Physics for Scientists and Engineers with Modern Physics
10th Edition
ISBN: 9781337553292
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
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Chapter 26, Problem 15P
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A current density of 8.50 x 10-13 A/m2 exists in the atmosphere at a location
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(a) Number i
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Chapter 26 Solutions
Physics for Scientists and Engineers with Modern Physics
Ch. 26.1 - Consider positive and negative charges of equal...Ch. 26.2 - Prob. 26.2QQCh. 26.2 - Prob. 26.3QQCh. 26.4 - When does an incandescent lightbulb carry more...Ch. 26 - Prob. 1PCh. 26 - A small sphere that carries a charge q is whirled...Ch. 26 - Prob. 3PCh. 26 - Prob. 4PCh. 26 - Prob. 5PCh. 26 - Figure P26.6 represents a section of a conductor...
Ch. 26 - The quantity of charge q (in coulombs) that has...Ch. 26 - Prob. 8PCh. 26 - Prob. 9PCh. 26 - A wire 50.0 m long and 2.00 mm in diameter is...Ch. 26 - Prob. 11PCh. 26 - Prob. 12PCh. 26 - Prob. 13PCh. 26 - Prob. 14PCh. 26 - Prob. 15PCh. 26 - Prob. 16PCh. 26 - Prob. 17PCh. 26 - Prob. 18PCh. 26 - An aluminum wire with a diameter of 0.100 mm has a...Ch. 26 - Prob. 20PCh. 26 - At what temperature will aluminum have a...Ch. 26 - You are working in a laboratory that studies the...Ch. 26 - Assume that global lightning on the Earth...Ch. 26 - The Van de Graaff generator, diagrammed in Figure...Ch. 26 - Prob. 25PCh. 26 - The potential difference across a resting neuron...Ch. 26 - Prob. 27PCh. 26 - Prob. 28PCh. 26 - Prob. 29PCh. 26 - Prob. 30PCh. 26 - Prob. 31PCh. 26 - Prob. 32PCh. 26 - Prob. 33PCh. 26 - Prob. 34APCh. 26 - Prob. 35APCh. 26 - You are working with an oceanographer who is...Ch. 26 - A charge Q is placed on a capacitor of capacitance...Ch. 26 - Prob. 38APCh. 26 - Prob. 39APCh. 26 - Prob. 40APCh. 26 - Review. An office worker uses an immersion heater...Ch. 26 - Prob. 42APCh. 26 - A close analogy exists between the flow of energy...Ch. 26 - The dielectric material between the plates of a...Ch. 26 - Review. A parallel-plate capacitor consists of...Ch. 26 - Prob. 46APCh. 26 - Prob. 47APCh. 26 - Prob. 48CPCh. 26 - Prob. 49CPCh. 26 - Material with uniform resistivity is formed into...
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- An aluminum wire 1.628 mm in diameter (14-gauge) carries a current of 3.00 amps, (a) What is the absolute value of the charge density in the wire? (b) What is the drift velocity of the electrons? (c) What would be the drift velocity if the same gauge copper were used instead of aluminum? The density of copper is 8.96 g/cm3 and thedensity of aluminum is 2.70 g/cm3. The molar mass ofaluminum is 26.98 g/mol and the molar mass of copper is 63.5 g/mol. Assume each atom of metal contributes one free electron.arrow_forwardTaking R = 1.00 k and = 250 V in Figure P21.49, determine the direction and magnitude of the current in the horizontal wire between a and e. Figure P21.49arrow_forwardEarth’s lower atmosphere contains negative and positive ions that are produced by radioactive elements in the soil and cosmic rays from space. In a certain region, the atmospheric electric field strength is 120 V/m and the field is directed vertically down.This field causes singly charged positive ions, at a density of 620 cm3, to drift downward and singly charged negative ions, at a density of 550 cm3, to drift upward. The measured conductivity of the air in that region is 2.70 * 10-14 (ohmm)-1. Calculate (a) the magnitude of the current density and (b) the ion drift speed, assumed to be the same for positive and negative ions.arrow_forward
- A current density of 8.50 × 10-¹5 A/m² exists in the atmosphere at a location where the electric field is 138 V/m. Calculate the electrical conductivity of the Earth's atmosphere in this region. (2. m)-¹arrow_forwardSilver wire has a cross-sectional area A = 2.0 mm2. A total of 9.4 x 10 electrons pass through the wire in 3.0 s. The conduction electron density in silver is 5.8 x 1028 electrons/m. What is the drift velocity of these electrons?arrow_forwardThe earth’s surface has a negative surface charge density of 10-9 C m-2. The potential difference of 400 kV between the top of the atmosphere and the surface results (due to the low conductivity of the lower atmosphere) in a current of only 1800 A over the entire globe. If there were no mechanism of sustaining atmospheric electric field, how much time (roughly) would be required to neutralise the earth’s surface? (This never happens in practice because there is a mechanism to replenish electric charges, namely the continual thunderstorms and lightning in different parts of the globe). (Radius of earth = 6.37 × 106 m.)arrow_forward
- Suppose that there is a wire. It is made out of material that has a the following information: temperature coefficient = 0.005/°C cross sectional area = 4.51x10-6 m² length: 1.00 m free electron density = 8.49 x 1028 electrons/m³ The wire is at temperature 20°C and it carries a current of 5 A when connected to a 35 V battery. Find the (1) drift speed of the electrons and (2) resistivity at 50°C.arrow_forwardAn iron wire has a cross-sectional area of 5.00 × 10−6 m2 . Carry out steps (a) through (e) to compute the drift speed of the conduction electrons in the wire. (a) How many kilograms are there in 1 mole of iron? (b) Starting with the density of iron and the result of part (a), compute the molar density of iron (the number of moles of iron per cubic meter). (c) Calculate the number density of iron atoms using Avogadro’s number. (d) Obtain the number density of conduction electrons given that there are two conduction electrons per iron atom. (e) If the wire carries a current of 30.0 A, calculate the drift speed of conduction electrons.arrow_forwardA conductor has a cross-sectional area of 2.3x106 m² and the number of free electrons per unit volume is 8.5 X1028 electron/m³. When the current is 7.1 A, find the drift speed (in mm/s) of the electrons. Use the charge of the electron to be 1.6×1019 c.arrow_forward
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