Manufacturing Engineering & Technology
7th Edition
ISBN: 9780133128741
Author: Serope Kalpakjian, Steven Schmid
Publisher: Prentice Hall
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Chapter 3, Problem 2RQ
Explain why the melting point of a material can be an important factor in material selection.
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Chapter 3 Solutions
Manufacturing Engineering & Technology
Ch. 3 - List several reasons that density is an important...Ch. 3 - Explain why the melting point of a material can be...Ch. 3 - What adverse effects can be caused by thermal...Ch. 3 - Prob. 4RQCh. 3 - What is the piezoelectric effect?Ch. 3 - Prob. 6RQCh. 3 - Prob. 7RQCh. 3 - What is the difference between thermal...Ch. 3 - What is corrosion? How can it be prevented or...Ch. 3 - Explain stress-corrosion cracking. Why is it also...
Ch. 3 - Prob. 11RQCh. 3 - Prob. 12RQCh. 3 - What is the fundamental difference between...Ch. 3 - Describe the significance of structures and...Ch. 3 - Prob. 15QLPCh. 3 - Note in Table 3.1 that the properties of the...Ch. 3 - Rank the following in order of increasing thermal...Ch. 3 - Prob. 18QLPCh. 3 - Explain how thermal conductivity can play a role...Ch. 3 - What material properties are desirable for heat...Ch. 3 - Prob. 21QLPCh. 3 - Prob. 22QLPCh. 3 - Two physical properties that have a major...Ch. 3 - Which of the materials described in this chapter...Ch. 3 - Which properties described in this chapter can be...Ch. 3 - If we assume that all the work done in plastic...Ch. 3 - The natural frequency, f, of a cantilever beam is...Ch. 3 - Plot the following for the materials described in...Ch. 3 - It can be shown that thermal distortion in...Ch. 3 - Add a column to Table 3.1 that lists the...Ch. 3 - Prob. 31SDPCh. 3 - Prob. 32SDPCh. 3 - Prob. 33SDPCh. 3 - Prob. 34SDPCh. 3 - Prob. 36SDPCh. 3 - Prob. 38SDPCh. 3 - Prob. 40SDPCh. 3 - Prob. 41SDPCh. 3 - Prob. 42SDPCh. 3 - Prob. 43SDP
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- The theoretical failure strength is significantly higher than the empirical failure strength of polycrystalline materials, even when they are highly polished because: a) Polycrystalline materials have little or no capacity for plastic deformation, so they have lower failure stresses b) Plastic deformation in polycrystalline materials adsorbs energy which reduces their failure strength c)The energy needed to break the atomic bonds in crystal lattices is lower in polycrystalline materials as compared to in single crystals d)Polycrystalline materials contain internal discontinuitiesarrow_forwardExplain the difference between qualative and quantative data in relation to materials testing.arrow_forwardIn the First project: you have been asked to perform tensile testing for four different materialsand analyse the results and work on some NDT process selection:a. For the results shown in Table 1 of the tensile testing that you have performed, find thefollowing, if you know that the original length of specimen is 20.8 mm and the original diameteris 6.4 mm. Fill the calculated results in the summary table below (Table 1):1. Plot the engineering stress versus engineering strain for each material and L-D Diagram.2. Compute the modulus of elasticity, E in GPa.3. Determine the yield strength at a strain offset of 0.002.4. Determine the tensile strength in MPa.5. What is the approximate %El ductility, measured by percent elongation?6. Compute the modulus of resilience.7. Determine the fracture stress in MPa.8. Compute the final area (Af) in mm2.arrow_forward
- What is Material Property Relationships?arrow_forwardShow the typical Stress versus Strain curve for the following materials, and define the materials properties "The stress-strain curve can be used to read off the structural load ability of materials. For many materials, including metals, their loading bearing capability is one of the most important material properties". by reference to the diagram: a) Hammer head is made from hardened tool steel b) Smelter is made from refractory ceramic c) Cable is made from pure copper d) Box is made from polypropylenearrow_forwardPlease I need answer quickly Q25(I) Explain the advantages of material selection process.arrow_forward
- At higher temperature, strength and strain hardening are increased, whereas, ductility is decreased which permits greater plastic deformation True False O Saaly i The strength constant (C) is increased with increasing of temperature True O False O The metal is becoming weaker as strain increases, this is because of .strain hardening (work hardening) property True O False O ly The engineering stress and strain are defined relative to the instantaneous area and length of test specimen True O False O In sheetmetal working processes, the surface area-to-volume ratio of .w.p. is low True O False O aly ihi Determine the value of the strain-hardening exponent for a metal that will cause the average flow stress to be 70% of the final flow stress after deformation 0.444 0.421 0.422 0.428 aaly i For pure copper (annealed), the strength coefficient = 330 MPa and strain-hardening exponent = 0.52 in the flow curve equation. Determine the average flow stress that the metal experiences if it is…arrow_forwardExplain how test results influence material selection for a given application.arrow_forwardIn your summer internship, you are tasked with measuring the ultimate tensile strength of a material to determine if it meets your company’s (Superior Super Ships Inc) specification. Your boss is worried that the new low-cost supplier, Shoddy Alloys Inc, may not be reliable but it is the only way to source on-time the SS304 needed to make finishings for Jeff Bezos’ new yacht, the Black Pearl. You collect several load versus displacement curves, as illustrated below. The initial diameter of the round gauge section is 0.25 in. You also collect the instantaneous diameter of the specimen during the test using a laser. Using the provided data, calculate what is the ultimate tensile strength measured in this test?arrow_forward
- By looking at these graphs, answer the following answer: 1/ Is the material is ductile or brittle? explain by using information from the graphs. 2/ What are the differences between these two graphs?arrow_forwardYield strength, ultimate tensile strength, linear coefficient of thermal expansion, modulus of elasticity (E), proportional limit, and rupture strength are all examples of mechanical properties of engineering materials. O True False A non-destructive test is any examination of an object in any manner which will not impair the future usefulness of the object. Non-destructive tests include: magnetic-particle, impacting testing, radiography, eddy current, and fluorescent-penetrant. O True O False One way to make a metal stronger is to increase the metal's grain size. O True O False --- OL T A metal that has a crystalline structure is called amorphous. O True O Falsearrow_forwardBoth yield strength and ultimate tensile strength exhibit the ability of a material to withstand a certain level of load. Which parameter do you prefer to use as a design parameter for a proper selection of materials for structural applications? Explain.arrow_forward
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Material Properties 101; Author: Real Engineering;https://www.youtube.com/watch?v=BHZALtqAjeM;License: Standard YouTube License, CC-BY