5th Edition

ISBN: 9780321976444

Author: James S. Walker

Publisher: PEARSON

Concept explainers

Optics is the study of light in the field of physics. It refers to the study and properties of light. Optical phenomena can be classified into three categories: ray optics, wave optics, and quantum optics. Geometrical optics, also known as ray optics, is…

Converging Lens

Converging lens, also known as a convex lens, is thinner at the upper and lower edges and thicker at the center. The edges are curved outwards. This lens can converge a beam of parallel rays of light that is coming from outside and focus it on a point on…

Plano-Convex Lens

To understand the topic well we will first break down the name of the topic, ‘Plano Convex lens’ into three separate words and look at them individually.

Lateral Magnification

In very simple terms, the same object can be viewed in enlarged versions of itself, which we call magnification. To rephrase, magnification is the ability to enlarge the image of an object without physically altering its dimensions and structure. This pr…

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Textbook Question

Chapter 26, Problem 54PCE

The observer in Figure 26-65 is positioned so that the far edge of the bottom of the empty glass (not to scale) is just visible When the glass is filled to the top with water, the center of the bottom of the glass is just visible to the observer. Find the height H. of the glass, given that its width is W = 5.7cm.

Chapter 26, Problem 54PCE, The observer in Figure 26-65 is positioned so that the far edge of the bottom of the empty glass

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Chapter 26, Problem 53PCE

Chapter 26, Problem 55PCE

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109 In Fig. 34-54, a fish watcher at point P watches a fish through a glass wall of a fish tank. The watcher is level with the fish; the index of re- fraction of the glass is 8/5, and that Watcher of the water is 4/3. The distances are di = 8.0 cm, dz = 3.0 cm, and dz = 6.8 cm. (a) To the fish, how far away does the watcher appear to be? (Hint: The watcher is the object. Light from that object passes through the wall's outside surface, which acts as a refracting sur- face. Find the image produced by that surface. Then treat that im- age as an object whose light passes through the wall's inside sur- face, which acts as another refracting surface.) (b) To the watcher, how far away does the fish appear to be? de D Wall Figure 34-54 Problem 109.

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(a) A small light fixture on the bottom of a swimming pool is 0.72 m below the surface. The light emerging from the still water forms a circle on the water surface. What is the diameter of this circle? (Give your answer, in m, to at least two decimal places.) (b) What If? If a 2.13 cm thick layer of oil (n = 1.35) is spread uniformly over the surface of the water, what is the diameter of the circle of light emerging from the swimming pool? (Give your answer, in m, to at least two decimal places.)

Chapter 26 Solutions

Physics (5th Edition)

Ch. 26.1 - A ray of light reflects from a horizontal flat...Ch. 26.2 - A meterstick is placed 40 cm in front of a plane...Ch. 26.3 - Rank the following spherical mirrors in order of...Ch. 26.4 - A spherical mirror with an object at the distance...Ch. 26.5 - (a) As a beam of light passes from flint glass to...Ch. 26.6 - The lenses shown in Figure 26-49 have objects that...Ch. 26.7 - An object at the distance do = 15 cm from a lens...Ch. 26.8 - Referring to Figure 26-53, do you expect the index...Ch. 26 - Two plane mirrors meet at right angles at the...Ch. 26 - Two plane mirrors meet at right angles at the...

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