College Physics
2nd Edition
ISBN: 9780134601823
Author: ETKINA, Eugenia, Planinšič, G. (gorazd), Van Heuvelen, Alan
Publisher: Pearson,
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Chapter 27, Problem 9P
To determine
The average kinetic energy of an atom in an ideal gas at
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The work function of cesium is 2.1 eV.
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Determine the lowest frequency photon that can eject an electron from cesium.
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Part B
Determine the maximum possible kinetic energy in electron volts of a photoelectron ejected from the metal that absorbs a 320-nm photon.
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PHOTOELECTRIC EFFECT
I. Which of the following observations from the photoelectric effect is NOT VIOLATION of classical physics??
A. Light can eject electrons from semi conductive material
B. Light intensity does not influence the kinetic energy of ejected electrons
C. Electrons are ejected immediately after impact from light
II. According to wave theory, what is the nessesary to eject electrons from surface??
A. A frequency that is higher than that of the electrons at the surface
B. A very small number of photons
C. Enough energy to overcome the binding energy of the electrons
III. The minimum frequency of radiation at which electrons will be ejected is called the threshold frequently go. TRUE OR FALSE??
. Access and open the simulation link to get data and follow what to do.
https://applets.kcvs.ca/photoelectricEffect/PhotoElectric.html
A.
DIRECTION:
1. Choose five (5) metals
2. Determine the lowest frequency of photoelectrons and the wavelength
3. Re-draw Table 1 on a clean paper and enter the data
Table 1
Sample Metals
Lowest frequency to produce photoelectrons
(in Hz)
Wavelength (in nm)
1.
2.
3.
4.
5.
B. Choose one (1) metal and calculate the threshold frequency.
Chapter 27 Solutions
College Physics
Ch. 27 - Prob. 1RQCh. 27 - Prob. 2RQCh. 27 - Prob. 3RQCh. 27 - Prob. 4RQCh. 27 - Prob. 5RQCh. 27 - Prob. 6RQCh. 27 - Prob. 1MCQCh. 27 - Prob. 2MCQCh. 27 - Prob. 3MCQCh. 27 - Prob. 4MCQ
Ch. 27 - Prob. 5MCQCh. 27 - Prob. 6MCQCh. 27 - Prob. 7MCQCh. 27 - Prob. 8MCQCh. 27 - Prob. 9MCQCh. 27 - Multiple Choice Questions In which of the...Ch. 27 - Prob. 11MCQCh. 27 - Prob. 12MCQCh. 27 - Prob. 13CQCh. 27 - Prob. 14CQCh. 27 - Prob. 15CQCh. 27 - Prob. 16CQCh. 27 - Prob. 17CQCh. 27 - Prob. 18CQCh. 27 - Prob. 19CQCh. 27 - Prob. 20CQCh. 27 - Prob. 1PCh. 27 - Prob. 2PCh. 27 - Prob. 3PCh. 27 - Prob. 4PCh. 27 - 27.1 Black Body Radiation * EST Estimate the...Ch. 27 - Prob. 6PCh. 27 - Prob. 7PCh. 27 - Prob. 8PCh. 27 - Prob. 9PCh. 27 - Prob. 10PCh. 27 - Prob. 11PCh. 27 - Prob. 12PCh. 27 - Prob. 13PCh. 27 - Prob. 14PCh. 27 - Prob. 15PCh. 27 - Prob. 16PCh. 27 - Prob. 17PCh. 27 - Prob. 18PCh. 27 - Prob. 19PCh. 27 - Prob. 20PCh. 27 - Prob. 21PCh. 27 - Prob. 22PCh. 27 - Prob. 23PCh. 27 - Prob. 24PCh. 27 - Prob. 25PCh. 27 - Prob. 26PCh. 27 - Prob. 27PCh. 27 - Prob. 28PCh. 27 - Prob. 29PCh. 27 - Prob. 30PCh. 27 - Prob. 31PCh. 27 - Prob. 32PCh. 27 - Prob. 33PCh. 27 - Prob. 34PCh. 27 - Prob. 35PCh. 27 - Prob. 36PCh. 27 - Prob. 37PCh. 27 - Prob. 38PCh. 27 - Prob. 39PCh. 27 - Prob. 40PCh. 27 - Prob. 41PCh. 27 - 42. * EST Estimate the temperature of the Sun's...Ch. 27 - Prob. 44GPCh. 27 - Prob. 46GPCh. 27 - Prob. 47GPCh. 27 - Prob. 48GPCh. 27 - Prob. 49GPCh. 27 - Prob. 50GPCh. 27 - Prob. 51GPCh. 27 - Prob. 52GPCh. 27 - Prob. 53GPCh. 27 - Prob. 54GPCh. 27 - Prob. 55RPPCh. 27 - Prob. 56RPPCh. 27 - Prob. 57RPPCh. 27 - Prob. 58RPPCh. 27 - Prob. 59RPPCh. 27 - Prob. 60RPPCh. 27 - Prob. 61RPPCh. 27 - Prob. 62RPPCh. 27 - Prob. 63RPPCh. 27 - Prob. 64RPP
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- Insulators (nonmetals) have a higher BE than metals, and it is more difficult for photons to eject electrons from insulators. Discuss how this relates to the free charges in metals that make them good conductors.arrow_forwardWhat two pieces of evidence allowed the first calculation of me, the mass of the electron? (a) The ratios qe/me and qp/mp. (b) The values of qe and EB. (c) The ratio qe/me and qe. Justify your response.arrow_forwardUnreasonable Results Red light having a wavelength of 700 nm is projected onto magnesium metal to which electrons are bound by 3.68 eV. (a) Use KEe=hfBE to calculate the kinetic energy of the ejected electrons. (b) What is unreasonable about this result? (c) Which assumptions are unreasonable or inconsistent?arrow_forward
- Construct Your Own Problem Consider a laser pen. Construct a problem in which you calculate the number of photons per second emitted by the pen. Among the things to be considered are the laser pen's wavelength and power output. Your instructor may also wish for you to determine the minimum diffraction spreading in the beam and the number of photons per square centimeter the pen can project at some large distance. In this latter case, you will also need to consider the output size of the laser beam, the distance to the object being illuminated, and any absorption or scattering along the way.arrow_forwardAn X-ray tube accelerates an electron with an applied voltage of 50 kV toward a metal target, (a) What is the shortest-wavelength X-ray radiation generated at the target? (b) Calculate the photon energy in eV. (c) Explain the relationship of the photon energy to the applied voltage.arrow_forwardIn a photoelectric effect experiment, light was shone on a metal surface and the data below were recorded. 13. Maximum kinetic Frequency of incident light (×10“ Hz) energy of ejected electrons (×10 " J) 6 1 7 1.6 8. 2.3 2.9 i) Graph these results, including the line of best fit. frequency (x10“ Hz) ii)Use the graph to determine the work function for this metal surface. Exmax (× 10-19 J)arrow_forward
- The photoelectric effect provided evidence that supported the early suggestion by Max Planck that electromagnetic waves exist as discrete packets of energy. a. Describe the energy transformations that occur during the photoelectric effect. b. If the incident light was not causing the emission of any electrons from the target metal, how could the light be changed to start causing emission of electrons? Explain your answer. c. Rather than changing the light source, explain why changing the target metal from part (c) may allow for the detection of emitted electrons.arrow_forwardFor the photoelectric effect, what is expected by the classical theory? A. The total amount of energy in a light wave increases as the light intensity increases. B. The photoelectrons depend on the value of the light frequency. C. The photoelectrons take so much time to be ejected. D. Existence of a threshold frequency.arrow_forward2. Use Max Planck's quantum theory to explain the following behaviour of photoelectrons. a. Low-intensity light does not release any photoelectrons. What will happen if the light is made brighter? Explain your reasoning. b. Low-intensity light releases photoelectrons. What will happen if the light is made brighter? Explain your reasoning. c. Low-intensity light does not release any photoelectrons. What will happen if the frequency of the light is gradually increased? Explain your reasoning.arrow_forward
- a. What is the energy in joules associated with photons that have a wavelength matching thatof the color blue in the visible spectrum? b. Repeat part (a) for the color red. c. Do the results confirm the fact that the shorter the wavelength the higher the energy level? d. Is light in the ultraviolet range more dangerous in regard to skin cancer than those in theinfrared range? Why? e. Can you guess why fluorescent lights are used for growing plants in a dark environment?arrow_forwardThe photoelectric effect: a. results in the ejection of electrons by light at high intensity. b. is the phenomenon that electrons will only be ejected from the surface of a metal by light that has some minimum brightness, no matter what the frequency. c. was explained by Max Planck. d. describes the phenomenon of producing light by shining a beam of electrons on a metal surface until it glows. e. is the phenomenon that electrons will only be ejected from the surface of a metal by light that has some minimum frequency, no matter how bright or how long you apply the light at a lower frequency.arrow_forward14 A metallic surface is first irradiated with Ultraviolet light and then with Infrared light. What will be the change in the K.E. of the emitted photoelectrons (Note: Ultraviolet has more frequency that infrared). * They will not make any difference Infrared radiations have longer wavelength so K.E will increase Infrared radiations have shorter wavelength so K.E will increase U.V radiations have shorter wavelength so K.E will decreasearrow_forward
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