Fundamentals of Electromagnetics with Engineering Applications
1st Edition
ISBN: 9780470105757
Author: Stuart M. Wentworth
Publisher: Wiley, John & Sons, Incorporated
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Textbook Question
Chapter 3, Problem 3.42P
Modify MATLAB 3.4 to find the differential force acting from each individual differential segment on the loop. Plot this force against the phi location of the segment.
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Chapter 3 Solutions
Fundamentals of Electromagnetics with Engineering Applications
Ch. 3 - Find AB for the following: A=2ax3ay+4az,B=5ay1az...Ch. 3 - Prob. 3.2PCh. 3 - Given the vertices of a triangle...Ch. 3 - A segment of conductor on the z–axis extends...Ch. 3 - Prob. 3.5PCh. 3 - Prob. 3.6PCh. 3 - A square conductive loop in the shape 10.0 cm is...Ch. 3 - A conductive loop in the x–y plane is bounded by...Ch. 3 - How close do you have to be to the middle of a...Ch. 3 - For the ring of current described in MATLAB 3.2,...
Ch. 3 - A solenoid has 200 turns, is 10.0 cm long, and has...Ch. 3 - For the solenoid of the previous problem, plot the...Ch. 3 - Prob. 3.13PCh. 3 - Two infinite extent current sheets exist at z=2.0m...Ch. 3 - An infinite extent current sheet with K=6.0ayA/m...Ch. 3 - Given the field H=3y2ax, find the current passing...Ch. 3 - Given a 3.0–mm–radius solid wire centered on...Ch. 3 - Given a 2.0–cm–radius solid wire centered on...Ch. 3 - An infinitesimally thin metallic cylindrical shell...Ch. 3 - A cylindrical pipe with a 1.0–cm wall thickness...Ch. 3 - Prob. 3.21PCh. 3 - Prob. 3.22PCh. 3 - Consider the toroid in Figure 3.55 that is tightly...Ch. 3 - Find A for the following fields: A=3xy2/zax...Ch. 3 - Find J at (3m,60,4m) for H=(z/sin)a(2/cos)azA/mCh. 3 - Suppose H=y2ax+x2ayA/m .(a) Calculate HdL around...Ch. 3 - Prob. 3.27PCh. 3 - Suppose you have the field H=rcosaA/m. Now...Ch. 3 - Prob. 3.29PCh. 3 - Suppose an infinite extent sheet of current with...Ch. 3 - Prob. 3.31PCh. 3 - A 1.0nC charge with velocity 100.m/s in the y...Ch. 3 - A 1.0nC charge with velocity 100.m/s in the z...Ch. 3 - A 10.nC charged particle has a velocity...Ch. 3 - What electric field is required so that the...Ch. 3 - An electron (with rest mass Me=9.111031kg and...Ch. 3 - Prob. 3.37PCh. 3 - Prob. 3.38PCh. 3 - Prob. 3.39PCh. 3 - Suppose you have a pair of parallel lines each...Ch. 3 - In Figure 3.57, a 2.0-A line of current is shown...Ch. 3 - Modify MATLAB 3.4 to find the differential force...Ch. 3 - Prob. 3.43PCh. 3 - A square loop of 1.0-A current of side 4.0 cm is...Ch. 3 - A current sheet K=100axA/m exists at z=2.0cm. A...Ch. 3 - Prob. 3.46PCh. 3 - Prob. 3.47PCh. 3 - A solid nickel wire of diameter 2.0 mm evenly...Ch. 3 - Prob. 3.49PCh. 3 - The plane y = O separates two magnetic media....Ch. 3 - Prob. 3.52PCh. 3 - Prob. 3.53PCh. 3 - Prob. 3.54PCh. 3 - Prob. 3.55PCh. 3 - Prob. 3.56PCh. 3 - Prob. 3.57PCh. 3 - Prob. 3.58PCh. 3 - Prob. 3.59PCh. 3 - Prob. 3.60PCh. 3 - Prob. 3.61PCh. 3 - In Figure 3.59, a 2.0-cm-diameter toroidal core...Ch. 3 - Suppose the 2.0-cm-diameter core of the toroid in...Ch. 3 - Prob. 3.64PCh. 3 - Consider a 1.0-mm air gap in Figure 3.49a. The...
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- 3 Biot-Savart for Curved Wire A segment of a closed current loop is shown in the following figure. Compute the magnetic field at the center of the semi-circle due to the straight and curved segments shown. b (Technically, to use the Biot-Savart law for currents in a wire, the current must be constant, and the wire must form a closed loop. As a result, there will be a contribution to the magnetic field at the origin due to the parts of the closed loop that are not shown. However, here we assume that the not- shown part of the loop is far enough away that they can be neglected.)arrow_forward8) the armature resistance of dc machines with number of poles > 2 is larger when the machine is: wave wound lap wound None of the abovearrow_forwardA three-legged ferromagnetic magnetic core with the coil dimensions shown below has a of 500 turns wrapped around the right leg. The core relative permeability is 4000 times, The magnetic flux in the left leg of the core has a value of 40 mWb. The center leg has an air gap of 0.8 mm, its fringing effect is neglected. Draw the corresponding magnetic circuit and find the values of the coil current i, and the flux in each leg of the core. cm 10 cm, 25cm 25 cm 10 cm 10 cm 25 cm 0.8 mm 500 turns 10 cm Core depth = 10 cmarrow_forward
- Explain deterministic and random signalsarrow_forwardThere are 6 equations that govern electromagnetism. Write them out in CGS and differential form (except for one in integral form). Assume the magnetostatic case.arrow_forwardScenario: Consider a magnetic circuit with a mean length of 0.6 m. A 4x10? turn coil is wound around the left-hand limb. The magnetic circuit is made from silicon steel; core effects may not be ignored. The cross section is uniform and there is a 1.1 mm air gap in the circuit. Find the current required in the coil to give a flux density of 1.40 T in the air gap. The number of turns in the coil is The magnetic field intensity in the core, He. is A-t/m. The current in the coil, i, is A. (keep two decimals)arrow_forward
- Within magnetic circuits, most of the structures are composed of a high-quality material permeability, which has the functionality to cause the magnetic flux to be directed to paths" Pre" delimited by this material structure. Within the electromechanical energy conversion processesw e find the application of magnetic materials in a multitude of devices and devices, and knowt he concepts that govern the operation of an apparatus or machine are part of the study regarding conversione lectromechanical energy. We know that transformers and electrical machines use materialsf erromagnetics to direct the magnetic flux and shape this “pre-established” magnetic field.K nowing this, you, engineer (a), should design a magnetic circuit consisting of a stack of ringsw ith a height of 2 cm wrapped around 65 turns. Consider an air gap area of 0.2 cm. Rings have radiusi nternal of 3.4 cm and the outer radius of couples rings is 4 cm. Suppose the magnetic flux present without materialf erromagnetic…arrow_forwardTopic Electrical Machines - Magnetic & E... For a coil, each turn faces (2t4 – t³ – 2t) milliwebers of flux. The value of induced EMF in coil for 100 turns coil at 2 sec is, (in Volts).arrow_forwardThe applied MMF to a simple magnetic circuit is 350AT. It was found that the resulting magnetic field denstiy is 0.7 Wb/m². The average length of this magnetic circuit is 1.64ft and its cross sectional area is 4cm². What is the reluctance (in AT/Wb) of the magnetic material of the core?arrow_forward
- A ferromagnetic core with a relative permeability of 1500 is shown in the following figure. The depth of the core is 5 cm. Because of fringing effects, the effective area of the air gaps is 5 percent larger than their physical size. If there are 300 turns in the coil wrapped around the center leg of the core, and if the current in the coil is 1.25 A, find the magnetic flux and the field density in all three legs of the core, as well as the magnetic flux and flux density in the two air gaps.arrow_forward2-The Magneto motive force of a steel-ring of 25 cm mean diameter- If it is wound uniformly with 700 turns of wire carrying a current of 2 amp. a-1500 AT b-2000 AT c-1800 AT d-1400 AT 3-The self-inductance cocfficient of a d.c. electromagnet- whose field winding is wound with 960 turns and has resistance of 50 2 when the exciting voltages is 230 V and the magnetic flux linking the coil is 0.005 Wb. a-10.43mH b-10.43H c-1.043H d-0.1043 H 4- An iron rod, 2 cm in diameter and 20 cm long is bent into a closed ring and is wound with 3000 turns of wire. It is found that when a current of 0.5 A is passed through this coil, the flux density in the coil is 0.5 Wb/m2. The magnetic field intensity of it -- a-300AT/m b-30AT/m c-3000AT/m d-300AT/cmarrow_forwardConsider a ferromagnetic ring (nucleus) that has a mean circumference of 40 cm, 300coiled copper turns and a sectional area of 5 cm2. A current of 2 is appliedA to winding, producing a flux of 1.5 mWb.Determine the permeability of the core material.Determine the relative permeability of the core material.If the ferromagnetic ring has an air gap of 2 mm. Find the required MMFso that the flux density in the gap is 0.5 T.arrow_forward
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