EBK DATA STRUCTURES AND ALGORITHMS IN C
EBK DATA STRUCTURES AND ALGORITHMS IN C
4th Edition
ISBN: 9781285415017
Author: DROZDEK
Publisher: YUZU
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Chapter 3, Problem 24E

Explanation of Solution

Criteria for Searching:

  • Searching requires construction of the self–organised list initially.
  • For the construction of the self–organized list, the following methods are used.
    • Plain method.
  • Move–to–front (MFT) method.
    • Ordering method.
    • Count method.
    • Transpose method.

Optimal Searching:

  • As the optimal search needs the construction of the list initially...

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What is the difference between Longest Increasing Subsequence (LIS) and Longest Decreasing Subsequence (LDS)?
Find shortest path from top left column to the right lowest column using DFS.only step on the columns whose value is 1if there is no path, it returns -1(The first column(top left column) is not included in the answer.) Ex 1)If maze is[[1,0,1,1,1,1], [1,0,1,0,1,0], [1,0,1,0,1,1], [1,1,1,0,1,1]],the answer is: 14 Ex 2)If maze is[[1,0,0], [0,1,1], [0,1,1]],the answer is: -1''' def find_path(maze):    cnt = dfs(maze, 0, 0, 0, -1)    return cnt def dfs(maze, i, j, depth, cnt):    directions = [(0, -1), (0, 1), (-1, 0), (1, 0)]     row = len(maze)    col = len(maze[0])     if i == row - 1 and j == col - 1:        if cnt == -1:            cnt = depth        else:            if cnt > depth:                cnt = depth        return cnt     maze[i][j] = 0     for k in range(len(directions)):        nx_i = i + directions[k][0]        nx_j = j + directions[k][1]         if nx_i >= 0 and nx_i < row and nx_j >= 0 and nx_j < col:            if maze[nx_i][nx_j] == 1:                cnt…
The Depth-first search is not optimal if limit is greater than depth. Select one: True False
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