Concept explainers
A mixture of methane (CH4) and ethane (C2H6) of mass 13.43 g is completely burned in oxygen. If the total mass of CO2 and H2O produced is 64.84 g, calculate the fraction of CH4 in the mixture.
Interpretation:
The fraction of
Concept introduction:
- Balanced chemical equation of a reaction is written according to law of conservation of mass.
- Equation for Number of moles of a substance, from its given mass is,
- Mole ratio between the reactant and a product of a reaction are depends upon the coefficients of reactant and product in a balanced chemical equation.
Answer to Problem 3.147QP
The fraction of
Explanation of Solution
In given reaction,
Mixture of
Therefore,
The chemical equation for this reaction is,
Balanced chemical equation of a reaction is written according to law of conservation of mass.
Therefore,
The total number of each atoms in the reactant side should equal to the total number of each atoms in the product side.
So, in order to balance a chemical equation, the coefficients of compounds or atoms are needed to be changed in such a way that total number of each atoms in the reactant side and the total number of each atoms in the product side is to become equal.
Hence,
The balanced equations for the given reactions are,
Assumes mass of
The mass of Mixture of
Let’s take mass of
So, the number of moles of
The balanced chemical equation of the reaction is,
The mole ratio between
The mole ratio between
So, the number of moles of
Then,
The mass of
The mass of
The mass of Mixture of
Let’s take mass of
So, the number of moles of
The balanced chemical equation of the reaction is,
The mole ratio between
The mole ratio between
So, the number of moles of
Then,
The mass of
The mass of
The mass of
The mass of
The mass of
The mass of
The total mass of
Therefore,
So, the mass of
Hence,
The fraction of
The fraction of
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Chapter 3 Solutions
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