Basics Of Engineering Economy
2nd Edition
ISBN: 9780073376356
Author: Leland Blank, Anthony Tarquin
Publisher: MCGRAW-HILL HIGHER EDUCATION
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Chapter 3, Problem 11P
To determine
Calculate the interest rate.
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The present worth of a deposit of $1000 now and $1000 every 6 months for 10 years at an interest rate of 10% per year, compounded semiannually is represented by which of the following equations: (a) P = 1000(P∕A,5%,21)(F∕P,5%,1) (b) P = 1000 (P∕A,5%,20) (c) P = 1000 (P∕A,5%,21) (d) P = 1000 + 1000(P∕A,10.25%,10)
Chapter 3 Solutions
Basics Of Engineering Economy
Ch. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Prob. 3PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Convert an interest rate of 1.5% per month into a...Ch. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Prob. 9PCh. 3 - Prob. 10P
Ch. 3 - Prob. 11PCh. 3 - Prob. 12PCh. 3 - Prob. 13PCh. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 19PCh. 3 - Prob. 20PCh. 3 - Prob. 21PCh. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Prob. 25PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - Prob. 30PCh. 3 - Prob. 31PCh. 3 - Prob. 32PCh. 3 - Prob. 33PCh. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - Prob. 40PCh. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Erbitux is a colorectal cancer treatment drug that...Ch. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - Prob. 47PCh. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 51PCh. 3 - Prob. 52PCh. 3 - Prob. 53PCh. 3 - Prob. 54PCh. 3 - Prob. 55PCh. 3 - Prob. 56PCh. 3 - Prob. 57PCh. 3 - Prob. 58PCh. 3 - The initial cost of a pulverized coal cyclone...Ch. 3 - Prob. 60PCh. 3 - Prob. 61PCh. 3 - Prob. 62PCh. 3 - Prob. 63PCh. 3 - Prob. 64PCh. 3 - Prob. 65PCh. 3 - Prob. 66PCh. 3 - Prob. 67PCh. 3 - Prob. 68APQCh. 3 - Prob. 69APQCh. 3 - Prob. 70APQCh. 3 - Prob. 71APQCh. 3 - Prob. 72APQCh. 3 - Prob. 73APQCh. 3 - Prob. 74APQCh. 3 - Prob. 75APQCh. 3 - Prob. 76APQ
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- The present worth of a deposit of $1000 now and $1000 every 6 months for 10 years at an interest rate of 10% per year, compounded semiannually is represented by which of the following equations: Select one: a. P = 1000 + 1000(P/A,10.25%,10) b. P = 1000 (P/A,5%,21) c. P = 1000(P/A,5%,21)(F/P,5%,1) %3D d. P = 1000 (P/A,5%,20)arrow_forwardYou place $100 per month into an account that earns 1% per month. Which of the following expressions can be used to calculate the account’s value after 3 years? (a) P = 100(P/A, 1%, 3) (b) F = 100(P/A, 1%, 36)(F/P, 1%, 36) (c) F = 100[(1 + 0.01) n − 1]/0.01 (d) F = 100(F/A, 12.68%, 3)arrow_forwardBid 1: 9% per year, compounded quarterly Bid 2: 3% per quarter, compounded quarterly Bid 3: 8.8% per year, compounded monthly (a) Determine the effective rate for each bid on the basis of semiannual periods. (b) What are the effective annual rates? These are to be a part of the final bid selection. (c) Which bid has the lowest effective annual rate?arrow_forward
- (a) Calculate the amount deposited 1 year ago to have $1000 now at an interest rate of 5% per year. • (b) Calculate the amount of interest earned during this time period. please show me how you solved it mathematicallyarrow_forwardFor an interest rate of 10% per year, compounded quarterly, determine the number of times interest is compounded (a) per quarter, (b) per 6 months, (c) per year, and (d) per 3 years.arrow_forwardA commercial real estate developer plans to borrow money to finance an upscale mall in an exclusive area of the city. The developer plans to get a loan that will be repaid with uniform payments of $425,000 beginning in year 2 and ending in year 16. How much will a bank be willing to loan at an interest rate of 6% per year? The bank will be willing to loan the developer a sum of $|arrow_forward
- If you make quarterly deposits for 3 years (beginning one quarter from now) into an account that compounds interest at 1% per month, the value of n in the F∕A factor (for determining F at the end of the 3-year period) is: (a) 3 (b) 4 (c) 12 (d ) 16arrow_forwardA certain sum of money will be deposited in a savings account that pays interest at the rate of 6% per year, compounded annually. If all of the money is allowed to accumulate, how much must be deposited initially so that $5,000 will have accumulated after 10 yearsarrow_forwardEXAMPLE 1.4 / HP borrowed money to do rapid prototyping for a new ruggedized computer that targets desert oilfield conditions. The loan is $1 million for 3 years at 5% per year simple interest. How much money will HP repay at the end of 3 years? Tabulate the results in $1000 units. EXAMPLE 1.5 / If HP borrows $1,000,000 from a different source at 5% per year compound interest, compute the total amount due after 3 years. Compare the results of this and the previous example. Comment : The difference between simple and compound interest grows signif- icantly each year. If the computations are continued for more years, for exam- ple, 10 years, the difference is $128.894; after 20 years compound interest is $653.298 more than simple interest.arrow_forward
- INDICATE A CASH FLOW DIAGRAM For an interest rate of 3% per quarter, determine the nominal interest rate per (a) semiannual period, (b) year, (c) 2 years.arrow_forwardWhat is the amount generated by a capital of $10,000 applied to compound interest for the following terms and rates: Compound interest rate Deadline a) 1.5% per month 12 months b)3.0% per quarter 30 years c) 18% per semester 2 yearsarrow_forwardAn interest rate of 18% per year, compounded continuously, is closest to an effective: (a) 1.51% per quarter (b) 4.5% per quarter (c) 4.6% per quarter (d) 9% per 6 monthsarrow_forward
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