Chapter 27, Problem 57QAP

To determine

(a)

The missing value of fusion reactions.

Answer to Problem 57QAP

The fusion reaction is $H+H\to He+n$.

Explanation of Solution

Given info:

The given reaction is, $H+H\to He+n$

Calculation:

To calculate the no of neutrons, release from the above equation. The mass should be equal to the left side and right side of the equation for balancing the equation. So, equate the left side and right side of the masses. We get,

  $\begin{array}{l}2+3=4+x\\ x=1\end{array}$

So, 1 neutron will be released from the above equation

Hence, the complete reaction would be

  $H+H\to He+n$

To determine

(b)

The missing value of fusion reactions.

Answer to Problem 57QAP

The fusion reaction is $H+H\to He+n$.

Explanation of Solution

Given info:

The given reaction is, $H+He\to Be+n$

Calculation:

To calculate the no of neutrons, release from the above equation. The mass should be equal to the left side and right side of the equation for balancing the equation. So, equate the left side and right side of the masses. We get,

  $\begin{array}{l}4+4=7+x\\ x=1\end{array}$

So, 1 neutron will be released from the above equation

Hence, the complete reaction would be

  $H+He\to Be+n$

To determine

(c)

The missing value of fusion reactions.

Answer to Problem 57QAP

The fusion reaction is $H+H\to He+n$.

Explanation of Solution

Given info:

The given reaction is, $H+H\to He+n$

Calculation:

To calculate the number of neutrons, release from the above equation. The mass should be equal to the left side and right side of the equation for balancing the equation. So, equate the left side and right side of the masses. We get,

  $\begin{array}{l}2+2=3+x\\ x=1\end{array}$

So, 1 neutron will be released from the above equation

Hence, the complete reaction would be

  $H+H\to He+n$

To determine

(d)

The missing value of fusion reactions.

Answer to Problem 57QAP

The fusion reaction is $H+H\to \gamma +He$.

Explanation of Solution

Given info:

The given reaction is, $H+H\to \gamma +X$

Calculation:

To calculate the no of neutrons, release from the above equation. The mass should be equal to the left side and right side of the equation for balancing the equation. So, equate the left side and right side of the masses. We get,

  $\begin{array}{l}2+1=0+x\\ x=3\end{array}$

And

  $\begin{array}{l}1+1=0+y\\ x=2\end{array}$

So, the atomic number is 2.

Hence, the complete reaction would be $H+H\to \gamma +He$

To determine

(f)

The missing value of fusion reactions.

Answer to Problem 57QAP

The fusion reaction is $H+H\to H+n$.

Explanation of Solution

Given info:

The given reaction is, $H+H\to He+n$

Calculation:

To calculate the no of neutrons, release from the above equation. The mass should be equal to the left side and right side of the equation for balancing the equation. So, equate the left side and right side of the masses. We get,

  $\begin{array}{l}2+3=4+x\\ x=1\end{array}$

So, 1 neutron will be released from the above equation

Hence, the complete reaction would be

  $H+H\to He+n$

  $H+H\to H+n$

To calculate the no of neutrons, release from the above equation. The mass should be equal to the left side and right side of the equation for balancing the equation. So, equate the left side and right side of the masses. We get,

  $\begin{array}{l}2+2=3+x\\ x=1\end{array}$

So, 1 neutron will be released from the above equation

Hence, the complete reaction would be

  $H+H\to H+n$