(a)
Interpretation: The formula and the name of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as
To determine: The formula and the name of the binary compound formed from
(a)
Answer to Problem 134AE
Answer
Calcium nitride
Explanation of Solution
Calcium belongs to the Group
Nitrogen is a non-metal of the
Hence, its oxidation state
So, the formula of the given compound is
The name of the cation present is Calcium
The anion present is Nitride
Calcium only exists in
Hence, the naming of this binary compound is, Calcium nitride.
While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.
(b)
Interpretation: The formula and the name of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as
To determine: The formula and the name of the binary compound formed from
(b)
Answer to Problem 134AE
Answer
Potassium oxide
Explanation of Solution
Potassium belongs to the Group
Oxygen belongs to the
Hence, its oxidation state
So, the formula of the given compound is
The name of the cation present is Potassium
The anion present is Oxide
Potassium only exists in
Hence, the naming of this binary compound is, Potassium oxide.
While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.
(c)
Interpretation: The formula and the name of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as
To determine: The formula and the name of the binary compound formed from
(c)
Answer to Problem 134AE
Answer
Rubidium fluoride
Explanation of Solution
Explanation
Rubidium belongs to the Group
Fluorine belongs to the
Hence, its oxidation state
So, the formula of the given compound is
The name of the cation present is Rubidium
The anion present is Fluoride
Hence, the naming of this binary compound is, Rubidium fluoride.
While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.
(d)
Interpretation: The formula and the name of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as
To determine: The formula and the name of the binary compound formed from
(d)
Answer to Problem 134AE
Answer
Magnesium sulphide
Explanation of Solution
Explanation
Magnesium belongs to the Group
Sulphur belongs to the
Hence, its oxidation state
So, the formula of the given compound is
The name of the cation present is Magnesium
The anion present is Sulphide
Hence, the naming of this binary compound is, Magnesium sulphide.
While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.
(e)
Interpretation: The formula and the name of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as
To determine: The formula and the name of the binary compound formed from
(e)
Answer to Problem 134AE
Answer
Barium iodide
Explanation of Solution
Explanation
Barium belongs to the Group
Iodine belongs to the
Hence, its oxidation state
So, the formula of the given compound is
The name of the cation present is Barium
The anion present is Iodide
Hence, the naming of this binary compound is, Barium iodide.
While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.
(f)
Interpretation: The formula and the name of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as
(f)
Answer to Problem 134AE
Answer
Aluminium selenide
To determine: The formula and the name of the binary compound formed from
Explanation of Solution
Explanation
Aluminium belongs to the Group
Selenium belongs to the
Hence, its oxidation state
So, the formula of the given compound is
The name of the cation present is Aluminium
The anion present is Selenide
Hence, the naming of this binary compound is, Aluminium selenide.
While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.
(g)
Interpretation: The formula and the name of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as
To determine: The formula and the name of the binary compound formed from
(g)
Answer to Problem 134AE
Answer
Cesium phosphide
Explanation of Solution
Explanation
Cesium belongs to the Group
Phosphorous belongs to the
Hence, its oxidation state
So, the formula of the given compound is
The name of the cation present is Cesium
The anion present is Phosphide
Hence, the naming of this binary compound is, Cesium phosphide.
While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.
(h)
Interpretation: The formula and the name of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as
To determine: The formula and the name of the binary compound formed from
(h)
Answer to Problem 134AE
Answer
Indium (III) bromide
Explanation of Solution
Explanation
Indium has an oxidation state of
Oxidation state exhibited by Bromine is
So, the formula of the given compound is
The name of the cation present is Indium
The anion present is Bromide
Here, indium exhibits the
Hence, the naming of this binary compound is, Indium (III) bromide.
While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.
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Chapter 3 Solutions
Chemistry: An Atoms First Approach
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