Chemistry
Chemistry
4th Edition
ISBN: 9780393919370
Author: Thomas R. Gilbert
Publisher: NORTON
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Chapter 3, Problem 3.36QP

(a)

Interpretation Introduction

Interpretation: The substance which contains greater number of ions from the given pairs of compound is to be selected.

Concept introduction: The mole is unit specially discovered for the atoms or molecules due to extreme small size and large numbers. One mole is defined as the amount of the substance which contains exactly the same number of particles as in 12g of carbon-12 isotope. One mole of anything consists of NA number of things. This number is known as Avogadro number (NA) and is numerically equal to 6.023×1023 . Every molecular formula contains exactly the same number of moles of elements as given the stoichiometric ratio in the molecular formula.

To determine: The substance which contains greater number of ions from the given pairs of compound.

(a)

Expert Solution
Check Mark

Answer to Problem 3.36QP

Solution

The substance which contains greater number of ions from the given pairs of compound is KCl .

Explanation of Solution

Explanation

Given

The given pair of compound is NaBr or KCl .

To calculate the number of ions in the given pair of compounds the mass of both the compound is assumed to be 100g . The molar mass of both the compounds is given as,

NaBr=102.89g/molKCl=74.54g/mol

Now, for the assumed mass, the moles of both the compound is calculated by the formula,

n=mM

Where,

  • n is the number of moles.
  • m is the given mass of the molecule.
  • M is the molar mass of the molecule.

Substitute the values in the above formula to calculate the moles.

For NaBr compound,

n=mMn=100g102.89g/moln=0.971mol

For KCl compound,

n=mMn=100g74.54g/moln=1.34mol

The compound NaBr contains two ions that are Na+ and Br . Therefore, one mole of NaBr contains one mole of Na+ and one mole of Br that is two moles of ions.

The compound KCl contains two ions that are K+ and Cl . Therefore, one mole of KCl contains one mole of K+ and one mole of Cl that is two moles of ions.

As already given in concept that one mole of anything contains the NA number of things. Therefore, for the calculated moles, the number of ions, Nions is calculated by the formula,

Nions=2n×NA

Substitute the values for NaBr compound,

Nions=2n×NANions=2×0.927×6.023×1023Nions=11.708×1023Ions

Substitute the values for KCl compound,

Nions=2n×NANions=2×1.34×6.023×1023Nions=16.14×1023Ions

The calculated values of number of ions clearly reveals that KCl compound contains more number of ions than NaBr .

(b)

Interpretation Introduction

To determine: The substance which contains greater number of ions from the given pairs of compound.

(b)

Expert Solution
Check Mark

Answer to Problem 3.36QP

Solution

The substance which contains greater number of ions from the given pairs of compound is NaCl .

Explanation of Solution

Explanation

Given

The given pair of compound is NaCl or MgCl2 .

To calculate the number of ions in the given pair of compounds the mass of both the compound is assumed to be 100g . The molar mass of both the compounds is given as,

NaCl58.43g/molMgCl295.2g/mol

Now, for the assumed mass, the moles of both the compound is calculated by the formula,

n=mM

Substitute the values in the above formula to calculate the moles.

For NaCl compound,

n=mMn=100g52.43g/moln=1.71mol

For MgCl2 compound,

n=mMn=100g95.2g/moln=1.05mol

The compound NaCl contains two ions that are Na+ and Cl . Therefore, one mole of NaCl contains one mole of Na+ and one mole of Cl that is two moles of ions.

As already given in concept that one mole of anything contains the NA number of things. Therefore, for the calculated moles of NaCl , the number of ions, Nions is calculated by the formula,

Nions=2n×NA

Substitute the values for NaCl compound,

Nions=2n×NANions=2×1.71×6.023×1023Nions=20.6×1023Ions

The compound MgCl2 contains three ions that are Mg+ and Cl . Therefore, one mole of MgCl2 contains one mole of Mg+ and two mole of Cl that is three moles of ions.

For the calculated moles of MgCl2 , the number of ions, Nions is calculated by the formula,

Nions=3n×NA

Substitute the values for MgCl2 compound,

Nions=3n×NANions=3×1.05×6.023×1023Nions=18.97×1023Ions

The calculated values of number of ions clearly reveals that NaCl compound contains more number of ions than MgCl2 .

(c)

Interpretation Introduction

To determine: The substance which contains greater number of ions from the given pairs of compound.

(c)

Expert Solution
Check Mark

Answer to Problem 3.36QP

Solution

The substance which contains greater number of ions from the given pairs of compound is Li2CO3 .

Explanation of Solution

Explanation

Given

The given pair of compound is BaCl2 or Li2CO3 .

To calculate the number of ions in the given pair of compounds the mass of both the compound is assumed to be 100g . The molar mass of both the compounds is given as,

BaCl2208.2g/molLi2CO373.887g/mol

Now, for the assumed mass, the moles of both the compound is calculated by the formula,

n=mM

Substitute the values in the above formula to calculate the moles.

For BaCl2 compound,

n=mMn=100g208.2g/moln=0.48mol

For Li2CO3 compound,

n=mMn=100g73.887g/moln=1.35mol

The compound BaCl2 contains three ions that are Ba+ and Cl . Therefore, one mole of BaCl2 contains one mole of Ba+ and two moles of Cl that is three moles of ions.

As already given in concept that one mole of anything contains the NA number of things. Therefore, for the calculated moles of BaCl2 , the number of ions, Nions is calculated by the formula,

Nions=3n×NA

Substitute the values for BaCl2 compound,

Nions=3n×NANions=3×0.48×6.023×1023Nions=8.67×1023Ions

For the calculated moles of Li2CO3 , the number of ions, Nions is calculated as,

Nions=3n×NANions=3×1.35×6.023×1023Nions=24.39×1023Ions

The calculated values of number of ions clearly reveals that Li2CO3 compound contains more number of ions than BaCl2 .

Conclusion

  1. a) The substance which contains greater number of ions from the given pairs of compound is KCl .
  2. b) The substance which contains greater number of ions from the given pairs of compound is NaCl .
  3. c) The substance which contains greater number of ions from the given pairs of compound is Li2CO3

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Chapter 3 Solutions

Chemistry

Ch. 3.5 - Prob. 12PECh. 3.5 - Prob. 13PECh. 3.6 - Prob. 14PECh. 3.6 - Prob. 16PECh. 3.7 - Prob. 17PECh. 3.8 - Prob. 18PECh. 3.8 - Prob. 19PECh. 3.9 - Prob. 20PECh. 3.9 - Prob. 21PECh. 3.9 - Prob. 22PECh. 3.9 - Prob. 23PECh. 3 - Prob. 3.1VPCh. 3 - Prob. 3.2VPCh. 3 - Prob. 3.3VPCh. 3 - Prob. 3.4VPCh. 3 - Prob. 3.5VPCh. 3 - Prob. 3.6VPCh. 3 - Prob. 3.7VPCh. 3 - Prob. 3.8VPCh. 3 - Prob. 3.9QPCh. 3 - Prob. 3.10QPCh. 3 - Prob. 3.11QPCh. 3 - Prob. 3.12QPCh. 3 - Prob. 3.13QPCh. 3 - Prob. 3.14QPCh. 3 - Prob. 3.15QPCh. 3 - Prob. 3.16QPCh. 3 - Prob. 3.17QPCh. 3 - Prob. 3.18QPCh. 3 - Prob. 3.19QPCh. 3 - Prob. 3.20QPCh. 3 - Prob. 3.21QPCh. 3 - Prob. 3.22QPCh. 3 - Prob. 3.23QPCh. 3 - Prob. 3.24QPCh. 3 - Prob. 3.25QPCh. 3 - Prob. 3.26QPCh. 3 - Prob. 3.27QPCh. 3 - Prob. 3.28QPCh. 3 - Prob. 3.29QPCh. 3 - Prob. 3.30QPCh. 3 - Prob. 3.31QPCh. 3 - Prob. 3.32QPCh. 3 - Prob. 3.33QPCh. 3 - Prob. 3.34QPCh. 3 - Prob. 3.35QPCh. 3 - Prob. 3.36QPCh. 3 - Prob. 3.37QPCh. 3 - Prob. 3.38QPCh. 3 - Prob. 3.39QPCh. 3 - Prob. 3.40QPCh. 3 - Prob. 3.41QPCh. 3 - Prob. 3.42QPCh. 3 - Prob. 3.43QPCh. 3 - Prob. 3.44QPCh. 3 - Prob. 3.45QPCh. 3 - Prob. 3.46QPCh. 3 - Prob. 3.47QPCh. 3 - Prob. 3.48QPCh. 3 - Prob. 3.49QPCh. 3 - Prob. 3.50QPCh. 3 - Prob. 3.51QPCh. 3 - Prob. 3.52QPCh. 3 - Prob. 3.53QPCh. 3 - Prob. 3.54QPCh. 3 - Prob. 3.55QPCh. 3 - Prob. 3.56QPCh. 3 - Prob. 3.57QPCh. 3 - Prob. 3.58QPCh. 3 - Prob. 3.59QPCh. 3 - Prob. 3.60QPCh. 3 - Prob. 3.61QPCh. 3 - Prob. 3.62QPCh. 3 - Prob. 3.63QPCh. 3 - Prob. 3.64QPCh. 3 - Prob. 3.65QPCh. 3 - Prob. 3.66QPCh. 3 - Prob. 3.67QPCh. 3 - Prob. 3.68QPCh. 3 - Prob. 3.69QPCh. 3 - Prob. 3.70QPCh. 3 - Prob. 3.71QPCh. 3 - Prob. 3.72QPCh. 3 - Prob. 3.73QPCh. 3 - Prob. 3.74QPCh. 3 - Prob. 3.75QPCh. 3 - Prob. 3.76QPCh. 3 - Prob. 3.77QPCh. 3 - Prob. 3.78QPCh. 3 - Prob. 3.79QPCh. 3 - Prob. 3.80QPCh. 3 - Prob. 3.81QPCh. 3 - Prob. 3.82QPCh. 3 - Prob. 3.83QPCh. 3 - Prob. 3.84QPCh. 3 - Prob. 3.85QPCh. 3 - Prob. 3.86QPCh. 3 - Prob. 3.87QPCh. 3 - Prob. 3.88QPCh. 3 - Prob. 3.89QPCh. 3 - Prob. 3.90QPCh. 3 - Prob. 3.91QPCh. 3 - Prob. 3.92QPCh. 3 - Prob. 3.93QPCh. 3 - Prob. 3.94QPCh. 3 - Prob. 3.95QPCh. 3 - Prob. 3.96QPCh. 3 - Prob. 3.97QPCh. 3 - Prob. 3.98QPCh. 3 - Prob. 3.99QPCh. 3 - Prob. 3.100QPCh. 3 - Prob. 3.101QPCh. 3 - Prob. 3.102QPCh. 3 - Prob. 3.103QPCh. 3 - Prob. 3.104QPCh. 3 - Prob. 3.105QPCh. 3 - Prob. 3.106QPCh. 3 - Prob. 3.107QPCh. 3 - Prob. 3.108QPCh. 3 - Prob. 3.109QPCh. 3 - Prob. 3.110QPCh. 3 - Prob. 3.111QPCh. 3 - Prob. 3.112QPCh. 3 - Prob. 3.113QPCh. 3 - Prob. 3.114QPCh. 3 - Prob. 3.115QPCh. 3 - Prob. 3.116QPCh. 3 - Prob. 3.117APCh. 3 - Prob. 3.118APCh. 3 - Prob. 3.119APCh. 3 - Prob. 3.120APCh. 3 - Prob. 3.121APCh. 3 - Prob. 3.122APCh. 3 - Prob. 3.123APCh. 3 - Prob. 3.124APCh. 3 - Prob. 3.125APCh. 3 - Prob. 3.126APCh. 3 - Prob. 3.127APCh. 3 - Prob. 3.128APCh. 3 - Prob. 3.129APCh. 3 - Prob. 3.130APCh. 3 - Prob. 3.131APCh. 3 - Prob. 3.132APCh. 3 - Prob. 3.133APCh. 3 - Prob. 3.134APCh. 3 - Prob. 3.135APCh. 3 - Prob. 3.136APCh. 3 - Prob. 3.137APCh. 3 - Prob. 3.138APCh. 3 - Prob. 3.139APCh. 3 - Prob. 3.140APCh. 3 - Prob. 3.141APCh. 3 - Prob. 3.142APCh. 3 - Prob. 3.143APCh. 3 - Prob. 3.144AP
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