Chapter 2.3, Problem 39E

To determine

To find: value for the given case by using the matrices $A,B,C,D,E$ and $F$ . Write impossible if the matrix does not exist.

Answer to Problem 39E

Impossible

Explanation of Solution

Given information:

The given matrices are as follows:

  $\begin{array}{ccc}\begin{array}{l}A=\left[\begin{array}{cc}5& 7\\ -6& 1\end{array}\right]\\ B=\left[\begin{array}{cc}3& 5\\ -1& 8\end{array}\right]\end{array}& \begin{array}{l}C=\left[\begin{array}{ccc}\begin{array}{l}4\\ 5\\ 9\end{array}& \begin{array}{l}-2\\ 0\\ 0\end{array}& \begin{array}{l}3\\ -1\\ 1\end{array}\end{array}\right]\\ D=\left[\begin{array}{ccc}\begin{array}{l}0\\ -2\\ 4\end{array}& \begin{array}{l}1\\ 3\\ 4\end{array}& \begin{array}{l}2\\ 0\\ -2\end{array}\end{array}\right]\end{array}& \begin{array}{l}E=\left[\begin{array}{ccc}\begin{array}{l}8\\ 3\end{array}& \begin{array}{l}-4\\ 1\end{array}& \begin{array}{l}2\\ -5\end{array}\end{array}\right]\\ F=\left[\begin{array}{ccc}\begin{array}{l}-6\\ 1\end{array}& \begin{array}{l}-1\\ 4\end{array}& \begin{array}{l}0\\ 0\end{array}\end{array}\right]\end{array}\end{array}$

The given case is $CF$ .

Calculation:

  $\begin{array}{c}CF=\left[\begin{array}{ccc}\begin{array}{l}4\\ 5\\ 9\end{array}& \begin{array}{l}-2\\ 0\\ 0\end{array}& \begin{array}{l}3\\ -1\\ 1\end{array}\end{array}\right]\left[\begin{array}{ccc}\begin{array}{l}-6\\ 1\end{array}& \begin{array}{l}-1\\ 4\end{array}& \begin{array}{l}0\\ 0\end{array}\end{array}\right]\\ =\text{Impossible}\end{array}$

Since the number of columns in $C$ is not the same as the number of rows in $F$ . So these two matrices cannot be multiplied. Thus, the matrix $CF$ does not exist.