Explanation Write the expression for energy of the electron shielded from the electric field. E = − ( Z − 1 ) 2 13.6 eV n 2 (I) Here, E is the energy of the electron state ( n = 2 ) , Z is the atomic number of the chromium atom, and n is the transition state of electron. Write the expression for final energy of the electron shielded from the electric field. E ′ = ( Z ) 2 13.6 eV n 2 (II) Here, E is the energy of the electron state ( n = 2 ) , Z is the atomic number of the chromium atom, and n is the transition state of electron. Write the expression for magnitude of the energy emitted by the atom. | Δ E | = E ′ − E (III) Here, Δ E is the magnitude of the electron’s energy loss and E ′ is the energy of the electron state ( n = 1 ) Write the expression for the investment energy to change ion from atom. E ionize = ( Z − 22 ) 2 13.6 eV n 2 (IV) Here, E ionize is the ionization energy of the chromium atom. Write the expression for remaining energy appeared as kinetic energy. K = Δ E − E ionize (V) Here, K is the kinetic energy. Conclusion: Substitute 2 for n and 24 for Z (chromium atom) in equation (I) to find transition energy for n = 2 . E = − ( 24 − 1 ) 2 13.6 eV ( 1 2 2 ) = − 1.80 × 10 3 eV ( 10 − 3 keV 1 eV ) = − 1

Principles of Physics: A Calculus-Based Text

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Author: Raymond A. Serway, John W. Jewett

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Chapter 29, Problem 65P

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The kinetic energy of the Auger electron.

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Chapter 29, Problem 64P

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Chapter 29 Solutions

Principles of Physics: A Calculus-Based Text

Ch. 29.2 - Prob. 29.1QQ Ch. 29.2 - Prob. 29.2QQ Ch. 29.4 - Prob. 29.3QQ Ch. 29.5 - Prob. 29.4QQ Ch. 29.6 - Prob. 29.5QQ Ch. 29.6 - Prob. 29.6QQ Ch. 29 - Prob. 1OQ Ch. 29 - Prob. 2OQ Ch. 29 - Prob. 3OQ Ch. 29 - Prob. 4OQ

Ch. 29 - Prob. 5OQ Ch. 29 - Prob. 6OQ Ch. 29 - Prob. 7OQ Ch. 29 - Prob. 8OQ Ch. 29 - Prob. 9OQ Ch. 29 - Prob. 10OQ Ch. 29 - Prob. 1CQ Ch. 29 - Prob. 2CQ Ch. 29 - Prob. 3CQ Ch. 29 - Prob. 4CQ Ch. 29 - Prob. 5CQ Ch. 29 - Prob. 6CQ Ch. 29 - Prob. 7CQ Ch. 29 - Prob. 8CQ Ch. 29 - Prob. 9CQ Ch. 29 - Prob. 10CQ Ch. 29 - Prob. 1P Ch. 29 - Prob. 2P Ch. 29 - Prob. 3P Ch. 29 - Prob. 4P Ch. 29 - Prob. 5P Ch. 29 - Prob. 6P Ch. 29 - Prob. 7P Ch. 29 - Prob. 8P Ch. 29 - Prob. 10P Ch. 29 - Prob. 11P Ch. 29 - Prob. 12P Ch. 29 - Prob. 13P Ch. 29 - Prob. 14P Ch. 29 - Prob. 15P Ch. 29 - Prob. 16P Ch. 29 - Prob. 17P Ch. 29 - Prob. 18P Ch. 29 - Prob. 19P Ch. 29 - Prob. 20P Ch. 29 - Prob. 21P Ch. 29 - Prob. 22P Ch. 29 - Prob. 23P Ch. 29 - Prob. 24P Ch. 29 - Prob. 25P Ch. 29 - Prob. 26P Ch. 29 - Prob. 27P Ch. 29 - Prob. 28P Ch. 29 - Prob. 29P Ch. 29 - Prob. 30P Ch. 29 - Prob. 31P Ch. 29 - Prob. 32P Ch. 29 - Prob. 33P Ch. 29 - Prob. 34P Ch. 29 - Prob. 35P Ch. 29 - Prob. 36P Ch. 29 - Prob. 37P Ch. 29 - Prob. 38P Ch. 29 - Prob. 39P Ch. 29 - Prob. 40P Ch. 29 - Prob. 41P Ch. 29 - Prob. 42P Ch. 29 - Prob. 43P Ch. 29 - Prob. 44P Ch. 29 - Prob. 45P Ch. 29 - Prob. 46P Ch. 29 - Prob. 47P Ch. 29 - Prob. 48P Ch. 29 - Prob. 49P Ch. 29 - Prob. 50P Ch. 29 - Prob. 51P Ch. 29 - Prob. 52P Ch. 29 - Prob. 53P Ch. 29 - Prob. 54P Ch. 29 - Prob. 55P Ch. 29 - Prob. 57P Ch. 29 - Prob. 58P Ch. 29 - Prob. 59P Ch. 29 - Prob. 60P Ch. 29 - Prob. 61P Ch. 29 - Prob. 63P Ch. 29 - Prob. 64P Ch. 29 - Prob. 65P Ch. 29 - Prob. 66P

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