College Physics: A Strategic Approach (4th Edition)
4th Edition
ISBN: 9780134609034
Author: Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher: PEARSON
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Question
Chapter 29, Problem 56GP
a.
To determine
Repulsive electric force between two protons.
b.
To determine
The attractive gravitational force between two protons.
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Students have asked these similar questions
What electrostatic force acts between two protons in a nucleus if they are 4×10-15 m apart?
Select one:
O a. 8.8x109 (attractive)
O b. 8.8×10 (repulsive)
O c. 14N (repulsive)
O d. 14N (attractive)
10. An electron has been placed at the origin. The grid spacing is 1 Angstrom per small square this time. Now you have a nucleus with 18 protons at x = 2.1 Angstroms on the x-axis. How much work would it take to bring in ANOTHER nucleus with 14 protons from 1 m away and place it at y = 8.0 Angstroms on the y-axis?
165.2 eV
413.1 eV
-25.2 eV
438.2 eV
In Rutherford's famous scattering experiments that led
to the planetary model of the atom, alpha particles (having
charges of +2e and masses of 6.64 x 10-27 kg) were fired
toward a gold nucleus with charge +79e. An alpha particle,
Chapter 29 Solutions
College Physics: A Strategic Approach (4th Edition)
Ch. 29 - Prob. 1CQCh. 29 - Prob. 2CQCh. 29 - Prob. 3CQCh. 29 - Prob. 4CQCh. 29 - Prob. 5CQCh. 29 - Prob. 6CQCh. 29 - Prob. 7CQCh. 29 - Prob. 8CQCh. 29 - Prob. 9CQCh. 29 - Prob. 10CQ
Ch. 29 - Prob. 11CQCh. 29 - Prob. 12CQCh. 29 - Prob. 13CQCh. 29 - Prob. 14CQCh. 29 - Prob. 15CQCh. 29 - Prob. 16CQCh. 29 - Prob. 17CQCh. 29 - Prob. 18CQCh. 29 - Prob. 20CQCh. 29 - Prob. 21CQCh. 29 - Prob. 22CQCh. 29 - Prob. 23CQCh. 29 - Prob. 24CQCh. 29 - Prob. 25CQCh. 29 - Prob. 27MCQCh. 29 - Prob. 28MCQCh. 29 - Prob. 29MCQCh. 29 - Prob. 30MCQCh. 29 - Prob. 31MCQCh. 29 - Prob. 32MCQCh. 29 - Prob. 1PCh. 29 - Prob. 2PCh. 29 - Prob. 3PCh. 29 - Prob. 4PCh. 29 - Prob. 5PCh. 29 - Prob. 6PCh. 29 - Prob. 7PCh. 29 - Prob. 8PCh. 29 - Prob. 9PCh. 29 - Prob. 10PCh. 29 - Prob. 11PCh. 29 - Prob. 12PCh. 29 - Prob. 13PCh. 29 - Prob. 14PCh. 29 - Prob. 15PCh. 29 - Prob. 16PCh. 29 - Prob. 17PCh. 29 - Prob. 18PCh. 29 - Prob. 19PCh. 29 - Prob. 20PCh. 29 - Prob. 21PCh. 29 - Prob. 22PCh. 29 - Prob. 23PCh. 29 - Prob. 24PCh. 29 - Prob. 25PCh. 29 - Prob. 27PCh. 29 - Prob. 28PCh. 29 - Prob. 29PCh. 29 - Prob. 30PCh. 29 - Prob. 31PCh. 29 - Prob. 32PCh. 29 - Prob. 33PCh. 29 - Prob. 34PCh. 29 - Prob. 35PCh. 29 - Prob. 36PCh. 29 - Prob. 37PCh. 29 - Prob. 39PCh. 29 - Prob. 40PCh. 29 - Prob. 41PCh. 29 - Prob. 42PCh. 29 - Prob. 43PCh. 29 - Prob. 45PCh. 29 - Prob. 46PCh. 29 - Prob. 47PCh. 29 - Prob. 48PCh. 29 - Prob. 49PCh. 29 - Prob. 50PCh. 29 - Prob. 51PCh. 29 - Prob. 52GPCh. 29 - Prob. 53GPCh. 29 - Prob. 54GPCh. 29 - Prob. 55GPCh. 29 - Prob. 56GPCh. 29 - Prob. 57GPCh. 29 - Prob. 58GPCh. 29 - Prob. 59GPCh. 29 - Prob. 60GPCh. 29 - Prob. 61GPCh. 29 - Prob. 62GPCh. 29 - Prob. 63GPCh. 29 - Prob. 64GPCh. 29 - Prob. 65GPCh. 29 - Prob. 66GPCh. 29 - Prob. 67GPCh. 29 - Prob. 69GPCh. 29 - Prob. 70MSPPCh. 29 - Prob. 71MSPPCh. 29 - Prob. 72MSPPCh. 29 - Prob. 73MSPPCh. 29 - Prob. 74MSPPCh. 29 - Prob. 75MSPPCh. 29 - Prob. 77MSPP
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- (a) An aspiring physicist wants to build a scale model of a hydrogen atom for her science fair project. If the atom is 1.00 m in diameter, how big should she try to make the nucleus? (b) How easy will this be to do?arrow_forward(a) How many electrons can be in the n=4 shell? (b) What are its subshells, and how many electrons can be in each?arrow_forwardThis problem demonstrates that the binding energy of the electron in the ground state of a hydrogen atom is much smaller than the rest mass energies of the proton and electron. Calculate the mass equivalent in u of the 13.6-eV binding energy of an electron in a hydrogen atom, and compare this with the known mass of the hydrogen atom. Subtract the known mass of the proton from the known mass of the hydrogen atom. Take the ratio of the binding energy of the electron (13.6 eV) to the energy equivalent of the electron’s mass (0.511 MeV). Discuss how your answers confirm the stated purpose of this problem.arrow_forward
- (a) Show that if you assume the average nucleus is spherical with a radius r=r0A1/3, and with a mass at A u, then its density is independent at A. (b) Calculate that density in u/fm3 and kg/m3, and compare your results with those found in Example 31.1 for 56Fe.arrow_forward(a) What voltage must be applied to an X-ray tube to obtain 0.0100-fm-wavelength X-rays for use in exploring the details of nuclei? (b) What is unreasonable about this result? (c) Which assumptions are unreasonable or inconsistent?arrow_forwardWhen a nucleus (decays, does the (particle move continuously from inside the nucleus to outside? That is, does it travel each point along an imaginary line from inside to out? Explain.arrow_forward
- Direction: Answer the following.1. This particle is found in the nucleus and has no chargea. Neutron b. Proton c. Electron d. Orbital2. This particle is found in the nucleus and has a positive chargea. Electron b. Proton c. Neutron d. Neutral3. This is a negatively charged particle found outside the nucleusa. Electron b. Proton c. Neutron d. Neutral4. What is the Law of Conservation of mass?a. Mass is created in a chemical reactionb. Mass is created in a physical changec. New chemicals formed from a chemical reaction have a largeroverall mass than the original reactantsd. Mass is never created or destroyed5. Which of the following are Subscripts in this Chemical Formula: 3Fe2O4a. 3,4b. 3,2c. 2,4arrow_forward2. The nuclear radius of gold is approximately r = 7.0 fm (1.0 fm = 1.0 × 10-15 m). The radii of protons and a particles are 1.3 fm and 2.6 fm, respectively. (a) What energy a particles would be needed in head-on collision for the nuclear surfaces to just touch? (This is about where the nuclear force becomes effective.) (b) What energy protons would be needed?arrow_forwardParticle Electron Proton Neutron Relative Charge -1 +1 0 What is: Electric Charge (C) -1.60 x 10-19 +1.60 x 10-19 0 a) The mass defect? Relative Mass (u) 5.485779 x 10-4 1.007276 1.008665 1u = 1.6605 x 10-27 kg 1eV = 1.60 x 10-19 Joules The 'cheating' equivalence shortcut 1u- 931.5 MeV He is the most abundant isotope of helium. Its mass is 6.6447x 10-27kg. Mass (kg) b) The binding energy of the nucleus in joules? 9.109390 x 10-31 1.672623 x 10-27 1.674929 x 10-27arrow_forward
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