Concept explainers
Interpretation:
The
Concept introduction:
Answer to Problem 1P
Explanation of Solution
The 3’ end of messenger ribonucleic acid can complement the 5’ end of the deoxyribonucleic acid transcribed from it. The deoxyribonucleic acid sequence can be represented from 5’ to 3’ as follows.
The amino group end of the aminoalkanoic acid sequence can start from the primary AUG sequence ranging from the 5’ end.
This ends up in the subsequent organic compound sequence as follows:
The 3’ end of ribonucleic acid can complement the 5’ end of the deoxyribonucleic acid transcribed from it. The N-terminal aminoalkanoic acid sequence can begin from the primary AUG sequence ranging from the 5’ end.
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Chapter 29 Solutions
Biochemistry
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- 5'– ATGGCGAGGCGGCAGCTGTTATGGTGA – 3' In the sequence above, suppose that the 20th nucleotide of the template (an T) was mutated to a A. (A) Now, what is the mRNA sequence? (B) What is the amino acid sequence of the translated protein? (C) Would this protein be able to carry out its function?arrow_forwardOriginal sequence: Consider the following coding 71 nucleotide DNA template sequence (It does not contain a translational start): 5’-GTTTCCCCTATGCTTCATCACGAGGGCACTGACATGTGTAAACGAAATTCCAACCTGAGCGGCGT GTTGAG-3’ Question: 4) In a mutant you discovered that the underlined nucleotide has been deleted. What would the resulting peptide sequence be? What type of mutation is this? 5’-GTTTCCCCTATGCTTCATCACGAGGGCACTGACATGTGTAAACGAAATTCCAACCTGAGCGGCGT GTTGAG-3arrow_forwardB Relates to the ribosome codon question please do ii ribosome coding questionsarrow_forward
- Why are some transposons medically important?arrow_forwardTemplate strand: 5' AATCATAACTCATTG 3' A. Write the CODING strand of this sequence, including the 5' and 3' end designations. B. Write the amino acid sequence coded by this mRNA. The start codon is the first codon in the sequence that codes for Met. First position (5'-end) U < G บบบ UUC phe UUA UUG CUU Couleu CUC Coc CUA CUG AUU AUG AUC ile GUU GUC GUA GUG Second position C UCU UCC UCA UCG val CCU co CCC CCA 000 CCG ACU ACC ACC AUA ACA thr AUA ACA AUG met ACG GCU GCC ser GCA GCG pro ala UAU ORD tyr UAC UAA Stop UAG Stop CAU CAC CAA CAG - AAU AAC www AAA 10 asn AAG 7 his GAU GAC GAA GAG gin }| lys asp glu UGU UGC cys UGA Stop UGG trp CGU C00 CGC CGA 000 CGG AGU AGC ACA AGA AGG GGU GGC GGA GGG Initiation Termination arg ser arg gly DUAL SUAU DUAU DUAG Third position (3-end)arrow_forwardPlz asaparrow_forward
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