(a)
Interpretation:
The name of compound using Roman numeral to show the charge on a
Concept Introduction:
The name of the compound written by writing the name of cation followed by the name of anion with either suffix -ate or -ide depending upon the group to which the atom belongs. The name of the cation is written same as the name of metal. The charge on the metal atom is its oxidation state and it can be written in roman numeral as follows:
1-(I), 2-(II), 3-(III), 4-(IV) and so on.
(b)
Interpretation:
The name of compound using Roman numeral to show the charge on a transition metal ion should be identified.
Concept Introduction:
The name of the compound written by writing the name of cation followed by the name of anion with either suffix -ate or -ide depending upon the group to which the atom belongs. The name of the cation is written same as the name of metal. The charge on the metal atom is its oxidation state and it can be written in roman numeral as follows:
1-(I), 2-(II), 3-(III), 4-(IV) and so on.
(c)
Interpretation:
The name of compound using Roman numeral to show the charge on a transition metal ion should be identified.
Concept Introduction:
The name of the compound written by writing the name of cation followed by the name of anion with either suffix -ate or -ide depending upon the group to which the atom belongs. The name of the cation is written same as the name of metal. The charge on the metal atom is its oxidation state and it can be written in roman numeral as follows:
1-(I), 2-(II), 3-(III), 4-(IV) and so on.
(d)
Interpretation:
The name of compound using Roman numeral to show the charge on a transition metal ion should be identified.
Concept Introduction:
The name of the compound written by writing the name of cation followed by the name of anion with either suffix -ate or -ide depending upon the group to which the atom belongs. The name of the cation is written same as the name of metal. The charge on the metal atom is its oxidation state and it can be written in roman numeral as follows:
1-(I), 2-(II), 3-(III), 4-(IV) and so on.
(e)
Interpretation:
The name of compound using Roman numeral to show the charge on a transition metal ion should be identified.
Concept Introduction:
The name of the compound written by writing the name of cation followed by the name of anion with either suffix -ate or -ide depending upon the group to which the atom belongs. The name of the cation is written same as the name of metal. The charge on the metal atom is its oxidation state and it can be written in roman numeral as follows:
1-(I), 2-(II), 3-(III), 4-(IV) and so on.
(f)
Interpretation:
The name of compound using Roman numeral to show the charge on a transition metal ion should be identified.
Concept Introduction:
The name of the compound written by writing the name of cation followed by the name of anion with either suffix -ate or -ide depending upon the group to which the atom belongs. The name of the cation is written same as the name of metal. The charge on the metal atom is its oxidation state and it can be written in roman numeral as follows:
1-(I), 2-(II), 3-(III), 4-(IV) and so on.
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Chapter 3 Solutions
Introduction To General, Organic, And Biochemistry
- Name each ionic compound. In each of these compounds, the metal forms more than one type of ion. (a) CrCl2 (b) C:CI3 (c) SnO2 (d) Pbl2arrow_forwardWrite the name of each of the following substances: (W (a) (HCOO)2Ni-½H2O (b) Zn(SCN)2 (c) Ag2CrO4 (d) HIO2(aq)arrow_forward4) 2 2 NaHCO3 (s) ----> 2 C(s) + 3 Na(s) + 02(g) 1 H2(g) +arrow_forward
- write a balanced chemical equation for each (A) Iron (III) chloride reacts with sodium hydroxide to produce iron (III) hydroxide and sodium chloride. (B) Magnesium nitrite reacts with perchloric acid to produce magnesium perchlorate and nitrous acid. (C) Copper(II) hydroxide reacts with hydrosulfuric acid to produce copper (II) sulfide and water.arrow_forwardName each ionic compound. In each of these compounds, the metal forms more than one type of ion.(a)SnCl4(b)CuI2(c)Fe2O3(d)HgBr2arrow_forwardAssume that you encounter the following phrases in your reading. What is the chemical formula for each substance mentioned? (a) Sodium Hydrogen carbonate is used as a deodorant. (b) Calcium hypochlorite is used in some bleaching solutions. (c) Hydrogen cyanide is a very poisonous gas. (d) Magnesium hydroxide is used as a cathartic. (e) Tin (II) fluoride has been used as a fluoride additive in toothpastes. (f) When cadmium sulfide is treated with sulfuric acid, fumes of hydrogen sulfide are given off.arrow_forward
- Write the empirical formula of the compound formed by (a) Al3+ and Cl - ions, (b) Al 3+ and O2 - ions, (c) Mg2+ and NO3 ions.arrow_forwardWrite the empirical formula of the compound formed by (a) Al3+ and Cl- ions, (b) Al3+ and O2 - ions, (c) Mg2+ and NO3- ions.arrow_forwardAnswer true or false. (a) The name of a binary ionic compound consists of the name of the positive ion followed by the name of the negative ion. (b) In naming binary ionic compounds, it is necessary to state the number of each ion present in the compound. (c) The formula of aluminum oxide is Al2 O3 . (d) Both copper(II) oxide and cupric oxide are acceptable names for CuO. (e) The systematic name for Fe2 O3 is iron(II) oxide. (f) The systematic name for FeCO3 is iron carbonate. (g) The systematic name for NaH2PO4 is sodium di- hydrogen phosphate. (h) The systematic name for K2HPO4 is dipotassium hydrogen phosphate. (i) The systematic name for Na2O is sodium oxide. (j) The systematic name for PCl3 is potassium chloride. (k) The formula of ammonium carbonate is NH4CO3. 39. (a) A covalent bond is formed between two atoms whose difference in electronegativity is less than 1.9. (b) If the difference in electronegativity between two atoms is zero (they have identical electronegativ- ities),…arrow_forward
- 1) A sample of blue crystals of copper (II) sulfate pentahydrate was heated to produce the copper(Il)sulfate tetrahydrate. (a) Write the chemical formulas of the copper(II)sulfate pentahydrate and copper(II)sulfate tetrahydrate. (b) Calculate mass percent of water in copper(II)sulfate pentahydrate (c) If 7.491 g of the copper (II) sulfate pentahydrate produces 6.951 g of the copper (II) sulfate tetrahydrate, how many grams of anhydrous copper(I1)sulfate could be obtained? (Cu=63.5 g/mol, S=32.0 g/mol, O=16.0 g/mol, H=1 g/mol)arrow_forwardProvide correct names for the following compounds. (a) (b) CI (c) (d) LOCH3 (e) (f) OCH3 Br Br NO2arrow_forward3. Consider the nickel salt: (NH4 )2Ni(SO4 )2 ·y H2O (Ammonium Nickel Sulfate Hydrate), where y is the number of coordinated waters. (a) Assuming that the product is anhydrous (y = 0), what is the theoretical yield of ammonium nickel sulfate from 1.500 g of Ni (s)? (b) The actual yield of product was 9.640 g - obviously containing coordinated water. The product was then heated strongly until all the water had been driven off. The resulting anhydrous salt had mass 7.000 g. What is the value of y? (c) Based on the mass of the anhydrous product (7.000 g), what is the % yield of the reaction?arrow_forward
- Introduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage Learning