Introduction To Genetic Analysis
12th Edition
ISBN: 9781319114787
Author: Anthony J.F. Griffiths, John Doebley, Catherine Peichel, David A. Wassarman
Publisher: W. H. Freeman
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Chapter 3, Problem 29P
a.
Summary Introduction
To determine: The proportion of the gametophytes that will be A ; B.
Introduction: The gametophyte is the sexual phase in the life cycle of plants and algae. It develops sex organs that produce gametes, haploid sex cells that participate in fertilization to form a diploid zygote that has a double set of chromosomes.
b.
Summary Introduction
To determine: The proportion of sporophytes in the next generation that will be A/a ; B/b, if fertilization is random.
Introduction: Saprophytes break down the dead and decaying organic matter into simpler substances that can be taken up and recycled by the plants. Thus they play an essential role in maintaining the ecological balance.
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Suppose you have an AAaa tetraploid plant and it undergoes self-fertilization. At least two copies of thedominant allele A are needed to obtain the dominantphenotype. At what frequency will progeny with thedominant phenotype appear?
Suppose you have an AAaa tetraploid plant and it undergo self- fertilization. At least two copies of the dominant allele A are needed to obtain the dominant phenotype. At what frequency will progeny with the dominant phenotype appear?
Consider a plant that has the "Leaf" gene (L) that causes leaves to be either smooth
or wrinkled and is inherited through complete dominance. Heterozygotes of the L
gene are smooth.
A. What are the two alleles of the gene?
B. What is the recessive phenotype?
C. What is the genotype of a homozygous dominant individual?
D. What gametes can a heterozygous individual make?
E. Make a Punnett square to predict the percentage or fraction of recessive
progeny when two heterozygous individuals are mated.
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Chapter 3 Solutions
Introduction To Genetic Analysis
Ch. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Prob. 3PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Prob. 9PCh. 3 - Prob. 10P
Ch. 3 - Prob. 11PCh. 3 - Prob. 12PCh. 3 - Prob. 13PCh. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 19PCh. 3 - Prob. 20PCh. 3 - Prob. 21PCh. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Prob. 25PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - Prob. 30PCh. 3 - Prob. 31PCh. 3 - Prob. 32PCh. 3 - Prob. 33PCh. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - Prob. 40PCh. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Prob. 43PCh. 3 - Prob. 43.1PCh. 3 - Prob. 43.2PCh. 3 - Prob. 43.3PCh. 3 - Prob. 43.4PCh. 3 - Prob. 43.5PCh. 3 - Prob. 43.6PCh. 3 - Prob. 43.7PCh. 3 - Prob. 43.8PCh. 3 - Prob. 43.9PCh. 3 - Prob. 43.10PCh. 3 - Prob. 43.11PCh. 3 - Prob. 43.12PCh. 3 - Prob. 43.13PCh. 3 - Prob. 43.14PCh. 3 - Prob. 43.15PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - Prob. 47PCh. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 51PCh. 3 - Prob. 52PCh. 3 - Prob. 53PCh. 3 - Prob. 54PCh. 3 - Prob. 55PCh. 3 - Prob. 56PCh. 3 - Prob. 57PCh. 3 - Prob. 58PCh. 3 - Prob. 59PCh. 3 - Prob. 61PCh. 3 - Prob. 62PCh. 3 - Prob. 63PCh. 3 - Prob. 64PCh. 3 - Prob. 65PCh. 3 - Prob. 66PCh. 3 - Prob. 67PCh. 3 - Prob. 70PCh. 3 - Prob. 1GSCh. 3 - Prob. 2GSCh. 3 - Prob. 3GS
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- Let P = purple flowers and p = white, and T = tall plants and t = dwarf. What are the genotypes of the gametes that are produced by a plant that is heterozygous for both traits? hint* This is a dihybrid self cross of an F1 heterozygous generation. O Tt, TT, tt, Pp, PP, and pp P, p, T, and t PT, Pt, pT, and pt PT and ptarrow_forwardGgTt pea plants can produce _____ type(s) of gamete(s), but a ggtt plant can produce _____ type(s) of gamete(s). explainarrow_forwardIn snapdragons red flower colour (CR) is incompletely dominant to white flower colour (CW). The heterozygote has pink flowers. Normal broad leaves (LB) are incompletely dominant to narrow, grass-like leaves, (LN). The heterozygote has intermediate leaf width. If a red-flowered, narrow leaved snapdragon is crossed with a white-flowered broad leaved one, what will be the phenotypes in the F1 and F2 generations, and what will be the proportions of the different phenotypic classes? (You must draw a branch diagram to provide the answer for the F2)arrow_forward
- In snapdragons red flower colour (CR) is incompletely dominant to white flower colour (CW). The heterozygote has pink flowers. Normal broad leaves (LB) are incompletely dominant to narrow, grass-like leaves, (LN). The heterozygote has intermediate leaf width. If a red-flowered, narrow leaved snapdragon is crossed with a white-flowered broad leaved one, what will be the phenotypes in the F1 and F2 generations, and what will be the proportions of the different classes? (Draw a branch diagram to provide the answer)arrow_forwardSuppose that a compound attractive to pollinators is produced by a plant in a pathway encoded by genes one (O) and two (T). You have obtained two pure lines of plants, one that produces the compound and one that does not (OOTT and oott, respectively). You cross them to obtain F1 plants that are heterozygous at both loci. (a) Use a branch diagram to visualize the possible outcomes of a cross between two F1 plants. (b) Calculate the expected proportion of offspring that will produce the attractant if this is a case of duplicate recessive epistasis. (c) What is the expected proportion of offspring that will produce attractant if this is a case of duplicate dominance?arrow_forwardAt the molecular level (with regard to loss-of-function alleles), explain why the ttvv homozygote has an ovate seed capsule.arrow_forward
- if a plant is an auto-tetraploid with the genotype A1A1A2A2, what is the frequenct of offspring with the genotype A1A1A1A1 following self-fertilization of the plantarrow_forwardGiven : The given plant is triploid. Symbol For purple = P For yellow seed = Y For round seed = R Answer 1. The Probability of PpYyRr = 8/64 = 1/8 2. The Probability of PPyyRr = 4/64 = 1/16 3. Probability of at least exhibiting wrinkled seeds = 32/64 = 1/2 4. Probability of at least exhibiting purple flowers = 48/64 = 6/8 = 3/4 QUESTION: Answer the remaining question (5, 6, 7)arrow_forward. In nature, the plant Plectritis congesta is dimorphic forfruit shape; that is, individual plants bear either winglessor winged fruits, as shown in the illustration.Wingless fruit Winged fruitPlants were collected from nature before floweringand were crossed or selfed with the following results:Number of progenyPollination Winged WinglessWinged (selfed) 91 1*Winged (selfed) 90 30Wingless (selfed) 4* 80Winged × wingless 161 0Winged × wingless 29 31Winged × wingless 46 0Winged × winged 44 0*Phenotype probably has a nongenetic explanation.Interpret these results, and derive the mode ofinheritance of these fruit-shaped phenotypes. Usesymbols. What do you think is the nongeneticexplanation for the phenotypes marked by asterisks inthe table?arrow_forward
- Large ear of corn has a total of 433 grains, including 26 Yellow & Shrunken, 73 Purple & Shrunken, 63 Yellow & Smooth, and 271 Purple & Smooth. Determine whether the ratio of corn kernels support the hypothesis that the plant is heterozygous.arrow_forwardIn Corn, Male sterility is controlled by maternal cytoplasmic elements. This phenotype renders the male part of corn plants(i.e. the tassol) unable to produce fertile pollen; the female parts. However, remain receptive to pollination by pollen from male fertile corn plants, however the presence of a nuclear fertility restore gene F restores fertility to make sterile lines. b. Explain the phenotype of the offspring.arrow_forwardshows the results of a dihybrid cross involving seed shape and seed color. a. What proportion of the round and yellow F2 progeny from this cross is homozygous at both loci? b. What proportion of the round and yellow F2 progeny from this cross is homozygous at least at one locus?arrow_forward
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