General Physics, 2nd Edition
2nd Edition
ISBN: 9780471522782
Author: Morton M. Sternheim
Publisher: WILEY
expand_more
expand_more
format_list_bulleted
Question
Chapter 27, Problem 43E
(a)
To determine
The energy of rotating molecule.
(b)
To determine
Sketch the energy of four lowest energy levels of rotating molecule.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
One description of the potential energy of a diatomic molecule is given by the Lennard–Jones potential, U = (A)/(r12) - (B)/(r6)where A and B are constants and r is the separation distance between the atoms. For the H2 molecule, take A = 0.124 x 10-120 eV ⋅ m12 and B = 1.488 x 10-60 eV ⋅ m6. Find (a) the separation distance r0 at which the energy of the molecule is a minimum and (b) the energy E required to break up theH2 molecule.
The two nuclei in the carbon monoxide (CO) molecules are 0.1128 nm apart.
The mass of the carbon atom is 1.993x10-26 kg.
The mass of the oxygen atom is 2.656x10-26 kg.
Spectroscopic measurements show that adjacent vibrational energy levels for the CO molecule are 0.269 eV.
What is the effective spring constant of the CO molecule? (Give your answer in N/m.)
An empirical interatomic pair potential for xenon atoms, in units of eV, and nm, and the lattice parameter
of Xenon is equal to 0.630 nm.
V(r) =
12.6 X 10-7 31.8 X 10-4
712
The calculated interatomic separation (nearest-neighbour) distance is:
A. 0.2227 nm.
B. 0.3536 nm
C. 0.4455 nm
D. 1.414 nm
Chapter 27 Solutions
General Physics, 2nd Edition
Ch. 27 - Prob. 1RQCh. 27 - Prob. 2RQCh. 27 - Prob. 3RQCh. 27 - Prob. 4RQCh. 27 - Prob. 5RQCh. 27 - Prob. 6RQCh. 27 - Prob. 7RQCh. 27 - Prob. 8RQCh. 27 - Prob. 9RQCh. 27 - Prob. 10RQ
Ch. 27 - Prob. 1ECh. 27 - Prob. 2ECh. 27 - Prob. 3ECh. 27 - Prob. 4ECh. 27 - Prob. 5ECh. 27 - Prob. 6ECh. 27 - Prob. 7ECh. 27 - Prob. 8ECh. 27 - Prob. 9ECh. 27 - Prob. 10ECh. 27 - Prob. 11ECh. 27 - Prob. 12ECh. 27 - Prob. 13ECh. 27 - Prob. 14ECh. 27 - Prob. 15ECh. 27 - Prob. 16ECh. 27 - Prob. 17ECh. 27 - Prob. 18ECh. 27 - Prob. 19ECh. 27 - Prob. 20ECh. 27 - Prob. 21ECh. 27 - Prob. 22ECh. 27 - Prob. 23ECh. 27 - Prob. 24ECh. 27 - Prob. 25ECh. 27 - Prob. 26ECh. 27 - Prob. 27ECh. 27 - Prob. 28ECh. 27 - Prob. 29ECh. 27 - Prob. 30ECh. 27 - Prob. 31ECh. 27 - Prob. 32ECh. 27 - Prob. 33ECh. 27 - Prob. 34ECh. 27 - Prob. 35ECh. 27 - Prob. 36ECh. 27 - Prob. 37ECh. 27 - Prob. 38ECh. 27 - Prob. 39ECh. 27 - Prob. 41ECh. 27 - Prob. 42ECh. 27 - Prob. 43ECh. 27 - Prob. 44ECh. 27 - Prob. 45ECh. 27 - Prob. 46ECh. 27 - Prob. 47ECh. 27 - Prob. 48E
Knowledge Booster
Similar questions
- A hypothetical NH molecule makes a rotational-level transition from I= 3 to l = 1 and gives off a photon of wavelength 1.740 nm in doing so. What is the separation between the two atoms in this molecule if we model them as point masses? The mass of hydrogen is 1.67 * 1 kg, and the mass of nitrogen is 2.33 * 10-26 kg. 5.59*10^(-13) m O 5.62*10^(-13) m 5.59*10^(-11} m 5.59*10^(-12)m 6.59*10^(-13) marrow_forwardK:54)arrow_forwardThe angular frequency of vibrations in a one-dimensional monatomic crystal are given by where w (k) = 4K m sin k = ka 2 2π λ is the wavenumber of the vibration pattern in terms of its wavelength >, the spring constant between neighbouring atoms, and m the mass of each atom. (i) Show that the frequency does not change if one shifts 2π k→ k +. a (ii) Briefly explain the physical reason for this periodicity.arrow_forward
- A ALAS semiconductor crystal has a lattice constant of a = 0.13 nm, the volume density of As atoms in this crystal will be: O 3.641e24 /cm^3 2.048e30 /cm^3 O 1.821e24 /cm^3 O 3.550e16 /cm^3 O 1.593e24 /cm^3arrow_forwardThe number of silicon atoms per m3 is 5 × 1028. This is doped simultaneously with 5 × 1022 atoms per m3 of Arsenic and 5 × 1020 per m3 atoms of Indium. Calculate the number of electrons and holes.arrow_forwardOne model for the potential energy of a two-atom molecule, where the atoms are separated by a distance r, is U(r) = Uo[(¹) ¹2 – ( )²] where ro = 0.8 nm and U₁ = 6.1 eV. Note: 1 eV = 1.6 × 10-19 J. Some helpful units: [Force] = eV/nm [Energy] = eV [distance] = nm Equilibrium Distance What is the distance between the atoms when the molecule is in stable equilibrium? Click here for a hint T'eq Hint: Hint: Hint: Hint: Hint: Hint: Force If the distance between the atoms increases from equilibrium by r₁ = 0.35 nm, then what is the force from one atom on the other associated with this potential energy? (Enter your answer as postive if they repel each other, and negative if they attract.) Fr(req+r₁) Hint: Hint: 0.89105934nm Kinetic Energy Hint: The atoms are oscillating back and forth. The maximum separation of the atoms is r₂ = 2 nm. What is the kinetic energy of the atoms when they are separated by the equilibrium distance? Click here for a hint K(req) Hint: Hint: = -1.288eV/nm 3.99eVarrow_forward
- Graph below shows the electron occupancy probability P(E) as a function of energy for Bismuth (mBi = 3.47 × 10-25 kg) at the temperature T = 0 K. What is the number of conduction electrons per unit volume for Bismuth? 1 1 2 3 4 5 6 7 8 E (ev) P(E)arrow_forwardSubject is "SOLID STATE PHYSICS"arrow_forwardA hypothetical NH molecule makes a rotational-level transition from l = 3 to l= 1 and gives off a photon of wavelength 1.780 nm in doing so. What is the separation between the two atoms in this molecule if we model them as point masses? (The mass of hydrogen is 1.67 * 10-27 kg, and the mass of nitrogen is 2.33 * 10-26 kg).arrow_forward
- Consider a Face Centered Cubic (FCC) lattice structured Nickel crystal. We are looking to find the surface energy of the new surface that is formed after it is sliced at the (100) plane. a- Find the value of R as function of the lattice constant a. 4R Oa = 2R Oa = 4R Oa = = 2/2R V2 Find the area A11 of (111) surface as function of R. 04R? O16R? O8R? OR? How many atoms lie on the plane (111) within the unit cell? N111 = atoms within the unit cell Find the number of atoms per unit surface area. 2 2 R2 8R2 16R? 4R? Which of the following represents the expression of the surface energt? ON BEPAarrow_forwardWhat is the energy of an electron in the n=2 state for an gold atom, , in units of eV. E = [x] _________________ eVarrow_forwardOne model for the potential energy of a two-atom molecule, where the atoms are separated by a distance r, is U(r) = U₁[(¹)¹² – ()] where ro = 0.8 nm and ₹₁ = 6.1 eV. 19 Note: 1 eV = 1.6 × 10-¹⁹ J. Some helpful units: [Force] = eV/nm [Energy] = eV [distance] = nm Equilibrium Distance What is the distance between the atoms when the molecule is in stable equilibrium? Click here for a hint req Hint: Hint: Hint: Hint: Hint: Force If the distance between the atoms increases from equilibrium by r₁ = 0.35 nm, then what is the force from one atom on the other associated with this potential energy? (Enter your answer as postive if they repel each other, and negative if they attract.) Fr(req+r₁) Hint: 0.89105934nm Hint:arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Physics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Modern PhysicsPhysicsISBN:9781111794378Author:Raymond A. Serway, Clement J. Moses, Curt A. MoyerPublisher:Cengage Learning
University Physics Volume 3PhysicsISBN:9781938168185Author:William Moebs, Jeff SannyPublisher:OpenStax
Physics for Scientists and Engineers with Modern ...
Physics
ISBN:9781337553292
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Modern Physics
Physics
ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher:Cengage Learning
University Physics Volume 3
Physics
ISBN:9781938168185
Author:William Moebs, Jeff Sanny
Publisher:OpenStax