College Physics: A Strategic Approach (4th Edition)
4th Edition
ISBN: 9780134609034
Author: Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher: PEARSON
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Chapter 29, Problem 2P
To determine
The wavelength’s of first four members of the series.
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The wavelengths of the Lyman series for hydrogen are given by = RH(1-2), = 2, 3, 4, ...
1/2
(a) Calculate the wavelengths of the first three lines in this series.
nm
nm
nm
(b) Identify the region of the electromagnetic spectrum in which these lines appear.
O ultraviolet region
O infrared region
O x-ray region
O visible light region
O gamma ray region
The wavelengths of the Lyman series for hydrogen are given by
1
λ
= RH
1 −
1
n2
,n = 2, 3, 4, . . .
(a) Calculate the wavelengths of the first three lines in this series.
nm
nm
nm
(b) Identify the region of the electromagnetic spectrum in which these lines appear.
infrared regionvisible light region x-ray regionultraviolet regiongamma ray region
Calculate the wavelengths of the first four spectral lines in the Lyman series of
the hydrogen spectrum.
Chapter 29 Solutions
College Physics: A Strategic Approach (4th Edition)
Ch. 29 - Prob. 1CQCh. 29 - Prob. 2CQCh. 29 - Prob. 3CQCh. 29 - Prob. 4CQCh. 29 - Prob. 5CQCh. 29 - Prob. 6CQCh. 29 - Prob. 7CQCh. 29 - Prob. 8CQCh. 29 - Prob. 9CQCh. 29 - Prob. 10CQ
Ch. 29 - Prob. 11CQCh. 29 - Prob. 12CQCh. 29 - Prob. 13CQCh. 29 - Prob. 14CQCh. 29 - Prob. 15CQCh. 29 - Prob. 16CQCh. 29 - Prob. 17CQCh. 29 - Prob. 18CQCh. 29 - Prob. 20CQCh. 29 - Prob. 21CQCh. 29 - Prob. 22CQCh. 29 - Prob. 23CQCh. 29 - Prob. 24CQCh. 29 - Prob. 25CQCh. 29 - Prob. 27MCQCh. 29 - Prob. 28MCQCh. 29 - Prob. 29MCQCh. 29 - Prob. 30MCQCh. 29 - Prob. 31MCQCh. 29 - Prob. 32MCQCh. 29 - Prob. 1PCh. 29 - Prob. 2PCh. 29 - Prob. 3PCh. 29 - Prob. 4PCh. 29 - Prob. 5PCh. 29 - Prob. 6PCh. 29 - Prob. 7PCh. 29 - Prob. 8PCh. 29 - Prob. 9PCh. 29 - Prob. 10PCh. 29 - Prob. 11PCh. 29 - Prob. 12PCh. 29 - Prob. 13PCh. 29 - Prob. 14PCh. 29 - Prob. 15PCh. 29 - Prob. 16PCh. 29 - Prob. 17PCh. 29 - Prob. 18PCh. 29 - Prob. 19PCh. 29 - Prob. 20PCh. 29 - Prob. 21PCh. 29 - Prob. 22PCh. 29 - Prob. 23PCh. 29 - Prob. 24PCh. 29 - Prob. 25PCh. 29 - Prob. 27PCh. 29 - Prob. 28PCh. 29 - Prob. 29PCh. 29 - Prob. 30PCh. 29 - Prob. 31PCh. 29 - Prob. 32PCh. 29 - Prob. 33PCh. 29 - Prob. 34PCh. 29 - Prob. 35PCh. 29 - Prob. 36PCh. 29 - Prob. 37PCh. 29 - Prob. 39PCh. 29 - Prob. 40PCh. 29 - Prob. 41PCh. 29 - Prob. 42PCh. 29 - Prob. 43PCh. 29 - Prob. 45PCh. 29 - Prob. 46PCh. 29 - Prob. 47PCh. 29 - Prob. 48PCh. 29 - Prob. 49PCh. 29 - Prob. 50PCh. 29 - Prob. 51PCh. 29 - Prob. 52GPCh. 29 - Prob. 53GPCh. 29 - Prob. 54GPCh. 29 - Prob. 55GPCh. 29 - Prob. 56GPCh. 29 - Prob. 57GPCh. 29 - Prob. 58GPCh. 29 - Prob. 59GPCh. 29 - Prob. 60GPCh. 29 - Prob. 61GPCh. 29 - Prob. 62GPCh. 29 - Prob. 63GPCh. 29 - Prob. 64GPCh. 29 - Prob. 65GPCh. 29 - Prob. 66GPCh. 29 - Prob. 67GPCh. 29 - Prob. 69GPCh. 29 - Prob. 70MSPPCh. 29 - Prob. 71MSPPCh. 29 - Prob. 72MSPPCh. 29 - Prob. 73MSPPCh. 29 - Prob. 74MSPPCh. 29 - Prob. 75MSPPCh. 29 - Prob. 77MSPP
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- When the absorption spectrum of hydrogen at room temperature is analyzed, absorption lines for the Lyman series are found, but none are found for the Balmer series. What does this tell us about the energy state of most hydrogen atoms at room temperature?arrow_forwardThe Balmer series for hydrogen was discovered before either the Lyman or the Paschen series. Why?arrow_forwardIn extreme-temperature environments, such as those existing in a solar corona, atoms may be ionized by undergoing collisions with other atoms. One example of such ionization in the solar corona is the presence of C5+ ions, detected in the Fraunhofer spectrum. (a) By what factor do the energies of the C5+ ion scale compare to the energy spectrum of a hydrogen atom? (b) What is the wavelength of the first line in the Paschen series of C5+ ? (c) In what part of the spectrum are these lines located?arrow_forward
- Calculate the wavelength of the first line in the Lyman series and show that this line lies in the ultraviolet part of the spectrum.arrow_forwardDo the Balmer series and the Lyman series overlap? Why? Why not? (Hint: calculate the shortest Balmer line and the longest Lyman line.)arrow_forwardThe work function for potassium is 2.26 eV. What is the cutoff frequency when this metal is used as photoelectrode? What is the stopping potential when for the emitted electrons when this photo electrode is exposed to radiation of frequency 1200 THz?arrow_forward
- Using the Rydberg formula, calculate the wavelengths of the first four spectral lines in the Lyman series of the hydrogen spectrum.arrow_forwardIn hydrogen’s characteristic spectra, each series (Lyman, Balmer, etc) has a “series limit”, where the wavelengths at one end of the series tend to “bunch up”, approaching a single limiting value. part a: Is it at the short-wavelength or the long-wavelength end of the series that this series limit occurs? part b: What is it about hydrogen’s allowed energies that leads to this phenomenon?arrow_forwardThe Balmer series consists of the spectral lines from hydrogen for an electron making a transition from an excited state to the m = 2 state. The Lyman series consists of the spectral lines from hydrogen for an electron making a transition from an excited state to the m = 1 state. Determine the wavelengths of the first four spectral lines of the Lyman series (n = 2, 3, 4, and 5). 12 = m 13 = 14 = E E E Earrow_forward
- The shortest wavelength of the hydrogen Lyman series is 91.13 nm. Find the three longest wavelengths in this series.arrow_forwardThe wavelengths of the Lyman series for hydrogen are given by: = RH(1-1), n = 2, 3, 4, ... For the second of this series; calculate the energy (in eV). Note: 1.60 x 10^-19 J = 1.0 eV O 4.10 x 10^3 eV 2.12 x 10^3 eV 3² O 1.21 x 10^3 eV 3.30 x 10^3 eVarrow_forwardThe Lyman series of photons each have an energy capable of exciting the electron of a hydrogen atom from the ground state (energy level 1) to energy levels 2, 3, 4, etc. The wavelengths of the first five photons in this series are 121.6 nm, 102.6 nm, 97.3 nm, 95.0 nm, and 93.8 nm. The ground state energy of hydrogen is −13.6 eV. Based on the wavelengths of the Lyman series, calculate the energies of the first five excited states above ground level for a hydrogen atom to the nearest 0.1 eV.arrow_forward
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