(A)
The radius of hydrogen-3 of the nuclei of the isotope.
Explanation of Solution
An atomic nucleus is approximately spherical with radius
Thus, the radius of hydrogen-3 of the nuclei of the isotopes is
(B)
The radius of beryllium-8 of the nuclei of the isotope.
Explanation of Solution
An atomic nucleus is approximately spherical with radius
Thus, the radius of beryllium-8 of the nuclei of the isotopes is
(C)
The radius of aluminum-26 of the nuclei of the isotope.
Explanation of Solution
An atomic nucleus is approximately spherical with radius
Thus, the radius of aluminum-26 of the nuclei of the isotopes is
(D)
The radius of gold-197 of the nuclei of the isotope.
Explanation of Solution
An atomic nucleus is approximately spherical with radius
Thus, the radius of gold-197 of the nuclei of the isotopes is
(E)
The radius of technetium-100 of the nuclei of the isotope.
Explanation of Solution
An atomic nucleus is approximately spherical with radius
Thus, the radius of technetium-100 of the nuclei of the isotopes is
(F)
The radius of tungsten-184 of the nuclei of the isotope.
Explanation of Solution
An atomic nucleus is approximately spherical with radius
Thus, the radius of tungsten-184 of the nuclei of the isotopes is
(G)
The radius of osmium-190 of the nuclei of the isotope.
Explanation of Solution
An atomic nucleus is approximately spherical with radius
Thus, the radius of osmium-190 of the nuclei of the isotopes is
(H)
The radius of plutonium-239 of the nuclei of the isotope.
Explanation of Solution
An atomic nucleus is approximately spherical with radius
Thus, the radius of plutonium-239 of the nuclei of the isotopes is
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Chapter 27 Solutions
COLLEGE PHYSICS
- The fact that BEN peaks at roughly A = 60 implies that the range of the strong nuclear force is about the diameter of this nucleus. Calculate the diameter of A = 60 nucleus. Compare BEN for 58Niand 90Sr . The first is one of the most tightly bound nuclides, whereas the second is larger and less tightly bound.arrow_forwardWhen a nucleus (decays, does the (particle move continuously from inside the nucleus to outside? That is, does it travel each point along an imaginary line from inside to out? Explain.arrow_forwardIf two nuclei are to fuse in a nuclear reaction, they must be moving fast enough so that the repulsive Coulomb force between them does not prevent them for getting within R1014mof one another. At this distance or nearer, the attractive nuclear force can overcome the Coulomb force, and the nuclei are able to fuse. (a) Find a simple formula that can be used to estimate the minimum kinetic energy the nuclei must have if they are to fuse. To keep the calculation simple, assume the two nuclei are identical and moving toward one another with the same speed v. (b) Use this minimum kinetic energy to estimate the minimum temperature a gas of the nuclei must have before a significant number of them will undergo fusion. Calculate this minimum temperature first for hydrogen and then for helium. (Hint: For fusion to occur, the minimum kinetic energy when the nuclei are far apart must be equal to the Coulomb potential energy when they are a distance R apart.)arrow_forward
- Integrated Concepts Estimate the density of a nucleus by calculating the density of a proton, taking it to be a sphere 1.2 fm in diameter. Compare your result with the value estimated in this chapter.arrow_forwardHow does the lithium deuteride in the thermonuclear bomb shown in Figure 32.33 supply tritium (3H) as well as deuterium (2H)?arrow_forwardConstruct Your Own Problem Consider a detector needed to observe the proposed, but extremely rare, decay of an electron. Construct a problem in which you calculate the amount of matter needed in the detector to be able to observe the decay, assuming that it has a signature that is clearly identi?able. Among the things to consider are the estimated half life (long for rare events), and the number of decays per unit time that you wish to observe, as well as the number of electrons in the detector substance.arrow_forward
- Another set of reactions that result in the fusing of hydrogen into helium in the Sun and especially in hotter stars is called the carbon cycle. It is 12C+1H13N+, 13N13C+e++ve, 13C+1H14N+, 14N+1H15O+, 15O15N+e++ve, 15N+1H12C+4He. Write down the overall effect at the carbon cycle (as was done for the protonproton cycle in 2e+41H+4He+2ve+6. Note the number of protons (lH) required and assume that the positrons (e+) annihilate electrons to form more (rays.arrow_forwardUnreasonable Results A frazzled theoretical physicist reckons that all conservation laws are obeyed in the decay of a proton into a neutron, positron, and neutrino (as in (+ decay of a nucleus) and sends a paper to a journal to announce the reaction as a possible end of the universe due to the spontaneous decay of protons. (a) What energy is released in this decay? (b) What is unreasonable about this result? (c) What assumption is responsible?arrow_forwardThe mass (M) and the radius (r) of a nucleus can be expressed in terms of the mass number, A. (a) Show that the density of a nucleus is independent of A (b) Calculate the density of a gold (Au) nucleus. Compare your answer to that for iron (Fe).arrow_forward
- 56Feis among the most tightly bound of all nuclides. It is more than 90% of natural iron. Note that 56Fe has even numbers of both protons and neutrons. Calculate BE/A, the binding energy per nucleon, for 56Fe and compare it with the approximate value obtained from the graph in Figure 31.27.arrow_forwardFind the radius of a 238Pu nucleus. 238Pu is a manufactured nuclide that is used as a power source on some space probes.arrow_forwardHow does the finite range of the nuclear force relate to the fact that BE/A is greatest for A new 60?arrow_forward
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