Chemistry: The Science in Context (Fifth Edition)
Chemistry: The Science in Context (Fifth Edition)
5th Edition
ISBN: 9780393614046
Author: Thomas R. Gilbert, Rein V. Kirss, Natalie Foster, Stacey Lowery Bretz, Geoffrey Davies
Publisher: W. W. Norton & Company
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Chapter 3, Problem 3.19QP

(a)

Interpretation Introduction

Interpretation: The number of moles of each gas in the sample is to be calculated.

Concept introduction: A mole of a substance is the quantity of a substance which contains the same number of particles as the number of carbon atoms in exactly 12 grams for the carbon-12 isotopes. A mole of particles contains Avogadro’s number (6.022×1023) of particles.

To determine: The number of moles of the given gas in the sample.

(a)

Expert Solution
Check Mark

Answer to Problem 3.19QP

Solution

The number of moles of Ne(g) is 7.3×1010mol_ .

Explanation of Solution

Given

The number of atoms of Ne(g) is 4.4×1014 atoms.

Also, 1mol=6.022×1023atoms .

The number of moles is calculated by using the formula,

Numberofmoles=NNA

Where,

  • N is the number of atoms.
  • NA is the Avogadro’s number of atoms.

Substitute the value of N and NA in the above formula to calculate the number of moles.

NumberofmolesofNe(g)=4.4×1014atoms6.022×1023atoms/mol=7.3×1010mol_

Hence, the number of moles of Ne(g) is 7.3×1010mol_ .

(b)

Interpretation Introduction

To determine: The number of moles of the given gas in the sample.

(b)

Expert Solution
Check Mark

Answer to Problem 3.19QP

Solution

The number of moles of CH4(g) is 7.0×1011mol_ .

Explanation of Solution

Given

The number of molecules of CH4(g) is 4.2×1013 molecules.

Also, 1mol=6.022×1023molecules .

The number of moles is calculated by using the formula,

Numberofmoles=NNA

Where,

  • N is the number of atoms.
  • NA is the Avogadro’s number of atoms.

Substitute the value of N and NA in the above formula to calculate the number of moles.

NumberofmolesofCH4(g)=4.2×1013molecules6.022×1023molecules/mol=7.0×1011mol_

Hence, the number of moles of CH4(g) is 7.0×1011mol_ .

(c)

Interpretation Introduction

To determine: The number of moles of the given gas in the sample.

(c)

Expert Solution
Check Mark

Answer to Problem 3.19QP

Solution

The number of moles of O3(g) is 4.2×1012mol_ .

Explanation of Solution

Given

The number of molecules of O3(g) is 2.5×1012 molecules

Also, 1mol=6.022×1023molecules .

The number of moles is calculated by using the formula,

Numberofmoles=NNA

Where,

  • N is the number of atoms.
  • NA is the Avogadro’s number of atoms.

Substitute the value of N and NA in the above formula to calculate the number of moles.

NumberofmolesofO3(g)=2.5×1012molecules6.022×1023molecules/mol=4.2×1012mol_

Hence, the number of moles of O3(g) is 4.2×1012mol_ .

(d)

Interpretation Introduction

To determine: The number of moles of the given gas in the sample.

(d)

Expert Solution
Check Mark

Answer to Problem 3.19QP

Solution

The number of moles of NO2(g) is 8.1×1015mol_ .

Explanation of Solution

Given

The number of molecules of NO2(g) is 4.9×109 molecules

Also, 1mol=6.022×1023molecules

The number of moles is calculated by using the formula,

Numberofmoles=NNA

Where,

  • N is the number of atoms.
  • NA is the Avogadro’s number of atoms.

Substitute the value of N and NA in the above formula to calculate the number of moles.

NumberofmolesofNO2(g)=4.9×109molecules6.022×1023molecules/mol=8.1×1015mol_

Hence, the number of moles of NO2(g) is 8.1×1015mol_ .

Conclusion

  1. a. The number of moles of Ne(g) is 7.3×1010mol_ .
  2. b. The number of moles of CH4(g) is 7.0×1011mol_ .
  3. c. The number of moles of O3(g) is 4.2×1012mol_ .
  4. d. The number of moles of NO2(g) is 8.1×1015mol_

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Chapter 3 Solutions

Chemistry: The Science in Context (Fifth Edition)

Ch. 3.4 - Prob. 11PECh. 3.5 - Prob. 12PECh. 3.5 - Prob. 13PECh. 3.6 - Prob. 14PECh. 3.6 - Prob. 15PECh. 3.6 - Prob. 16PECh. 3.7 - Prob. 17PECh. 3.8 - Prob. 18PECh. 3.8 - Prob. 19PECh. 3.9 - Prob. 20PECh. 3.9 - Prob. 21PECh. 3.9 - Prob. 22PECh. 3.9 - Prob. 23PECh. 3 - Prob. 3.1VPCh. 3 - Prob. 3.2VPCh. 3 - Prob. 3.3VPCh. 3 - Prob. 3.4VPCh. 3 - Prob. 3.5VPCh. 3 - Prob. 3.6VPCh. 3 - Prob. 3.7VPCh. 3 - Prob. 3.8VPCh. 3 - Prob. 3.9VPCh. 3 - Prob. 3.10VPCh. 3 - Prob. 3.11QPCh. 3 - Prob. 3.12QPCh. 3 - Prob. 3.13QPCh. 3 - Prob. 3.14QPCh. 3 - Prob. 3.15QPCh. 3 - Prob. 3.16QPCh. 3 - Prob. 3.17QPCh. 3 - Prob. 3.18QPCh. 3 - Prob. 3.19QPCh. 3 - Prob. 3.20QPCh. 3 - Prob. 3.21QPCh. 3 - Prob. 3.22QPCh. 3 - Prob. 3.23QPCh. 3 - Prob. 3.24QPCh. 3 - Prob. 3.25QPCh. 3 - Prob. 3.26QPCh. 3 - Prob. 3.27QPCh. 3 - Prob. 3.28QPCh. 3 - Prob. 3.29QPCh. 3 - Prob. 3.30QPCh. 3 - Prob. 3.31QPCh. 3 - Prob. 3.32QPCh. 3 - Prob. 3.33QPCh. 3 - Prob. 3.34QPCh. 3 - Prob. 3.35QPCh. 3 - Prob. 3.36QPCh. 3 - Prob. 3.37QPCh. 3 - Prob. 3.38QPCh. 3 - Prob. 3.39QPCh. 3 - Prob. 3.40QPCh. 3 - Prob. 3.41QPCh. 3 - Prob. 3.42QPCh. 3 - Prob. 3.43QPCh. 3 - Prob. 3.44QPCh. 3 - Prob. 3.45QPCh. 3 - Prob. 3.46QPCh. 3 - Prob. 3.47QPCh. 3 - Prob. 3.48QPCh. 3 - Prob. 3.49QPCh. 3 - Prob. 3.50QPCh. 3 - Prob. 3.51QPCh. 3 - Prob. 3.52QPCh. 3 - Prob. 3.53QPCh. 3 - Prob. 3.54QPCh. 3 - Prob. 3.55QPCh. 3 - Prob. 3.56QPCh. 3 - Prob. 3.57QPCh. 3 - Prob. 3.58QPCh. 3 - Prob. 3.59QPCh. 3 - Prob. 3.60QPCh. 3 - Prob. 3.61QPCh. 3 - Prob. 3.62QPCh. 3 - Prob. 3.63QPCh. 3 - Prob. 3.64QPCh. 3 - Prob. 3.65QPCh. 3 - Prob. 3.66QPCh. 3 - Prob. 3.67QPCh. 3 - Prob. 3.68QPCh. 3 - Prob. 3.69QPCh. 3 - Prob. 3.70QPCh. 3 - Prob. 3.71QPCh. 3 - Prob. 3.72QPCh. 3 - Prob. 3.73QPCh. 3 - Prob. 3.74QPCh. 3 - Prob. 3.75QPCh. 3 - Prob. 3.76QPCh. 3 - Prob. 3.77QPCh. 3 - Prob. 3.78QPCh. 3 - Prob. 3.79QPCh. 3 - Prob. 3.80QPCh. 3 - Prob. 3.81QPCh. 3 - Prob. 3.82QPCh. 3 - Prob. 3.83QPCh. 3 - Prob. 3.84QPCh. 3 - Prob. 3.85QPCh. 3 - Prob. 3.86QPCh. 3 - Prob. 3.87QPCh. 3 - Prob. 3.88QPCh. 3 - Prob. 3.89QPCh. 3 - Prob. 3.90QPCh. 3 - Prob. 3.91QPCh. 3 - Prob. 3.92QPCh. 3 - Prob. 3.93QPCh. 3 - Prob. 3.94QPCh. 3 - Prob. 3.95QPCh. 3 - Prob. 3.96QPCh. 3 - Prob. 3.97QPCh. 3 - Prob. 3.98QPCh. 3 - Prob. 3.99QPCh. 3 - Prob. 3.100QPCh. 3 - Prob. 3.101QPCh. 3 - Prob. 3.102QPCh. 3 - Prob. 3.103QPCh. 3 - Prob. 3.104QPCh. 3 - Prob. 3.105QPCh. 3 - Prob. 3.106QPCh. 3 - Prob. 3.107QPCh. 3 - Prob. 3.108QPCh. 3 - Prob. 3.109QPCh. 3 - Prob. 3.110QPCh. 3 - Prob. 3.111QPCh. 3 - Prob. 3.112QPCh. 3 - Prob. 3.113QPCh. 3 - Prob. 3.114QPCh. 3 - Prob. 3.115QPCh. 3 - Prob. 3.116QPCh. 3 - Prob. 3.117QPCh. 3 - Prob. 3.118QPCh. 3 - Prob. 3.119QPCh. 3 - Prob. 3.120QPCh. 3 - Prob. 3.121APCh. 3 - Prob. 3.122APCh. 3 - Prob. 3.123APCh. 3 - Prob. 3.124APCh. 3 - Prob. 3.125APCh. 3 - Prob. 3.126APCh. 3 - Prob. 3.127APCh. 3 - Prob. 3.128APCh. 3 - Prob. 3.129APCh. 3 - Prob. 3.130APCh. 3 - Prob. 3.131APCh. 3 - Prob. 3.132APCh. 3 - Prob. 3.133APCh. 3 - Prob. 3.134APCh. 3 - Prob. 3.135APCh. 3 - Prob. 3.136APCh. 3 - Prob. 3.137APCh. 3 - Prob. 3.138APCh. 3 - Prob. 3.139APCh. 3 - Prob. 3.140APCh. 3 - Prob. 3.141APCh. 3 - Prob. 3.142APCh. 3 - Prob. 3.143APCh. 3 - Prob. 3.144APCh. 3 - Prob. 3.145APCh. 3 - Prob. 3.146APCh. 3 - Prob. 3.147APCh. 3 - Prob. 3.148AP
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