Understanding Our Universe
3rd Edition
ISBN: 9780393614428
Author: PALEN, Stacy, Kay, Laura, Blumenthal, George (george Ray)
Publisher: W.w. Norton & Company,
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Chapter 3, Problem 15QAP
To determine
The correct reason for the wrong statement given.
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Assume the earth's mass is 73.13 x 1025 kg, and radius is 27.06 x 103 miles, what would be the gravitational acceleration on such an planet in unit of m/s2? Use G=6.67x 10 -11 Nm2/kg2.
According to Kepler's third law of planetary motion, the mean distance D, in millions of miles, from a planet in our solar system to the sun is related to the time P, in years, that it takes for the planet to complete a revolution around the sun, and the relationship is
D = 93P 2/3.
It takes the planet Pluto 248 years to complete a revolution around the sun. What is the mean distance from Pluto to the sun? What is the mean distance from Earth to the sun? Give your answers to the nearest million miles.
from pluto to sun _____ million miles
from earth to sun _____ million miles
Newton’s version of Kepler’s third law is P2 = 4 π2 / [G (M1 + M2)] · a3, where G is the gravitational constant, which is equal to 6.67*10-11 m3 kg-1 s-2. NASA's New Horizons mission found that Pluto's moon Charon orbits Pluto every 5.7 days at an average distance of 19200.0 km. What is the combined mass (in kg) of Pluto and Charon?
Chapter 3 Solutions
Understanding Our Universe
Ch. 3.1 - Prob. 3.1CYUCh. 3.2 - Prob. 3.2CYUCh. 3.3 - Prob. 3.3CYUCh. 3.4 - Prob. 3.4CYUCh. 3.5 - Prob. 3.5CYUCh. 3 - Prob. 1QAPCh. 3 - Prob. 2QAPCh. 3 - Prob. 3QAPCh. 3 - Prob. 4QAPCh. 3 - Prob. 5QAP
Ch. 3 - Prob. 6QAPCh. 3 - Prob. 7QAPCh. 3 - Prob. 8QAPCh. 3 - Prob. 9QAPCh. 3 - Prob. 10QAPCh. 3 - Prob. 11QAPCh. 3 - Prob. 12QAPCh. 3 - Prob. 13QAPCh. 3 - Prob. 14QAPCh. 3 - Prob. 15QAPCh. 3 - Prob. 16QAPCh. 3 - Prob. 17QAPCh. 3 - Prob. 18QAPCh. 3 - Prob. 19QAPCh. 3 - Prob. 20QAPCh. 3 - Prob. 21QAPCh. 3 - Prob. 22QAPCh. 3 - Prob. 23QAPCh. 3 - Prob. 24QAPCh. 3 - Prob. 25QAPCh. 3 - Prob. 26QAPCh. 3 - Prob. 27QAPCh. 3 - Prob. 28QAPCh. 3 - Prob. 29QAPCh. 3 - Prob. 30QAPCh. 3 - Prob. 31QAPCh. 3 - Prob. 32QAPCh. 3 - Prob. 33QAPCh. 3 - Prob. 34QAPCh. 3 - Prob. 35QAPCh. 3 - Prob. 36QAPCh. 3 - Prob. 37QAPCh. 3 - Prob. 38QAPCh. 3 - Prob. 39QAPCh. 3 - Prob. 40QAPCh. 3 - Prob. 41QAPCh. 3 - Prob. 42QAPCh. 3 - Prob. 43QAPCh. 3 - Prob. 44QAPCh. 3 - Prob. 45QAP
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- Mars has an orbital radius of 1.523 AU and an orbital period of 687.0 days. What is its average speed v in SI units? (1 AU is the astronomical unit, the mean distance between the Sun and the Earth, which is 1.496×1011 m) a. 0.00221 AU/day b. 3838 m/s c. 0 d. 1.28×10−9 m/sarrow_forwardWhich of the following statements cannot be supported by Kepler's laws of planetary motion? a The distance of a planet around the sun changes throughout its orbit. b The speed a planet is moving around the sun changes throughout the year. c The orbital period of Mercury can be calculated using the orbital period of Jupiter and the average distances of both planets. d The age of the four largest planets can be determined using the age of the four smallest planets and the average distances of each planet.arrow_forwardWhat is Kepler's first law of planetary motion? The period of a planet's orbit is proportional to its distance from the sun. Planets have circular orbits. Planets have elliptical orbits. The eccentricity of a planet's orbit is proportional to its distance from the sun.arrow_forward
- A newly discovered planet has four times the mass of the Earth, but a person's weight on the new planet's surface is the same as the person's weight on the Earth's surface. The radius of the new planet in terms of the radius R of Earth isarrow_forwardThe mass of Mars is 6.42 × 10^23 kg. Its moon Phobos is 9.378 x 10^6 meters away from Mars, with a mass of 1.06 × 10^16 kg and a period of 7.66 hours. It's moon Deimos has a mass of 1.4762x10^15 kg and a period of 30.3 hours. a) Use Kepler's 3rd law to determine the orbital distance between Mars and Deimos? b) What is the tangential velocity of Phobos, using the formula v (tangential) = sqrt (G x m(central)/ r)? c) What is the gravitational force of attraction between Mars and Phobos.arrow_forwardA man is standing on the moon. His mass is 100 kg. The mass of the moon is 7x10^22 kg. The radius is 3.8x10^5 km. How much is the gravitational force between the man and the moon?arrow_forward
- A certain planet has a radius of 4990 km. If, on the surface of that planet, a 95.0 kg object has a weight of 591 N, then what is the mass of the planet?arrow_forwardThe mass of Mars is 6.42 × 10^23 kg. Its moon Phobos is 9.378 x 10^6 meters away from Mars, with a mass of 1.06 × 10^16 kg and a period of 7.66 hours. It's moon Deimos has a mass of 1.4762×10^15 kg and a period of 30.3 hours. a) Use Kepler's 3rd law to determine the orbital distance between Mars and Deimos? b) What is the tangential velocity of Phobos, using the formula v(tangential) = sqrt (G x m(central)/ r)? c) What is the gravitational force of attraction between Mars and Phobos.arrow_forwardYou are trapped on an earth-like planet with a mass of 7.00×1024 kg and a radius of 3000 km. You were able to build a cannon capable of launching a human. What velocity will you need to escape the planet? (We can simplify the Gravitational Constant G to 6.7x10-11 Nm2/kg) m/sarrow_forward
- Suppose a planet with a mass of 2.24 ✕ 1025 kg is orbiting a star with a mass of 3.55 ✕ 1031 kg, and the mean distance between the planet and the star is 1.62 ✕ 1012 m. Using Newton's law of universal gravity, determine the speed of the planet when it is at the mean distance from the star. m/sarrow_forwardAn object of mass 0.50 kg is transported to the surface of Planet X where the object's weight is measured to be 20 N. The radius of the planet is 4.0 x10^6 m. What is the mass of Planet X? (G = 6.67x10^-11 N m*2/kg^2) * O 13x1019 kg O 17x10^22 kg 9.6x10^24 kg O 21x10°25 kgarrow_forwardIn a distant star system there are many inhabitable planets. One of these planets is named Qomar. Qomar is 3.2 AU's from its star and takes 6.5 Earth years to go around its star once. There is another planet in the same star system called Ferenginar. Ferenginar is 0.9 AUs from the star. What is the length of a Ferengi year (on Ferenginar) in terms of Earth years?arrow_forward
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