance contributors? (b) Which have a negatively charged carbon? (c) Which have a positively charged carbon? (d) Which have a positively charged nitrogen? (e) Which have a negatively charged nitrogen? (f) What is the net charge on each? (g) Which is a more stable structure, A or B? Why? (h) Which is a more stable structure, B or C? Why? (i) What is the CNN geometry in each according to VSEPR?
The curved arrow notation introduced in Section 1.6B is a powerful method used by organic chemists to show the movement of electrons not only in resonance structures, but also in chemical reactions.Because each curved arrow shows the movement of two electrons, following the curved arrows illustrates what bonds are broken and formed in a reaction. Consider the following three-step process. (a) Add curved arrows in Step [1] to show the movement of electrons. (b) Use the curved arrows drawn in Step [2] to identify the structure of X. X is converted in Step [3] to phenol and HCl.
For each of the following structures,1. Draw a Lewis structure; fill in any nonbonding electrons.2. Calculate the formal charge on each atom other than hydrogen.(a) CH3NO(nitromethane)(b) (CH3)3NO(trimethylamine oxide)(c) [N3]-(azide ion)(d) [(CH3)3O]+ (e) CH3NC (f) (CH3)4NBr

Chapter 3 Solutions

Organic Chemistry

Ch. 3 - Prob. 11PPCh. 3 - Prob. 12PPCh. 3 - Prob. 13PPCh. 3 - Prob. 14PPCh. 3 - PRACTICE PROBLEM 3.15 Nitro groups have a large...Ch. 3 - PRACTICE PROBLEM 3.16 Your laboratory instructor...Ch. 3 - Prob. 17PPCh. 3 - Prob. 18PPCh. 3 - Prob. 19PPCh. 3 - What is the conjugate base of each of the...Ch. 3 - List the bases you gave as answers to Problem 3.20...Ch. 3 - 3.22 What is the conjugate acid of each of the...Ch. 3 - List the acids you gave as answers to Problem 3.22...Ch. 3 - Rank the following in order of increasing acidity.Ch. 3 - Without consulting tables, select the stronger...Ch. 3 - Designate the Lewis acid and Lewis base in each of...Ch. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Write an equation, using the curved-arrow...Ch. 3 - 3.30 What reaction will take place if ethyl...Ch. 3 - 3.31 (a) The of formic acid. What is the? (b)...Ch. 3 - Acid HA has pKa=20; acid HB has pKa=10. (a) Which...Ch. 3 - Prob. 33PCh. 3 - 3.34 (a) Arrange the following compounds in order...Ch. 3 - 3.35 Arrange the following compounds in order of...Ch. 3 - 3.36 Arrange the following in order of increasing...Ch. 3 - Prob. 37PCh. 3 - 3.38 Supply the curved arrows necessary for the...Ch. 3 - Glycine is an amino acid that can be obtained from...Ch. 3 - 3.40 Malonic acid, , is a diprotic acid. The for...Ch. 3 - 3.41 The free-energy change, , for the ionization...Ch. 3 - 3.42 At the enthalpy change, , for the ionization...Ch. 3 - The compound at right has (for obvious reasons)...Ch. 3 - 3.44. (a) Given the above sequence of...Ch. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - 3.47 As noted in Table 3.1, the of acetone, , is...Ch. 3 - Formamide (HCONH2) has a pKa of approximately 25....Ch. 3 - List all the chemical species likely to be present...Ch. 3 - Prob. 2LGPCh. 3 - Prob. 3LGPCh. 3 - Prob. 4LGP
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