World of Chemistry, 3rd edition
World of Chemistry, 3rd edition
3rd Edition
ISBN: 9781133109655
Author: Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher: Brooks / Cole / Cengage Learning
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Chapter 3, Problem 29A

(a)

Interpretation Introduction

Interpretation: The number of protons and neutrons present in the nucleus of 244Pu94 needs to be determined.

Concept Introduction :

The number of protons in an atom is called the atomic number. The addition of the number of protons and neutrons, is equal to the mass number. When the numbers of neutrons are different the mass number of element is changes but atomic number remains unchanged that consider as an isotope of the element.

(a)

Expert Solution
Check Mark

Answer to Problem 29A

The number of protons= 94

The number of neutrons= 150

The number of electrons = 94

Explanation of Solution

The number of protons= 94

For the number of neutrons= Mass number − number of

  =24494=150

The number of neutrons= 150

When the number of electron is equal to the number of protons, then atom is uncharged.

So the number of electrons = 94

(b)

Interpretation Introduction

Interpretation: The number of protons and neutrons are contained in the nucleus of A243m95 needs to be determined.

Concept Introduction :

The number of protons in an atom is called the atomic number. The sum of the number of protons and neutrons, is equal to the mass number. When the numbers of neutrons are different the mass number of element is changes but atomic number remains unchanged that consider as a isotope of the element.

(b)

Expert Solution
Check Mark

Answer to Problem 29A

The number of protons = 95

The number of neutrons= 148

The number of electrons= 95

Explanation of Solution

The number of protons = 95

For the number of neutrons= Mass number − number of protons

   =24395 = 148

The number of neutrons= 148

When the number of electron is equal to the number of protons, then atom is uncharged.

So the number of electrons= 95

(c)

Interpretation Introduction

Interpretation: The number of protons and neutrons are contained in the nucleus of 277Ac89 needs to be determined.

Concept Introduction :

The number of protons in an atom is called the atomic number. The sum of the number of protons and neutrons, is equal to the mass number. When the numbers of neutrons are different the mass number of element is changes but atomic number remains unchanged that consider as a isotope of the element.

(c)

Expert Solution
Check Mark

Answer to Problem 29A

The number of protons = 89

The number of neutrons =188

The number of electrons= 89

Explanation of Solution

The number of protons = 89

For the number of neutrons= Mass number − number of protons

  =27789=188

The number of neutrons =188

When the number of electron is equal to the number of protons, then atom is uncharged.

So the number of electrons= 89

(d)

Interpretation Introduction

Interpretation: The number of protons and neutrons are contained in the nucleus of 132Cs55 needs to be determined.

Concept Introduction :

The number of protons in an atom is called the atomic number. The sum of the number of protons and neutrons, is equal to the mass number. When the numbers of neutrons are different the mass number of element is changes but atomic number remains unchanged that consider as a isotope of the element.

(d)

Expert Solution
Check Mark

Answer to Problem 29A

The number of protons = 55

The number of neutrons =77

The number of electrons= 55

Explanation of Solution

The number of protons = 55

For the number of neutrons= Mass number − number of protons

  =13255=77

The number of neutrons =77

When the number of electron is equal to the number of protons, then atom is uncharged.

So the number of electrons= 55

(e)

Interpretation Introduction

Interpretation: The number of protons and neutrons contained in the nucleus of 192Ir77 needs to be determined.

Concept Introduction :

The number of protons in an atom is called the atomic number. The sum of the number of protons and neutrons, is equal to the mass number. When the numbers of neutrons are different the mass number of element is changes but atomic number remains unchanged that consider as a isotope of the element.

(e)

Expert Solution
Check Mark

Answer to Problem 29A

The number of protons = 77

The number of neutrons =115

The number of electrons= 77

Explanation of Solution

The number of protons = 77

For the number of neutrons= Mass number − number of protons

  =19277=115

The number of neutrons =115

When the number of electron is equal to the number of protons, then atom is uncharged.

So the number of electrons= 77

(f)

Interpretation Introduction

Interpretation: The number of protons and neutrons contained in the nucleus of 54Mn25 needs to be determined.

Concept Introduction :

The number of protons in an atom is called the atomic number. The sum of the number of protons and neutrons, is equal to the mass number. When the numbers of neutrons are different the mass number of element is changes but atomic number remains unchanged that consider as a isotope of the element.

(f)

Expert Solution
Check Mark

Answer to Problem 29A

The number of protons = 25

The number of neutrons= 29

The number of electrons= 25

Explanation of Solution

The number of protons = 25

For the number of neutrons= Mass number − number of protons

  =5425=29

The number of neutrons= 29

When the number of electron is equal to the number of protons, then atom is uncharged.

So the number of electrons= 25

Chapter 3 Solutions

World of Chemistry, 3rd edition

Ch. 3.2 - Prob. 5RQCh. 3.2 - Prob. 6RQCh. 3.3 - Prob. 1RQCh. 3.3 - Prob. 2RQCh. 3.3 - Prob. 3RQCh. 3.3 - Prob. 4RQCh. 3.3 - Prob. 5RQCh. 3.3 - Prob. 6RQCh. 3.3 - Prob. 7RQCh. 3.4 - Prob. 1RQCh. 3.4 - Prob. 2RQCh. 3.4 - Prob. 3RQCh. 3.4 - Prob. 4RQCh. 3.4 - Prob. 5RQCh. 3.4 - Prob. 6RQCh. 3.4 - Prob. 7RQCh. 3.4 - Prob. 8RQCh. 3.5 - Prob. 1RQCh. 3.5 - Prob. 2RQCh. 3.5 - Prob. 3RQCh. 3.5 - Prob. 4RQCh. 3.5 - Prob. 5RQCh. 3 - Prob. 1ACh. 3 - Prob. 2ACh. 3 - Prob. 3ACh. 3 - Prob. 4ACh. 3 - Prob. 5ACh. 3 - Prob. 6ACh. 3 - Prob. 7ACh. 3 - Prob. 8ACh. 3 - Prob. 9ACh. 3 - Prob. 10ACh. 3 - Prob. 11ACh. 3 - Prob. 12ACh. 3 - Prob. 13ACh. 3 - Prob. 14ACh. 3 - Prob. 15ACh. 3 - Prob. 16ACh. 3 - Prob. 17ACh. 3 - Prob. 18ACh. 3 - Prob. 19ACh. 3 - Prob. 20ACh. 3 - Prob. 21ACh. 3 - Prob. 22ACh. 3 - Prob. 23ACh. 3 - Prob. 24ACh. 3 - Prob. 25ACh. 3 - Prob. 26ACh. 3 - Prob. 27ACh. 3 - Prob. 28ACh. 3 - Prob. 29ACh. 3 - Prob. 30ACh. 3 - Prob. 31ACh. 3 - Prob. 32ACh. 3 - Prob. 33ACh. 3 - Prob. 34ACh. 3 - Prob. 35ACh. 3 - Prob. 36ACh. 3 - Prob. 37ACh. 3 - Prob. 38ACh. 3 - Prob. 39ACh. 3 - Prob. 40ACh. 3 - Prob. 41ACh. 3 - Prob. 42ACh. 3 - Prob. 43ACh. 3 - Prob. 44ACh. 3 - Prob. 45ACh. 3 - Prob. 46ACh. 3 - Prob. 47ACh. 3 - Prob. 48ACh. 3 - Prob. 49ACh. 3 - Prob. 50ACh. 3 - Prob. 51ACh. 3 - Prob. 52ACh. 3 - Prob. 53ACh. 3 - Prob. 54ACh. 3 - Prob. 55ACh. 3 - Prob. 56ACh. 3 - Prob. 57ACh. 3 - Prob. 58ACh. 3 - Prob. 59ACh. 3 - Prob. 60ACh. 3 - Prob. 61ACh. 3 - Prob. 1STPCh. 3 - Prob. 2STPCh. 3 - Prob. 3STPCh. 3 - Prob. 4STPCh. 3 - Prob. 5STPCh. 3 - Prob. 6STPCh. 3 - Prob. 7STPCh. 3 - Prob. 8STPCh. 3 - Prob. 9STPCh. 3 - Prob. 10STP
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