Chemistry
Chemistry
4th Edition
ISBN: 9780393919370
Author: Thomas R. Gilbert
Publisher: NORTON
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Chapter 3, Problem 3.19QP

(a)

Interpretation Introduction

Interpretation: The atoms of titanium in 0.125mole of each of the given compound are to be calculated.

Concept introduction: A mole of a substance is the quantity of a substance which contains the same number of particles as the number of carbon atoms in exactly 12 grams for the carbon-12 isotopes. A mole of particles contains Avogadro’s number (6.022×1023) of particles. The number of atoms in a substance is equal to the product of moles and Avogadro’s number.

To determine: The atoms of titanium in 0.125mole of ilmenite, FeTiO3 .

(a)

Expert Solution
Check Mark

Answer to Problem 3.19QP

Solution

The number of atoms of titanium in 0.125mole of FeTiO3 is 7.53×1022atoms_ .

Explanation of Solution

Explanation

Given

One mole ilmenite contains Avogadro’s number of molecules of ilmenite. Therefore, one mole of ilmenite is equivalent to 6.022×1023 molecules of ilmenite.

So, 1molFeTiO3=6.022×1023moleculesFeTiO3 .

One molecule of FeTiO3 contains one atom of Fe , one atom of Ti and three atoms of O .

The number of titanium atoms in 0.125mole of FeTiO3 is calculated by using the formula,

N=n×NA×numberofTiatomsinamolecule

Where,

  • N is the number of atoms.
  • NA is the Avogadro’s number of atoms.
  • n is the number of moles.

Substitute the values of n and NA in the above formula to calculate the number of titanium atoms.

N=0.125mole×6.022×1023molecules/mole×1Tiatom1moleculeFeTiO3=0.125×6.022×1023×1atoms=7.53×1022atoms_

Hence, the number of atoms of titanium in 0.125mole of FeTiO3 is 7.53×1022atoms_ .

(b)

Interpretation Introduction

To determine: The atoms of titanium in 0.125mole of titanium (IV) chloride.

(b)

Expert Solution
Check Mark

Answer to Problem 3.19QP

Solution

The number of atoms of titanium in 0.125mole of TiCl4 is 7.53×1022atoms_ .

Explanation of Solution

Explanation

Given

One mole titanium (IV) chloride (TiCl4) contains Avogadro’s number of molecules of ilmenite. Therefore, one mole of TiCl4 is equivalent to 6.022×1023 molecules of TiCl4 .

So, 1molTiCl4=6.022×1023moleculesTiCl4 .

One molecule of TiCl4 contains one atom of Ti and four atoms of Cl .

The number of titanium atoms in 0.125mole of TiCl4 is calculated by using the formula,

N=n×NA×numberofTiatomsinamolecule

Where,

  • N is the number of atoms.
  • NA is the Avogadro’s number of atoms.
  • n is the number of moles.

Substitute the values of n and NA in the above formula to calculate the number of titanium atoms.

N=0.125mole×6.022×1023molecules/mole×1Tiatom1moleculeTiCl4=0.125×6.022×1023×1atoms=7.53×1022atoms_

Hence, the number of atoms of titanium in 0.125mole of TiCl4 is 7.53×1022atoms_ .

(c)

Interpretation Introduction

To determine: The atoms of titanium in 0.125mole of Ti2O3 .

(c)

Expert Solution
Check Mark

Answer to Problem 3.19QP

Solution

The number of atoms of titanium in 0.125mole of Ti2O3 is 1.51×1023atoms_ .

Explanation of Solution

Explanation

Given

One mole Ti2O3 contains Avogadro’s number of molecules of Ti2O3 . Therefore, one mole of Ti2O3 is equivalent to 6.022×1023 molecules of Ti2O3 .

So, 1molTi2O3=6.022×1023moleculesTi2O3 .

One molecule of Ti2O3 contains two atoms of Ti and three atoms of O .

The number of titanium atoms in 0.125mole of Ti2O3 is calculated by using the formula,

N=n×NA×numberofTiatomsinamolecule

Where,

  • N is the number of atoms.
  • NA is the Avogadro’s number of atoms.
  • n is the number of moles.

Substitute the values of n and NA in the above formula to calculate the number of titanium atoms.

N=0.125mole×6.022×1023molecules/mole×2Tiatom1moleculeTi2O3=0.125×6.022×1023×2atoms=1.51×1023atoms_

Hence, the number of atoms of titanium in 0.125mole of Ti2O3 is 1.51×1023atoms_ .

(d)

Interpretation Introduction

To determine: The atoms of titanium in 0.125mole of Ti3O5 .

(d)

Expert Solution
Check Mark

Answer to Problem 3.19QP

Solution

The number of atoms of titanium in 0.125mole of Ti3O5 is 2.26×1023atoms_ .

Explanation of Solution

Explanation

Given

One mole Ti3O5 contains Avogadro’s number of molecules of Ti3O5 . Therefore, one mole of Ti3O5 is equivalent to 6.022×1023 molecules of Ti3O5 .

So, 1molTi3O5=6.022×1023moleculesTi3O5 .

One molecule of Ti3O5 contains three atoms of Ti and five atoms of O .

The number of titanium atoms in 0.125mole of Ti3O5 is calculated by using the formula,

N=n×NA×numberofTiatomsinamolecule

Where,

  • N is the number of atoms.
  • NA is the Avogadro’s number of atoms.
  • n is the number of moles.

Substitute the values of n and NA in the above formula to calculate the number of titanium atoms.

N=0.125mole×6.022×1023molecules/mole×3Tiatom1moleculeTi3O5=0.125×6.022×1023×3atoms=2.26×1023atoms_

Hence, the number of atoms of titanium in 0.125mole of Ti3O5 is 2.26×1023atoms_ .

Conclusion

  1. a. The number of atoms of titanium in 0.125mole of FeTiO3 is 7.53×1022atoms_ .
  2. b. The number of atoms of titanium in 0.125mole of TiCl4 is 7.53×1022atoms_ .
  3. c. The number of atoms of titanium in 0.125mole of Ti2O3 is 1.51×1023atoms_ .
  4. d. The number of atoms of titanium in 0.125mole of Ti3O5 is 2.26×1023atoms_

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Chapter 3 Solutions

Chemistry

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