Organic Chemistry (6th Edition)
Organic Chemistry (6th Edition)
6th Edition
ISBN: 9781260119107
Author: Janice Gorzynski Smith
Publisher: McGraw Hill Education
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Chapter 28.2, Problem 4P

Draw the mechanism for the radical polymerization of vinyl acetate (CH2-CHOCOCH3) using ((CH3)3CO-OC(CH3)3) as the initiator.

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Propylene does not undergo free radical polymerization readily because there are two competing steps after initiation: propagation and hydrogen atom abstraction.(a) Using a generic radical R• as a reactant with propylene, draw the mechanism and products for the two competing steps.(b) Which step produces the more stable product?(c) How do your results explain propylene’s poor reactivity in free radical polymerization?
When HBr adds to (CH3)2C = CH2 under radical conditions, two radicals are possible products in the first step of chain propagation. Draw the structure of both radicals and indicate which one is formed. Then draw the preferred product from HBr addition under radical conditions.
Styrene derivatives such as A can be polymerized by way of cationic rather than radical intermediates. Cationic polymerization is an example of electrophilic addition to an alkene involving carbocations. a.) Draw a short segment of the polymer formed by the polymerization ofA.b.) Why does A react faster than styrene (C6H5CH=CH2) in a cationicpolymerization?
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CBSE Class 12 Chemistry || Polymers || Full Chapter || By Shiksha House; Author: Best for NEET;https://www.youtube.com/watch?v=OxdJlS0xZ0Y;License: Standard YouTube License, CC-BY