
To find: the maximum amount that should be deposited into each account in order to earn more interest possible in one year; if not possible state whether the problem is infeasible, unbounded or has alternate optimal solutions.

Answer to Problem 17E
First bank: $4000
City bank: $7000
Explanation of Solution
Given information:
Let the amount deposited in first bank x and amount deposited in first bankbe y .
Total amount in both the banks = $11000
Maximum deposit at first bank = $7500
Minimum deposit at city bank = $1000
Maximum deposit at city bank = $7000
Simple interest offered at first bank = 6%
Simple interest offered at city bank = 6.5%
Calculation:
Let P(x,y) be the maximum interest function. The maximum interest is as follows:
P(x,y)=0.06x+0.065y .
The inequalities derived from the given information are as follows:
x≤750001000≤y≤7000x+y≤11000
Use a graphing calculator to plot the inequalities as shown below.
The vertices are (0,1000),(7500,1000),(7500,3500),(4000,7000) and (0,7000) . Now test each vertex as shown below.
P(0,1000)=0.06(0)+0.065(1000)=$65P(7500,1000)=0.06(7500)+0.065(1000)=$515P(7500,3500)=0.06(7500)+0.065(3500)=$677.50P(4000,7000)=0.06(4000)+0.065(7000)=$695P(0,7000)=0.06(0)+0.065(7000)=$455
Thus, the maximum amount that should be deposited into first bank and city bank account in order to earn more interest possible in one year is $ 4000 and $ 7000 respectively.
Chapter 2 Solutions
Advanced Mathematical Concepts: Precalculus with Applications, Student Edition
Additional Math Textbook Solutions
Introductory Statistics
Elementary Statistics (13th Edition)
Thinking Mathematically (6th Edition)
Pre-Algebra Student Edition
University Calculus: Early Transcendentals (4th Edition)
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