Explanation Given data: Kinetic energy of the emitted electrons is 1.50eV. Wavelength of light is 250 nm. Formula used: Consider the work function equation. E = h c λ (1) Here, h is the planks constant, which has a standard value as 6.63 × 10 − 34 J ⋅ s , c is the speed of light , which has a standard value as 3 × 10 8 m s , and λ is the wavelength. Explanation: Substitute 6.63 × 10 − 34 J ⋅ s for h , 3 × 10 8 m s for c , and 250 nm for λ in equation (1), E = ( 6.63 × 10 − 34 J ⋅ s ) ( 3 × 10 8 m s ) 250nm = ( 6.63 × 10 − 34 J ⋅ s ) ( 3 × 10 8 m s ) 250 × 10 − 9 m = 0.0795 × 10 − 17 J Consider the conversion factor for J to eV

College Physics: A Strategic Approach (3rd Edition)

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Chapter 28, Problem 9P

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The maximum kinetic energy of the metal when illuminated by light with a wavelength of 250 nm.

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Chapter 28, Problem 8P

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Chapter 28 Solutions

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The maximum kinetic energy of the metal when illuminated by light with a wavelength of 250 nm.

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The maximum kinetic energy of the metal when illuminated by light with a wavelength of 250 nm.

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Chapter 28 Solutions