Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
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Chapter 28, Problem 61P
(a)
To determine
The rate at which battery supplies energy
(b)
To determine
The rate of joule heating in the resistor
(c)
To determine
The rate at which energy is stored in the inductor.
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59 In Fig. 27-51, R₁ = 20.0 2, R₂ = 10.0 2, and the ideal bat-
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Figure 27-51 Problem 59.
a S₁
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18 R₁ R₁
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The switch on an RC circuit is closed at t = 0. Given thate = 6.0 V, R = 92 Ω, and C = 28 mF, how much charge is on thecapacitor at time t = 4.0 ms?
C = 46 microF, R1 = 41 ohms, R2 = 25 ohms, R3 = 90 ohms, R4 = 45 ohms, t open = 620 microseconds, and a 20 V battery.
Chapter 28 Solutions
Physics for Scientists and Engineers
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- When the switch S is toggled to the left, the capacitor C charges through the resistor R. When the switch is toggled to the right, the capacitor discharges current through the patient's torso, modeled as the resistor Rtorso, allowing the heart's normal rhythm to be reestablished. (a) If the capacitor is initially uncharged with C = 7.75 µF and = 1220 V, find the value of R (in ohms) required to charge the capacitor to a voltage of 765 V in 1.70 s. Ω (b) If the capacitor is then discharged across the patient's torso with Rtorso = 1230 Ω, calculate the voltage (in V) across the capacitor after 5.50 ms.arrow_forwardWhen the switch S is toggled to the left, the capacitor C charges through the resistor R. When the switch is toggled to the right, the capacitor discharges current through the patient's torso, modeled as the resistor Rtorso, allowing the heart's normal rhythm to be reestablished. (a)If the capacitor is initially uncharged with C = 8.25 µF and = 1270 V, find the value of R (in ohms) required to charge the capacitor to a voltage of 755 V in 1.70 s. answer in Ω b) If the capacitor is then discharged across the patient's torso with Rtorso = 1260 Ω, calculate the voltage (in V) across the capacitor after 4.50 ms. answer in Varrow_forward95 In Fig. 27-79, E, = 6.00 V, = 12.0 V, R = 100 0, R, = 200 N, and R, = 300 N. One point of the circuit is grounded (V = the (a) size and (b) direction (up or down) of the current through resistance 1, the (c) size and (d) direction (left or right) of the current through resistance 2, and the (e) size and (f) direction of the current through resistance 3? (g) What is the electric potential at point A? 0), What arearrow_forward
- When the switch S is toggled to the left, the capacitor C charges through the resistor R. When the switch is toggled to the right, the capacitor discharges current through the patient's torso, modeled as the resistor Rtorso, allowing the heart's normal rhythm to be reestablished. (a) If the capacitor is initially uncharged with C = 7.00 µF and = 1270 V, find the value of R (in ohms) required to charge the capacitor to a voltage of 795 V in 1.70 s. Ω (b) If the capacitor is then discharged across the patient's torso with Rtorso = 1270 Ω, calculate the voltage (in V) across the capacitor after 4.50 ms.arrow_forward**57 Go In Fig. 30-63, R = 15 N, L = 5.0 H, the ideal battery has & = 10 V, and the fuse in the upper branch is an ideal 3.0 A fuse. It has Fuse R zero resistance as long as the cur- rent through it remains less than 3.0 L. A. If the current reaches 3.0 A, the fuse “blows" and thereafter has in- finite resistance. Switch S is closed Fig. 30-63 Problem 57. at time t= 0. (a) When does the fuse blow? (Hint: Equation 30-41 does not apply. Rethink Eq. 30-39.) (b) Sketch a graph of the current i through the inductor as a function of time. Mark the time at which the fuse blows.arrow_forwardAn initially uncharged capacitor is connected as shown. If the switch is closed at t0, the time it takes the capacitor to reach BO% of its final voltage is T. f the time constant of the circuit is t, determine T/r. R ww O16 22 5.0 3.0 1.9arrow_forward
- Suppose the following circuit is left open for a long time. 24 V 5000 Ω 80mF (a) What is the energy stored in the capacitor 90s after we close the switch? (b) What is the energy dissipated by the resistor during the first 90s since the switch is closed?arrow_forwardFor the circuit shown below, ε=22 V, L=7.5 mH, and R=6Ω. After steady state is reached with S1 closed and S2 open, at t=0, S2 is closed and S1 is opened. Determine (a) the current through L at t=0, (b) the current through L at t=4.5×10-4 s, (c) the voltage across R on the right at t=4.5×10-4 s, and (d) the rate at which current through L changes at t=4.5×10−4 s. The current through L at t=0 is__________A. The current through L at t=4.5×10-4 s is_____A. The voltage across R at t=4.5×10-4 s is______V. The rate at which current through L changes at t=4.5×10-4 s is______A/s.arrow_forwardWhen the switch S is toggled to the left, the capacitor C charges through the resistor R. When the switch is toggled to the right, the capacitor discharges current through the patient's torso, modeled as the resistor Rtorso, allowing the heart's normal rhythm to be reestablished. HINT (a) If the capacitor is initially uncharged with C = 8.50 µF and = 1260 V, find the value of R (in ohms) required to charge the capacitor to a voltage of 755 V in 1.30 s. Ω (b) If the capacitor is then discharged across the patient's torso with Rtorso = 1270 Ω, calculate the voltage (in V) across the capacitor after 4.50 ms. Varrow_forward
- (a) In the figure what value must R have if the current in the circuit is to be 1.3 mA? Take ₁ = 2.7 V, 8₂ = 5.3 V, and r₁= r₂ = 3.9 Q. (b) What is the rate at which thermal energy appears in R? ww www. (b) Number 12₂ (a) Number 1992.2 i 2.6 Units Units Ω W <arrow_forwardThe figure below shows a circuit with an open switch, an emf device, Ɛ = 21 V, and a resistor, R = 70 Q. If we assume the switch remains open, use the given values to find the potential difference between the following points. a b R d (a) Vb - Va V (b) Vc - Vb V (c) Vd - Vc V (d) Va - Vd Varrow_forwardV=6.23731 Varrow_forward
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